i subscribed and liked! You're a life saver. About to do a mock and im terrified because im aiming for an A but ive been doing so bad- your videos are so very helpful. Thank you for taking the time out of your day to help strangers :)

@crave4654

2 жыл бұрын

How did u do?

@brandonpotter7574

Жыл бұрын

@@crave4654failed

Thank you Tony, this was well structured video has helped my son to understand the topic. Keep up the good work!

Thank you for the video, i have at least general knowledge for tomorrows test :D

Great vid! Got me through my mocks!

Thank you very much for this video. Whenever my teachers taught mechanics i just never seemed to understand it as easily as everyone else, and the lessons where so fast paced. Thank you for helping me understand what is actually going on. Its much easier to do now that i understand

@tonydebling

11 ай бұрын

My pleasure ☺

Thank youu so much.....it really helped me..😃😃😃

You save lives🙏

KZread had to recommend me this video AFTER my mech exam today..... thanks youtube :I

BLESS YOU! IHAVE MY IGCSE TOMORROW AND YOU ARE AN ANGEL

@brunocarrascosa632

3 жыл бұрын

A bit late but this is AS

@aimminjale3032

3 жыл бұрын

@@brunocarrascosa632 Brooooo😭😭 Good Luck

Thankyou very much, this was so concise and helpful for revision :)

Please do a video on variable acceleration!

Thank you so much!!

Good lad tony love that from you xx

@eleanorachurch5279

Жыл бұрын

agreed, thanks tony xoxo

you sound a bit like David Attenborough, thanks for the amazing vid!

@tonydebling

2 жыл бұрын

Ha ha, flattery indeed!

Thank you!

Great video, thank you 👍🏽

thank u so much!!!

@tonydebling

3 жыл бұрын

No problem 😊

Hi Toney, shouldn't the value of acceleration due to gravity be 9.8. Is 10 acceptable?

@tonydebling

2 жыл бұрын

You will normally be told what approximation to use in the question.

hi tony, at 22:50 how do i work out the distance travelled for each value of t??

@tonydebling

3 жыл бұрын

Substitute the value of the into the equation for x, namely x =1/2t^2(t^2 - 2t +1) which is given in the question.

@tonydebling

3 жыл бұрын

To be more precise x is the displacement, which means if it starts at zero, becomes 1/32, and then goes back to zero the distance travelled is 1/32 + 1/32 = 1/16, then from x=0 at t=1 it becomes x=2 at t=2, so it travels a further distance of 2, giving a total distance travelled of 2 1/16, whilst the displacement at this point in time is still 2. So it is important to understand the difference between distance travelled and displacement.

@elliothosie3206

3 жыл бұрын

@@tonydebling no problem thank you. wasnt using my brain very well for my question👍 thanks again.

Alsalam Alaykoum brother (Hello dear brother). Can you send me the slides' link? Thank you so much. Allah bless you.

@tonydebling

2 жыл бұрын

Wa-Alaykum-Salaam. docs.google.com/presentation/d/1ozUFikQvwgm6unqcs3wZ4FMgv3ycnKTD/edit?usp=sharing&ouid=113090209927709126638&rtpof=true&sd=true

@tonydebling

2 жыл бұрын

Or for a pdf drive.google.com/file/d/1lJQVionh3zFAT9aQrhdTY9YkojsVbB1d/view?usp=sharing

For part B of the variable acceleration question, instead of plugging in all the different values, could you do a definite integral of the velocity equation since the area under the curve of a velocity time graph is displacement? You would still need to split it up of course but would it still work? its probably the most complicated way to do it but its the first thing that came to my mind 😅

@tonydebling

11 ай бұрын

Just remember distance travelled is different from displacement. Areas below the axis represent negative displacement but still positive distances travelled.

For the ball question at 8:22 did you take the upwards direction as positive and is that why 9 was positive cause the ball was moving up? And why wouldn't 9 be negative cause the ball moves down too

@tonydebling

Жыл бұрын

Yep. Positive was chosen to be up. So it's +9 on the way up and -9 on the way down 😀

@ratofalady8125

Жыл бұрын

@@tonydebling ah okay thanks, but then how come you only used +9 when substituting it in and not -9?

@tonydebling

Жыл бұрын

@@ratofalady8125 that was the u in the formula, initial velocity

Hi is this video enough for mechanic?:)

Thank you for the video! At 8:12, why did you say that the acceleration is -10? Shouldn't it be positive 10 since the force of gravity downwards into the ground is positive?

@tonydebling

Жыл бұрын

Up direction has been chosen to be positive.

@mattyhalsall2820

Жыл бұрын

@@tonydebling er sorry if im wrong but shouldn't gravity be 9.8, and not 10

@tonydebling

Жыл бұрын

@@mattyhalsall2820 depends on accuracy used. Question will usually tell you 10, 9.8, 9.81 and I'm sure there are more accurate versions, which would also depend on altitude!!!

