Can You Solve This Equation ?
In this session we learn about an interesting equation solving concept.
📢 Join us on telegram : t.me/bhannatmathsofficial
Stay tuned with @BHANNATMATHS
#bhannatmaths #equationsolving #jee2024 #jee
In this session we learn about an interesting equation solving concept.
📢 Join us on telegram : t.me/bhannatmathsofficial
Stay tuned with @BHANNATMATHS
#bhannatmaths #equationsolving #jee2024 #jee
Пікірлер: 192
this concept is actually very important. thank you sir ji this
Best sir keep sharing like this question ❤❤❤❤❤
this video was randomly recommended to me and I couldn't resist leave without liking. but bhai majaa aa gaya. keep up the great work !!!
Sawal ka solution dek ke bahut maza aaya..❤ Thank You Aman Sir.
The Lamber W function is used for these type of exponential equations
@Bhuvan_MS
6 ай бұрын
But we won't get any solution in radicals using Lambert W function. So this method is not suitable in this case.
@podcastforcreators
6 ай бұрын
Yes
@sakshamsrivastava2178
6 ай бұрын
What's this? I'm Class 11 JEE Aspirant
@podcastforcreators
6 ай бұрын
@@sakshamsrivastava2178 its denoted by W and W(xe^x) is x
@alien3200
5 ай бұрын
Fish 🐠 🐟 🐟 🐠 If ykyk
First attempt correct answer. Thanks for such questions sir .
WoW , great observation
Wow nice concept thanks
sir maza aagaya sir ekdam bhannat
Thank you sir
Thank you sir🎉🎉
Typical problem on Sybermath
@Bhuvan_MS
6 ай бұрын
True lol.
@shiveshpratapsingh3501
6 ай бұрын
Also a typical problem on mind your decisions
@user-sf3qd2ss6l
6 ай бұрын
@@shiveshpratapsingh3501similar q is also in premath
@Karan_k1888
5 ай бұрын
Also similar to prmo pyq
The Best !!!
Additional information I’d add is that a in this case must not equal to 0 because 0^0 itself is undefined so 0^0^0 is undefined
@stormatime9426
5 ай бұрын
0^0 is 1 I think 💬
@Brid727
5 ай бұрын
@stormatime9426 in limits even 0^0 is an indeterminant form so yeah wouldn't say 0^0 = 1
@BasicToGenius
5 ай бұрын
Becaur 0¹-¹ =0/0 which is indeterminant
@Brid727
5 ай бұрын
@@BasicToGenius you cannot expand 0. I can say 0^(2-1) is indeterminant because (0^2)/0^1 = 0/0
@BasicToGenius
5 ай бұрын
Both are same bcz 0¹=0²
This is interesting question ❤❤
Sir you made the same video a year ago on tower exponential problem
Thanks a lot sir ❤
awesome
Sir aap jitne is tarah ke numerical kraye ho unka playlist bna do ....
Jordar sir
Please make video lectures on linear programming in mathematics
Thanks for reading😊
Didn't even ask to subscribe or like ❤❤❤
WOW 🤩🤩
We can also do by putting both side log
This is was simply, amazing. 👏✨🤯
Respect for sir
Sir this was easy for me because I am preparing for ioqm
I solved this type of question recently love ❤ u sir
This can also be done by raising both sides to power 8 and then forming (x power 8) power (x power 8) = 8 power 8, and then setting: x power 8 = 8
@nameka6127
6 ай бұрын
Nah as when you power both side by 8..the powered 8 on left side will be multiplied with x⁸...
