Cardinality of the Power Set Part 2

The cardinality of the power set is never the same as the cardinality of the original set. This can be proven with Cantor’s diagonal argument familiar from the proof of the uncountability of the real numbers.

Пікірлер: 17

  • @Nick-kg7sk
    @Nick-kg7sk5 жыл бұрын

    This proof is very similar to Cantor’s diagonal argument. Very clear presentation. You should do a video on friendly numbers in number theory.

  • @gutzimmumdo4910
    @gutzimmumdo49102 жыл бұрын

    beautifull, your explanation was superb as always.

  • @AKARIMIZUNASHIVENEZIA
    @AKARIMIZUNASHIVENEZIA2 жыл бұрын

    Thank you very much, these videos are truly well made!

  • @sencreations1856
    @sencreations18562 жыл бұрын

    Amazing videos mate, keep it up, very bingable!

  • @nirgle
    @nirgle5 жыл бұрын

    Your math videos are a joy to watch

  • @majdhijjawi3791
    @majdhijjawi37915 жыл бұрын

    Thank you so much ..... I am in love with your videos your explanation and drawings make everything easy ..... No enough words to thank you..... Plz could you make videos on cancer stem cells .... idiopathic pulmonary fibrosis...flow cytometry.... Thanks again and good luck

  • @rtg_onefourtwoeightfiveseven
    @rtg_onefourtwoeightfiveseven4 жыл бұрын

    These videos are excellent! Will you ever make more videos on set theory?

  • @BF-wq1dm
    @BF-wq1dm5 жыл бұрын

    Would you please upload video on Solid phase Oligodeoxynucleotied synthesis.(Triester pathway and Phosphoramidite pathway)

  • @andresgarciaescalante8316
    @andresgarciaescalante83163 жыл бұрын

    Omg you saved my life !!! I love you

  • @elliotnicholson5117

    @elliotnicholson5117

    3 жыл бұрын

    You’re welcome.

  • @johnnorman7676
    @johnnorman76765 жыл бұрын

    I really hope you do a series on quantum mechanics someday.

  • @philippehaas2577
    @philippehaas25775 жыл бұрын

    Thanks a lot for all your great videos! The argument is truly beautiful but its similarity with Cantor's diagonal argument makes me wonder: is the proof valid for all infinite sets or only for countable infinite sets?

  • @elliotnicholson5117

    @elliotnicholson5117

    5 жыл бұрын

    In principle there still exists a set outside of the range of any attempt at a bijective map even if the set is uncountably infinite.

  • @algorithmo134
    @algorithmo134 Жыл бұрын

    Why does my textbook says that it is enough to show that there is an injection and not a surjection to show that the cardinality of any set A is less than the cardinality of power set A

  • @MuffinsAPlenty

    @MuffinsAPlenty

    Жыл бұрын

    That actually is enough. There is a subtle difference here. What Elliot is saying is that if you are dealing with finite sets S and T and you find a single function f : S → T which is an injection but not a surjection, that is enough to conclude that |S| However, with infinite sets X and Y, it is possible to have a function f : X → Y which is an injection but not a surjection while simultaneously having another function g : X → Y which is a bijection. What your book is saying is that, in order to show |A| And this is the difference between "there is an injection _which is_ not a surjection" (enough for finite sets) and "there is an injection _and_ not a surjection" (needed for infinite sets).

  • @umairshahzad2293
    @umairshahzad22934 жыл бұрын

    Which software you use to teach.??

  • @elliotnicholson5117

    @elliotnicholson5117

    3 жыл бұрын

    Explain everything.