From all the videos I've watched online that concerns with finding an unknown substance based on the new freezing point of a solution after a mix, this one has helped me the most at finally understanding the idea behind how all the calculations relate. Thank you!

no joke, i've been trying to finish this lab for 2 hours and couldn't solve this question. I have to leave for class in 20 minutes but im still taking the time to type out that this video was awesome. It wasn't the same question, in fact it was almost the reverse of it. But this still helped more than any other youtube channel or chem help website. Thanks for the help!

THANK YOU SO MUCH. This is literally the most helpful thing ever. You are fantastic. Thank you for existing.

This was everything I needed. Thanks for the helpful video!

You really know your stuff! Thank you for the video, it helped a lot.

Thank you so much! I have been struggling for hours on a problem like this! You're awesome :)

Thank you for making this, helped out a lot!

Saving lives out here, Thanks

So helpful, thanks so much! :') makes so much more sense now

Thank you for uploading this.

Thank you, you just helped me with my lab report!

really apreciate this!!!

Thank you! You're brilliant!

ur such a life saver and helped me undertand my chem lab !!! AMAZING AND I MEAN AMAZING explanation

@kentchemistry

2 жыл бұрын

You are welcome

YOU JUST SAVED MY ASS ^_^ Both my ass and my assignment :') Thank you so much!!!

Awesome, thank you!

Wow! YOU MADE THAT EASY!

thank you so much!

easy to follow, thx

shouldn't the freezing point of solution be subtracted from freezing point of pure benzene and not the other way around?

Why did the depression constant for benzene change to negative?

@vivian164

8 жыл бұрын

+Willam Bailey it's always been negative since depression means that it goes down

help🙏🙏. About this solution..... Calculate the molar mass of sucrose in a solution prepared by dissolving 4.27 grams glucose in 50.0 grams water. The solution boils at 100.3°C which is above the normal boiling point of pure water. Kb=0.512°C/m

Do you not have to put the kg back to g?

Do I need to convert to g if the given value of the mass of the unknown compound is in kg?

@kentchemistry

3 жыл бұрын

The water or different solvent must me in kg so you can solve for your moles in the molality. Please like and subscribe. Look for the yellow paper for your chemistry videos explanations.

dammm ur soo cool! :D

Move hand

illuminati confirmed

Legit

Thank you so much for this. It really helped me out a ton. And am I the only one who laughed when the molality was .666? I'm sure of it now. my chemistry teacher is satan, since it took this example to teach me how to do it.

@Lexyvil

8 жыл бұрын

+TheEternalMoonlight Your teacher is awesome. Wish I could get referential videos like that from mine on how to explain relations between data better.

Is it right that freezing point depression = freezing point of solution (minus) freezing point of pure solvent? Because some of the example that I saw, they uses freezing point of pure solvent (minus) frezzing point of solution to find the freezing point depression.

@kentchemistry

2 жыл бұрын

yes, it is the difference.