@saptadeepnath5664
6 ай бұрын
@@nameka6127 (x power 8x power 8) = (x power 8) power (x power 8)
@uncannyroaches5933
5 ай бұрын
no he is correct and this is a more effective solution. do your math again@@nameka6127
Best
Sir mene ye saval hit and try se solve kiya
Sir plz tell aap online me kaha padhte hai
Sir jee advance 2024 ke liye advance problem solving Lana har ch ki April se
Sir, if we take the log of bith LHS and RHS, we get x raised to the power 8 = log(8) = 0.9 (approx) And if we take the eighth root of 0.9, we get a different value of x than x = 8. I don't seem to get why there is such an irregularity. Please explain this if possible🙏🏻
it can also be done when we write 8 as x^x^8 from this x^8=8 and x=8^1/8
@prabuddhabose4033
6 ай бұрын
Maine bhi yahi Kiya hai
but taking power 8 on both sides just gives one answer which is y=8, other complex solutions are formed in it. that's why it is hard to deal with unknown powers.
Wow ❤❤
This was also a Mind Your Decisions video
Taking log on both side X^a (logX)=log a Multiply by a on both side X^a (logX^a)=a log a Compare, we get X^a=a So X=a^(1/a)
Maja ageya
Super sir
Maja aa gaya ❤❤❤❤❤❤
Sir please upload a video on this problem 11 members of a club form four committees of 3,4,2,2 members so that no person is a member of more than one committee.Find the number of committees.
Sir both side log lake aur 8 ko 2 ka cube karke solve hoga kya
I have an other concept... X^X^8=2^3 this implies that either x is 2 or x is 3^1/8...
@jagdishmohapatra4744
5 ай бұрын
Yes my answer is same I have used log concept Let x^8=y X^y=2³ Take log with base 2 y.log2(x) = 3.log2(2) By comparing both sides we got - 1. y=3 x=3^⅛ 2.log2(x)=log2(2) Log2(x)=1 X=2
@CyberFreak108
5 ай бұрын
@@jagdishmohapatra4744 i am in 10th rn so i dont know much bout the log concept or so
❤👍🏻
Damn it was good
Jai Hind sir NDA ke liye maths padhai na please sir NDA 1 2024 ke liye
From last part is a is 2 or 4, wont x be √2?
X = 2^(3/8) easy question tha 20 sec me solve hogaya without pen and paper
LIKE 4 THIS MATHEMAGICIAN 😊
Big fan
Good vid ^^
Sir this is not valid for a= 4 please explain
Easiest problem I have ever seen
Sir please recheck the problem
Log laka ho sakta ha kya
sir x negative nhi aa sakta?
Cube root of 8..dekhke hi samajh geya
x≈1.73205
Sir but it doesn't work when a=4 😢😥
I dont know if this works but first i took natural log on both sides of the eqn,and i differentiated the eqn with respect to x, product rule on the LHS, and we will get two factors in LHS whose product is equals to 0
@jhumaghosh9845
6 ай бұрын
Same for me😂
@Harsh-dd7nm
5 ай бұрын
That will simply give you x=(some critical points), those values of x can't be said the solutions of this function.
@sigmamaleslogokijalegi6683
5 ай бұрын
@@Harsh-dd7nm But actually if u see I didn't solve for dy/dx=0,so no critical points, so what kind of values we are obtaining tho?
X = Antilog( -1/8) acc to me I take log both sides then differentiate both sides. Is it correct?
@Nitin19L14sn
5 ай бұрын
SAME MAINE BHI YEHO SOCHA BUT ANSWER NHI BANA
😃
Mera ek question tha sir
Sir I am you big fan but from sometime i don't watch your videos because I was preparing for my class 10 Board exam
Simple, x^x^8 = 8 x^8x = 8 log x (8) = 8x
@Offline-X
28 күн бұрын
Wrong. x^x^8 ≠ x^x8 This is Common misunderstanding
Take log on both sides.... It will even more easier
@AdityaSharma-lt4rh
5 ай бұрын
Mene bhi ye socha tha but solution nahi nikla
got it within 20 seconds with hit n trial
Sir, 27th se pehle kuch jee pyq ki tricks bta do..
