I want to say thank you. You had helped me so much and I made an A in every class from statics to Structural Analysis. I spread word about you to everyone at Texas Tech university to learn from you. You are the man!

I just love ur sound and approach to solve problem... !!!!

@structurefree

10 жыл бұрын

satya prakash patel fo sho.

thanks for this Video Tutorial Master . ur the man . More Students to come to watch ur videos :) Thanks again

Thanks for saving my ass before every final exam.

@martinchalonga7595

4 жыл бұрын

lol he does that me too

Very helpful. Much better than my teachers. Thanks

BAM!!! good stuff i enjoy the way u explain things

This was extremely helpful, thank you so much for this video m8 :)

watching 2018 structure free is my saviour thank you Structure free

Deflection is the hardest chapter in structure in first 9 chapters i can proudly saying that you (structure free) is my teacher

Thank you, one question would this be considered as a variable section beam?

u are awesome keep uploading amazing videos like this .... thank for your effort

how do I know if the reactions from the real beam are going to make a rectangular distributed load vs a triangular one in the conjugate beam?

Thanks a lot for the videos man! so very helpful! :)

Thanks. do you have another examples for Conjugate beam method?

thanks for the help, keep the videos coming

You are a hero!

What determines the direction of the curvature loading? Is it just a convention such that the loading is upwards when the beam is under comp at top and tension at bottom?

do u have a video for statically indeterminate beams finding the reactions ..

Thaaaaaank you. Big midterm tomorrow on conjugate and double integration method. Didn't understand either one bit till I watched your videos.

@RohanRonQM

8 жыл бұрын

+Chad Waisanen tank a u

love ur voice so much....

Love your videos, Always helpful

man you da best

that bam sound was amazing 😉

I love the way you do commentary it gets me siked to do SA

Do you tutor?! I’m in desperate need and your videos are the only thing that somewhat get me through!

You are amazing thank you!

great videos!!!

جامد جدا والله الواحد سهل يدرس بره بس محتاج توفيق ربنا بس

U R the man .. thanx for the vids

@ eyeGOPu1 as the loading is a uniformly distributed load UDL so total force on the span = loading per unit distance[w(x)] times the loading distance and the moment about the point is multiply the shear force with the center of its action to the section C so 4m times 5m.

thanks for the lesson

awesome!!!!

Hey, When you calculate Mc what is the 5m and 1.5m - "is the arm here" ??

Im from the middle east but i dont know why i understand in english better than arabic :/ And yeah you are awesome bro you make things easier.. thank you

thanks for your video really helped me a lot.

Thank you

Whats statics?

why did you draw the conjugate beam below the x axis?

I have a quick question, what will happen if your deflection and angle turned up to be negative and not as they should be (positive) ?

@structurefree

9 жыл бұрын

Mel13z the internal moment diagram would change and consequently the curvature diagram and then the conjugate loading direction would change...give it a shot.

nice way of xplanation... i got it

May I ask if this problem is also applicable to Double Integration method? thank you :)

@structurefree

4 жыл бұрын

You could solve this problem using the double integration method too.

Thank You!!!

Awesome, but your diagram isn't it supposed to be sloping?

Sir, can use D.I. method and area-moment method here? Or just conjugate method? Thanks!

@structurefree

5 жыл бұрын

Yes, just be sure to account for the change in EI.

@martrayleigh7988

5 жыл бұрын

@@structurefree thanks sir. But can you give me idea how to do it in D.I. method? Area-moment is look same in conjugate method but I can't on D.I. method. Thanks.

THANK YOU

you saved my ass, thanks a metric ton

If there would have another concentrated moment at B then how would be the curvature diagram??

@tarikhussain2450

5 жыл бұрын

Okay...I got it.... Thanku....

ثانكس ^^

thank you sir.. :))

Holy Shit. God Bless The Internet!

Thanx Alot

Thank Bro.

@structurefree

8 жыл бұрын

+Wora B'Wp you're welcome.

@712vrt

8 жыл бұрын

+structurefree what if if there is a loading at the center ...where the inertia changes plz hlp?

but this beam has to be translated since it has different moment of inertia, how come you not using 250*4 for the translated section AB and 500*3 for BC and taking moment arms respectively

Your V'c should be equal to V'c={ (2000N.m^2 / EIab) + (1500N.m^2 / EIbc) } you should square the meter see ~ 9:00