Conjugation and color | Spectroscopy | Organic chemistry | Khan Academy

Why extensively conjugated compounds absorb light in the visible region and thus have color. Created by Jay.
Watch the next lesson: www.khanacademy.org/science/o...
Missed the previous lesson? www.khanacademy.org/science/o...
Organic Chemistry on Khan Academy: Carbon can form covalent bonds with itself and other elements to create a mind-boggling array of structures. In organic chemistry, we will learn about the reactions chemists use to synthesize crazy carbon based structures, as well as the analytical methods to characterize them. We will also think about how those reactions are occurring on a molecular level with reaction mechanisms. Simply put, organic chemistry is like building with molecular Legos. Let's make some beautiful organic molecules!
About Khan Academy: Khan Academy offers practice exercises, instructional videos, and a personalized learning dashboard that empower learners to study at their own pace in and outside of the classroom. We tackle math, science, computer programming, history, art history, economics, and more. Our math missions guide learners from kindergarten to calculus using state-of-the-art, adaptive technology that identifies strengths and learning gaps. We've also partnered with institutions like NASA, The Museum of Modern Art, The California Academy of Sciences, and MIT to offer specialized content.
For free. For everyone. Forever. #YouCanLearnAnything
Subscribe to Khan Academy’s Organic Chemistry channel: / channel
Subscribe to Khan Academy: kzread.info_...

Пікірлер: 37

  • @Jo24Park
    @Jo24Park7 жыл бұрын

    I've now known the effect of phenolphthalein for 10 years and never heard of that mechanism before. THIS IS SO COOL! :D

  • @zubeyirozay2164
    @zubeyirozay21645 жыл бұрын

    This was the best explanation i have ever seen i my life!

  • @najgauner
    @najgauner6 жыл бұрын

    wow this was a great video... Even i as a high schooler with only basic knowlegde get it now

  • @juliamo9755
    @juliamo97556 жыл бұрын

    Omg thank you so much DX I finally understood this topic

  • @seanpeters8551
    @seanpeters85513 жыл бұрын

    this helped so much, thank you!

  • @evelynakow6771
    @evelynakow67713 жыл бұрын

    wonderful explanation thank you!

  • @fakhrulnawawi9681
    @fakhrulnawawi96817 жыл бұрын

    VERY VERY NICE VIDEO..THANKS A LOT

  • @agathaknive3321
    @agathaknive33213 жыл бұрын

    THIS IS EXPLAINED SO WELL OH MY GOD WHY CAN'T YOU BE MY CHEM TEACHER

  • @andyposbe11
    @andyposbe117 жыл бұрын

    really liked these transitions. no homo

  • @pawelino134
    @pawelino1343 жыл бұрын

    Great explanation, great teacher!

  • @sheetalmore2052
    @sheetalmore20526 жыл бұрын

    I love you.. You always help me a lot.. 😭😭

  • @amilasandaruwan7583
    @amilasandaruwan75838 жыл бұрын

    thanks for the help! (y)

  • @brayanelian6905
    @brayanelian69053 жыл бұрын

    Thanks for the explanation

  • 3 жыл бұрын

    good video, but i dont get which of the videos about this topic is the first one i should watch!!!!

  • @jojolili8764
    @jojolili87645 жыл бұрын

    Why is the reduced form of DCPIP colorless but the DCPIP blue?

  • @anitalayal9171
    @anitalayal91712 жыл бұрын

    Wowwww✌️

  • @mnswz3140
    @mnswz31402 жыл бұрын

    thanks so much

  • @briannahoff8589
    @briannahoff85893 жыл бұрын

    Why does the energy difference between the HOMO and LUMO decrease though? (other than that you've drawn them closer together)

  • @anitalayal9171

    @anitalayal9171

    2 жыл бұрын

    I want answer of this one ,,,I have same doubt ✌️

  • @ahmednesartahsinchoudhury2628
    @ahmednesartahsinchoudhury26282 жыл бұрын

    The volume is very low

  • @cara.bella15
    @cara.bella15 Жыл бұрын

    Wait why are we focusing on only the pi bonds? Why not sigma bonds?

  • @pawanjandu4285
    @pawanjandu42852 жыл бұрын

    Sir app kis app se videos bnte ho

  • @agent475816
    @agent4758168 жыл бұрын

    What if you re-acidify the phenolphalein. How would it go back to its original structure? Wouldn't you get an alcohol on the O- and end up with a carboxylic acid on the COO-? Then it would still be pink.

  • @Jo24Park

    @Jo24Park

    7 жыл бұрын

    basically possible and it will also happen. But only in equilibrium with the formation of H2O. Remember that this is an effect in the absence of H ions. So either H2O or OH/COOH but not both simultaneously. And I'd guess that because OH- ions are just smaller they get H+ more easily than the sterically hindered phenolphthalein.

  • @31rifahnoorchowdhury19
    @31rifahnoorchowdhury192 жыл бұрын

    why is the energy difference smaller ?

  • @georgeclooney9164
    @georgeclooney91646 жыл бұрын

    Ok, So i understand the concept of absorbing a specific wavelength of light, but hwo do we get it reflecting a different wavelength? Is there another formula that dictates what wavelength is emitted from a molecule based on what that molecule absorbs? Thanks!

  • @Nicolas-eo7lo

    @Nicolas-eo7lo

    5 жыл бұрын

    This might be a bit late, but as far as i understood it: If a material is lets say red, then every wavelength is absorbed by this material, EXCEPT red/reddish wavelengths which are reflected into your eye. Can anyone verify this?

  • @ghostsniiper1

    @ghostsniiper1

    5 жыл бұрын

    @@Nicolas-eo7lo Not quite, lets see a molecule absorbs red wavelength of light. The light reflected will be the complementary colour according to the colour wheel, in the case of red light being absorbed the complementary colour is green and so the compound wil be green coloured. Hope this helps

  • @MEBSAMPATHKUMARKODI
    @MEBSAMPATHKUMARKODI3 жыл бұрын

    When a compound is subjected to electromagnetic radiation why cant it absorbs all radiations like microwave , ir, and uv and emits light in visible region?

  • @drgeetali
    @drgeetali4 жыл бұрын

    Sound is very feeble in this video.

  • @zestrus11
    @zestrus118 жыл бұрын

    When you say, "sp3 has no p-orbital, and sp2 has a p-orbital" Do you mean sp3 has no pi bonds and sp2 has one pi bond? I thought sp3 has 3 p-orbitals and sp2 has 2 p-orbitals. Did you mean to say pi bond instead of p-orbital?

  • @LUICT15

    @LUICT15

    8 жыл бұрын

    +danielle lebouthillier i think what he meant was that sp3 does not have any unhybridized p atomic orbitals to form pi bonds while sp2 has 1 unhybridized p orbital and can form a pi bond

  • @manzoorahmeds7567

    @manzoorahmeds7567

    8 жыл бұрын

    hi

  • @nicolasvelez1099
    @nicolasvelez10994 жыл бұрын

    can anyone tell me how spectroscopy is used in real life? I don't get this subject :(

  • @km-sc4kz

    @km-sc4kz

    4 жыл бұрын

    Spectroscopy is used to identify molecules by looking at their absorption spectra.

  • @h7opolo
    @h7opolo Жыл бұрын

    0:03 wrong. wtf r you talking about?