One day, I'll pay all the great tutors on KZread back.

@barrettjamie1642

2 жыл бұрын

i know Im randomly asking but does anyone know a method to log back into an Instagram account..? I stupidly lost my account password. I appreciate any help you can offer me.

@finnegandylan800

2 жыл бұрын

@Barrett Jamie Instablaster :)

@barrettjamie1642

2 жыл бұрын

@Finnegan Dylan i really appreciate your reply. I found the site through google and I'm trying it out atm. Looks like it's gonna take a while so I will reply here later with my results.

@barrettjamie1642

2 жыл бұрын

@Finnegan Dylan It worked and I finally got access to my account again. I am so happy! Thanks so much you saved my ass !

@finnegandylan800

2 жыл бұрын

@Barrett Jamie Happy to help :)

wow, these last couple of videos of the playlist help make a complete comprehensive overview of the ideas need to learn tensor algebra and tensor calculus. This is a must watch for any General Relativity student

The way you explain is wonderful. I'm glad I found you. I was breaking my head with these concepts, now it's all clear. Thanks a million for making it EASY. :) God bless.

0:27 A Basis 1:31 Check Linear Combination 2:26 Span 2:52 Satisfying Linear Independence 3:21 A more complicated example (R 2x2) 3:54 Span check 4:23 Distribute the Scalars. Add up the new matrix. 4:45 Make sure a solution exists 5:43 Check Linear Independence 6:57 Row Echelon Form: - No Free Variables - All Scalars must be = 0 7:34 Both conditions verified ✔️ Basis With N Elements= Dimension N 9:05 Check Comprehension

@hamidalrawi2204

5 жыл бұрын

people like you are angels in human form !! thank you.

@tidalfriction5301

3 жыл бұрын

gangster

@silverlink1191

2 жыл бұрын

Nicee, thx for this

@Smoothcurveup52

Жыл бұрын

Wow wonderful

Wow! Thank you so much! Your videos are so simple, easy to understand, and concise! Thank you!

Wow u are an awesome tutor. I easily learned the topics in 1 hour instead of 24 hours of nonsense thank u so much😊😊😊😊

Thank you for explaining this topic so clearly. 💕

Thank you for explaining this so straight forward and to the point.

Professor Dave has really helped me and still helping me

Basis vectors/Matrices seemed so far out of reach even after trying to understand them for a couple of weeks but after this video, which make them seem easy, I think I finally understand them. Thanks Dave! :))

very clear explanation and examples,thank you !

Thanks a lot for sharing your knowledge. Your explanation is good. It would have been better if you have included explanation of the question and answers also.

Your video is amazing! I finally understand this point. Thank you so much!

Very easy to understand..Thanks for the video🙏

This was incredible and clear bro!!!

YOU ARE AMAZING! YOU NEED TO HAVE MORE SUBS!!

I never imagined that I would ever understand linear algebra. Thanks bro

I love your content. Why don't you have a million subs yet man!?

@ProfessorDaveExplains

5 жыл бұрын

tell your friends and help me get there!

@hemanthkotagiri8865

5 жыл бұрын

@@ProfessorDaveExplains I'm already on it, Dave.

@davidmulit8167

3 жыл бұрын

@@ProfessorDaveExplains This aged well.

@sandeepjabez

2 жыл бұрын

@@ProfessorDaveExplains well, look where you are!! btw, is there a way I can get hold of your presentation 'ppt'?

@LexusKing-iz3up

Ай бұрын

3 now lol

Thank You! Can't wait for a video about a uniform space and tensors; I repent, I never truly understood them.

I have a sweet information When n (number of columns) is not equal to m (number of rows) then the set is always not a basis (if the question ask if a specific set of vectors is a basis or not) but when n = m, then you have two possibilities depending on the det(A), in other words: det(A) is equal to 0 ==> the set is not a basis det(A) isn't equal to 0 ==> the set is a basis

Thanks Professor Dave! ❤

Please send reference books, websites that you use... That would be helpful.

The reduced row echelon form isn't finished yet at 7:22, you can still do R3+R4, R2-R4 and after that R1-R3 which doesn't require you to solve the remaining set of equations.

@johanjimenez1249

3 жыл бұрын

You don't need to since you can see c4 is equal to zero which would then make the rest zero.

you saved my life, linear algebra wanted me not to graduate

@Chad-be3jm

4 ай бұрын

how are you doing now bud ?

