Plenty of commenters are jumping to the answer but I’m enjoying the Professor’s approaches to the problem!😀

@PreMath

2 ай бұрын

Excellent! Glad to hear that! Thanks ❤️

In the interests of mathematical rigour, an area can only be equal to a perimeter if one ignores the units. Usually, you are very precise in showing the units in which the answers are expressed. This time, you didn't mention units at all. Maybe you should clarify.

Substitution is the beauty of MATHEMATICS ❤ ❤ 😊

@PreMath

2 ай бұрын

Very true! Thanks for sharing ❤️

Nice

These questions are really good! Thanks a lot!

@PreMath

2 ай бұрын

Glad to hear that! You are very welcome! Thanks ❤️

Let 2/3 = b 1) Hypotenuse = 29*X^b 2) Major Cathetus = 21*X^b 3) Minor Cathetus = 20*X^b 4) Perimeter = 70*X^b 5) Area = (21*20*X^b*X^b) / 2 : Area = (420*X^2b) / 2 ; Area = 210*X^2b 6) Perimeter = Area 7) 70*X^b = 210*X^2b 8) 3*X^2b = X^b 9) 3*X^b = 1 10) X^b = 1/3 11) X^(2/3) = 1/3 12) (X^(2/3))^3 = (1/3)^3 13) X^2 = 1/27 14) X = 1/(3*sqrt(3)) 15) X = sqrt3) / 9 16) X ~ 0,19245 17) Answer : X = Sqrt(3) / 9 or X ~ 0,19245; Linear Units

@PreMath

2 ай бұрын

Excellent! Thanks for sharing ❤️

Root 27 divided by 27 is Root 3 divided by 9! Good practice for manipulating exponents with exponent rules.

😉

@PreMath

2 ай бұрын

😀 Thanks ❤️

Buenas noches Sres. PreMath, Gracias este lindo ejercicio, es bien novedoso y alto contenido pedagógico. sería bueno unos tres más. Éxitos.

@PreMath

2 ай бұрын

Gracias querida🌹 ¡Amor y oraciones desde Estados Unidos! 😀

📐 Nice! Appreciated the review of exponents.

@PreMath

2 ай бұрын

Excellent! Thanks for the feedback❤️

As suggested by @robertlynch7520, here we have a problem with a (20, 21, 29) Pythagorean triangle. Since Area = Perimeter, let's write our equation: ½ 20 x^(⅔) 21 x^(⅔) = 20 x^(⅔) + 21 x^(⅔) + 29 x^(⅔). Solutions are x = 0 (rejected) or x = 1/3√3 (accepted) which, rationalized, gives our answer: x = √(3)/9. Thank you PreMath! 🙏

@PreMath

2 ай бұрын

Excellent! You are very welcome! Thanks for sharing ❤️

x=√(1/27)=√3/9≈0,1925

@PreMath

2 ай бұрын

Excellent! Thanks for sharing ❤️

X=√3/9 units.❤❤❤ Thanks sir.

@PreMath

2 ай бұрын

Very good🌹 Thanks for sharing ❤️

Easy

Area=1/2 21×20×x^(4/3)=perimeter=70x^(2/3), x^(2/3)=70/210=1/3, x=(1/3)^(3/2)=3^(-3/2).😊

@PreMath

2 ай бұрын

Thanks for sharing ❤️

A bit of simplification first: √441 = 21 √841 = 29 u = x²ᐟ³ a² + b² = c² a² + (21u)² = (29u)² a² = 841u² - 441u² a² = 400u² a = √(400u²) = 20u A = bh/2 = 21u(20u)/2 A = 21(10)u² A = 210u² P = 20u + 21u + 29u P = 70u A = P 210u² = 70u 210u² - 70u = 0 3u² - u = 0 u(3u-1) = 0 u = 0 | 3u - 1 = 0 x²ᐟ³ = 0 | 3x²ᐟ³ = 1

@PreMath

2 ай бұрын

Excellent! Thanks for sharing ❤️

No difficulty. The result can be simplified in sqrt(3)/9.

@PreMath

2 ай бұрын

Thanks for sharing ❤️

Sres. PreMath, reciban un cordial saludo desde Quito - Ecuador, Soy un adulto mayor aficionado a las Sagradas Matemáticas. Gracias por la atención prestada, Espero su valioso comentario al video anterior y me sentiré bendecido. Éxitos.

Solved it orally :)

@PreMath

2 ай бұрын

Excellent! Thanks for sharing ❤️

It is very easy question..☺️☺️

@PreMath

2 ай бұрын

Well done🌹

@thepi553

2 ай бұрын

@@PreMath hii sir , how are you.( I am from India) 😁😁

@PreMath

2 ай бұрын

@@thepi553 Hello dear🌹 Take care

X3/2 × 3 = X9/2

x^2 = 1/27 → x = √3/9

??? m^2 (not =) m ???

This was not worthy of you, sorry.

@LuisdeBritoCamacho

2 ай бұрын

😂😂😂 C'mon!!

X=1