@shaatirop8901
6 ай бұрын
Mathematical inclined pe daali thi kuch 1 din pehle if you want dekh lo
X= 8^1/8
Sir is 9!^9!^9! the biggest number that i can write with three digits? As in question doesn't mention to use symbols or not......
@Aurora-ux9vb
6 ай бұрын
tetration of 9 tetration of 9 tetration of 9,
Sir can we do by taking log base x both sides.
@chandraprakash227
6 ай бұрын
I tried but nothing happened
@prabuddhabose4033
6 ай бұрын
Aur bhi complex hoh Jata
8^1/8 easy
Me in 9th class : hmm yes yes i totally understand it
@zeusssOP69
5 ай бұрын
us man😂
I solved It By Observations
@prabuddhabose4033
6 ай бұрын
Talented
@shiveshpratapsingh3501
26 күн бұрын
Oral prediction=hit and trial Solution given by sir = the actual answer you aren't that much talented if you aren't able to solve without hit and trial
Can this question be solved using log?
Taking log on both side
@YASHJEE-
6 ай бұрын
Phir dono ki power same hujaengi
@YASHJEE-
6 ай бұрын
Phir compare krlo
I have solved it it's ans is 2 raise to 3 divide by 8 without seeing video
Sir both side log lekar kar sakte kya ?
@PRATIKGHOSH17
4 ай бұрын
Usse chiz mushkil ho sakti hai
x^x^8 = 8 x^8 lnx = ln8 e^lnx^8 lnx = ln8 e^8lnx lnx = ln8 8lnx e^8lnx = 8ln8 W[8lnx e^8lnx] = W[8ln8] 8lnx = W[ln64] lnx = W[ln64] / 8 x = exp{W[ln64] / 8} Noice question 😂
@AradhyBharadwaj
6 ай бұрын
lambert function
@Bhuvan_MS
6 ай бұрын
Using Lambert W function, you can get infinitely many solutions(including complex solutions) by using branches other than 0 and 1. If only real solution is required, we can use Sir's technique.
Mene to ise 30 seconds main utar diya😅
Sir ye log se hoga
Take log take log diff
x^(x^8)=8 From this equation we get the following equation x^(x^........ ♾️ x^8)=8 Taking log to the base x on both sides assuming it to be valid we get x^(x^........... ♾️ x^8)logx(x)=logx(8) Therefore finally we can write it as 8=logx(8) x⁸=8 Therefore x=8^(1/8) Ans
@JAANY_GAMER
27 күн бұрын
X ki value logn with base n where n € R
Jai Shree Ram 🙏🚩🕉️
X = 0.325
Your Glasses Though 😭😭
this answer does not satisfy as by solution---- x = 8^1/8 = 8^0.125 = 1.2968 question given---- x^8x = 8 1.2968^(1.2968*8) = 14.9 approx. , not equal to 8 kindly explain please
Log leke bhi kar sakte hai
Take logarithmic on both side Simple 12th mathematics ques
@sansolerajib
19 күн бұрын
log leke dekhliya nhi hora
Ezy
Log leke kare toh?🤔😅
X= 1 that's right ✅ ya wrong ❌ please tell me
maine toh double time log lagaya tha
Bhannat Maths 🤝 blackpenredpen
Duh x is 2 to the power of 3/8 , just by checking 2 to the power n/8 forms
@shiveshpratapsingh3501
26 күн бұрын
Oral prediction=hit and trial Solution given by sir = the actual answer
I have done like this 😅 X^X^8 = 8 X^X^8 × 1^X^8 = 8 8 × 1^X^8 = 8 [X^X^8 = 8] 1^X^8 = 8/8 1^X^8 = 1 So any number to the power 0 is 1 That's why 1^0^8 = 1 [ X=0 ] 1^0 = 1 1 = 1 So X=0
@shiveshpratapsingh3501
26 күн бұрын
But in case of 1 any power raise to one is 1 therefore all real values of x satisfy not just x=0
x = e^[W(3ln2/8)]