@creedbratton4950

2 ай бұрын

I wanna know too ​@@Chad-be3jm

I literally understood something that my professor has been explaining for two weeks in just 10 minutes. Thanks!

these r so helpful and great !! helping me survive thru college 😄😁

Great video. Very clear. With gratitude from india

Thanks for teaching me Newton's Laws! ~We love your work

YOU ARE SAVING MINE AND MY ROMMAMTES FUTURES THX

I already gave a like as soon as I saw the intro

sir, you're a hero, jesus christ you have no idea how doomed i'd be without this video right now

tysm!!!!!! you saved my life!!

Dave single handedly educated half a million people in 10 minutes

5:05 since you’re taking the determinate of the square matrix and it’s a none zero number, isn’t also linearly independent too?

@gayathrik8194

3 жыл бұрын

that was what i was thinking too :)

this guy is actually the goat

but the main question is-why the canonical basis is indexed by natural numbers?And can we describe canonaical basis in terms of matrices?

Can we expect a subspace who span vector space but vectors (elements ) in that subspace are linearly dependent?

I think the first 3 vectors is because for a R2, one need only 2 vectors for creating a base for R2. Plus, 3,2 could be 2 times the 1,0. Right?

@CHEESYhairyGASH

2 жыл бұрын

Yeah, the could be built using 2 x + 1 x

Wonderful theme

Really very good contain 🙏🏽

Do free variables effect whether or not the basi can be linearly independent?

Thanks

Good expression , thanks 🇹🇷

so good thank you

Superb 😃😃

Linear independent vectors means we cant take linear combination of them...on the other hand span is all the linear combination of those vectors. Basis is the vectors will be linearly independent + they will span. I am confused...how these 2 can be true at the same time?

You are a godsend

thanks a lot!

Thx

For the first question in the comprehension part, 0 is the determinant, so that should be linearly dependent right?

@eduardomoreira7624

2 жыл бұрын

Independent

@eduardomoreira7624

2 жыл бұрын

|A|=0 =linearly independent

why do professors make everything seem harder...?

@muhammadzaid308

3 жыл бұрын

I wish I knew....

@joeysmith5767

3 жыл бұрын

They feel like they have to fill up the lecture time that was assigned and they end up stretching the material out in a complex way to fill the time

@gemy6188

3 жыл бұрын

It's about Talent and the different criteria, some have the knowledge but they haven't the capability to deliver this knowledge.

@kmishy

3 жыл бұрын

@@gemy6188 In India we could also talk about lack of knowledge and poor delivery skills

@swavekbu4959

2 жыл бұрын

Two reasons: 1. They don't know how to teach and don't have a firm grasp of the subject themselves. 2. They want to confuse you so that fewer people have mastery of the knowledge. The less you know, the more they know, and people with big egos want to have "specialized" knowledge that is not accessible to others. Write a book nobody understands, and claim yourself a genius.

At 5:26 how is the determinant 1? Cause multiplying the 4 brackets above from the formula (ad-bc) gets: 0, 0, 1, then the last one is 0-1 which is -1

@egeyesilyurt3701

Жыл бұрын

doesnt matter regardless, if the det isnt equal to 0 we can proceed

If they are linearly independent, it means there are no linear combinations among the vectors. So, how can a basis have two conditions where (1) they are linearly independent and (2) they span the vector space V (by a linear combination of the vectors), don't the conditions contradict each other? Please clarify, and let me know if I'm missing something here.

@sahilkhurana6941

3 жыл бұрын

Dude ! Linearly independent does not mean that they will have no linear combination its actually satisfies that they can have linear combination coz we check that the vectors are not dependant so that we can have all the possible linear combination!

@RahulSharma-oc2qd

3 жыл бұрын

Linear combination and linear dependent is two different things. Whether given two vector elements within the vector space are linearly dependent or not has to do nothing with the linear combination. Any set of vector elements can be written as linear combination (with respect to their coefficients)

superb ....

Sir can we find the null space of set of vectors from M2x2 like we do for vectors in R^n

What if such cases when determinant is zero yet it has infinitely many solutions?

what if instead of all leading ones we had a leading 2 in some position. thats okay right ?. since its not Reduced row echelon form

2 v + 3 w.. In this v and w are vectors and these are basis as well?

For R 2X2 matix, can't we just say that the matices are linearly independent as their determinant is not equal to zero. We created the matrix 4X4 which is a square matrix and its determinant is 1, so it satisfies that they are linearly independent.!!!

@Anton-vy5dt

Жыл бұрын

I thought the same thing, but idk

How can you have more than a dimension of 3 in a 3D space? Wouldnt any more vectors are just repetitive and therefore be linearly dependent?

@ProfessorDaveExplains

2 жыл бұрын

Mathematics isn't limited to the three spatial dimensions we are familiar with, it can utilize many more. We just are incapable of visualizing it.

But Im not getting the determinant value as 1 in example 2 while checking for spaning 5.23 ... Can somebody please help.... please...

How to apply curl to higher dimensional vector field

cool haircut and nice video .

Doesn't the det of matrix being 1 (not 0) means its elements are linearly independent (so we don't need to form row echelon form)

@Yuu.riishii

10 ай бұрын

I agree with this.

@nark4837

6 ай бұрын

also, can you confirm that there is no point in ever checking both conditions for basis, i.e., condition 1: spanning, condition 2: linearly independent? if you know it spans and number of vectors > number of dimensions, it can't be a basis. if you know it spans and number of vectors = number of dimensions, it MUST be a basis. if you know number of vectors you might as well just manually look, saves you work

Isnt the set of vectors rank 4 ? How can a rank 4 span R2

1. The dimension of the matrix is 2. In the matrix , the entry in the third row and second column is _____. 3. For what values of and , the two matrices are equal?______ 4. Write a diagonal matrix of order two, such that the entries on the diagonal zero._______ 5. Given the following matrices and , then compute a) b) c) d) e) f) 6. Find the products of a row matrix and the column matrix ; that is and YX. 7. A manufacturer produces three products: A, B, and C, which he can sell in two markets. Annual sales volume is indicted as follows. Product A B C Market I 10,000 units 2,000 units 80,000 units Market II 6,000 units 20,000 units 8,000 units a) If unit sales of A, B, and C are 2.50 Birr, 1.25 Birr, and 1.50 Birr, respectively, find the total revenue as a product of matrices in each market. b) If unit sales of A, B, and C are 1.80 Birr, 1.20 Birr, and 0.80 Birr, respectively, find the gross profit as a product of matrices in each market pleas do you make this

Can somebody please help me? In the previous video where we had to check whether a matrix is linear independent or not by row operation, we didn't get all 1's in the main diagonal. But in this video why do I have to get all one's in the main diagonal?

@karthi6548

3 ай бұрын

works either way, i think

@karthi6548

3 ай бұрын

because all we aim is to reduce the variables

in the comprehension, how the first one is not linearly independent ?

This is a godsend. Ya boy thought he was fucked for midterm

6:36 how can we multiply R3 by -1 wont it change the equation??

@AS-ds4in

Жыл бұрын

Found this comment 6 months later and now i know the answer if we multiply both sides of an equation it will still remain the same equation and is valid here the other side of the equation(right of =) is 0 and 0 multiplied by anything gives 0 so we dont include it

Professor, vector space with the only vector "zero vector" has dimension 1. 8:23

@evertonalmeida1165

3 жыл бұрын

Nope, it has dim 0 or none

He unlocked the 4th dimension 👀

thank you, can you give me a vector space with infinite dimensions?

4:54

Can anyone provide me solution of last 2 questions?

why is the first one not a basis in the comprehension

Your explanation is good but you didnt explain the type of questions in the check comprehension

Move words passing through a video when you are explaining

Save my life

thank you linear algebra jesus.

why aren't u my college professor 😭

Sir ua so handsome

Pls help me?

😮

in french: span is engendré!!!

Sahh dude

What happend to your hair prof ?

Stop watching anime brother. We must fight the MPLA. (Matrices Projections Linear Algebra)

1st to comment!

I miss the jesus version 😂😂

@oussamameddori

Ай бұрын

🤣🤣🤣🤣

There is god and he is an American

I am disappointed...I sent you an email two weeks ago. No response from you yet.

Dude... Every 5 seconds you pause for like 3 seconds.... then we all get to hear you take a deep breath and talk for 5 more seconds, then pause again. You need to just relax and talk like you are in a conversation.

@ProfessorDaveExplains

4 жыл бұрын

No. The pacing is deliberate for those who need time to process what's on the screen. Teaching math is not a conversation.

@aryanks2167

3 жыл бұрын

The pacing is all good to me

@farhatfatima1168

2 жыл бұрын

@@ProfessorDaveExplains yes you are right sir