@mattyhalsall2820

Жыл бұрын

@@tonydebling but in my exams what degree of accuracy is expected, thanks

@tonydebling

Жыл бұрын

@@mattyhalsall2820 you will usually be told which value to use for g in the question or at the start of the paper.

well done u did all corect

Hi, for 6:13, why couldn't you use s=vt-0.5at^2? Why did you use s=ut+0.5at^2? Wouldn't it be easier to use the first than having to find the value for u to use the second equation could you have not done 20=10t-0.5(0.8)t^2 I came to the answer t=22.8 t=2.2 (to 1dp) (I also hope you're having a great day)

@procasination2544

3 жыл бұрын

ahhhhh wait is it because v is the final velocity at the end of the journey at AB but we don't know what it is at the midpoint of AB/ it will be different at the midpoint so we cant use 10ms^-1 for the second part

@procasination2544

3 жыл бұрын

wait no what but you used 10ms^-1 to find out u but I thought (well came to the conclusion that) we couldnt use v for any other point other than the end at AB

@tonydebling

3 жыл бұрын

Are you procrastinating?

@procasination2544

3 жыл бұрын

@@tonydebling but can you help me and answer why because I have no idea and I can't move on if I don't understand

@LucyLucyLucyLucyLucy99

2 жыл бұрын

@@procasination2544 do you get it yet? lmaooo i saw this and had to ask

Cheers cuz

How do you get T=8.4N at 16:48?

@tonydebling

3 жыл бұрын

Take g=9.81, rearrange equation 1,29 -T = 1.2x2.81, T = 1.2(9.81-2.81)=1.2x7=8.4N

@syeed7659

3 жыл бұрын

@@tonydebling ohh, thanks

which formula are you rearranging at 23:20

@tonydebling

3 жыл бұрын

in the question you are given x=1/2t^2(t^2 -2t +1) which can be factorised/rearranged to give x=1/2t^2(t-1)^2

at 14:47 why the acceleration of Q is not -5g/7 ???

@tonydebling

11 ай бұрын

You are asked to find the magnitude which us always positive. Whether the acceleration is positive or negative depends on you choice of positive (displacement, velocity, acceleration and force) up or down.

why is t=-2 for the suvat equation @7:55

@tonydebling

Жыл бұрын

t = +2 as a root ot the quadratic. s = -2 as when particle hits ground displacement is 2 in negative direction

5:35 answer for acceleration how does it equal 0.8? isn't it 2.5? or am I tripping?

@tonydebling

Жыл бұрын

Too many mushrooms in the omelette I think. Are you happy with 40=50- 1/2 a 5^2? -10 = - 1/2 a x 25 so 20 = 25 a so a = 20/25 = 0.8 :)

@swipez_yt1741

Жыл бұрын

@@tonydebling where the -10 come from?

@tonydebling

Жыл бұрын

40 - 50 (subtract 50 from both sides of the equation)

@swipez_yt1741

Жыл бұрын

@@tonydebling oh yup, thank you I was just tripping

Thanks for the video. Exam in less than 24 hours👍🏽

@tonydebling

2 жыл бұрын

Pleasure

Tony I hava q quostion any chance you could help me?

@tonydebling

3 жыл бұрын

Sure

@Aryan-fy6cq

3 жыл бұрын

@@tonydebling hey I know this sounds Ridiculous but I have a test next week and I might need some help moment any chance you could contact me at my email Ariyan26f@gmail.com so I can send u what I need help with if not I completely understand

@Zen_Zen_Zense

3 жыл бұрын

@@Aryan-fy6cq so how did the test go, were you prepared enough 👍

@Vic4life

3 жыл бұрын

@@Aryan-fy6cq did he answer ???

i think i love you

Hi Tony, could you explain why there are two Rs in 18:06? I did not understand that part x

@tonydebling

2 жыл бұрын

Hi Kiara, there is an equal and opposite reactions between the lift and the woman. The blue R reprsents the lift pushing the woman up, and the red R represents the woman pushing the lift down. These are equal and opposite. The colours were used to separate the forces acting on the woman and the forces acting on the lift.

@kiaraj7044

2 жыл бұрын

@@tonydebling thank you!

hi tony, just wanted to ask how you got t= 1000(g-2) at 19:47

@tonydebling

2 жыл бұрын

Just rearrange the equation above it and factorise. -T + 1000g = 2000, 1000g = 2000 + T, T= 1000g - 2000 = 1000(g - 2)

@condoriano4217

2 жыл бұрын

@@tonydebling ohh so 7800 N, thanks alot for clearing that up

9:51 why do you +\- 0.458 ?

@tonydebling

Жыл бұрын

Values of t as particle when it is at height are roots of the quadratic 5t^2 - 9t + 3 = 0 using the quadratic formula you get the roots as 0.9 +/- 0.458. The first part is -b/2a second part is the discriminant divided by 2a. Sqrt(9^2 - 4(5)(3))/2(5). Hope this helps.

@jasmine9215

Жыл бұрын

@@tonydebling tysm for the quick reply! i used quadratic but kept getting different answers compared to the vid, maybe there was an error in my calculation

@tonydebling

Жыл бұрын

@@jasmine9215 I think you made a mistake in your calculation. B^2 -4ac is 21, sqrt(21) is 4.582

hello fellow procrastinators

@Sxlanki._x

Жыл бұрын

🫣

How did you rearrange the formula at 5:37

@tonydebling

2 жыл бұрын

40 = 50- 1/2a x 25, so 1/2a x 25 = 10, so 25a = 20, and a = 20/25 [was that your question?]

14

For 19:01 is it meant to be (R - T + 950g = 950 x 2) or is it (R + 950g - T = 950 x 2)

@DopeAK7

2 жыл бұрын

nevermind its the same thing lol

@tonydebling

2 жыл бұрын

They're equivalent?

Will this make me pass tomorrow's exam, or shall I ask you one on sports instead?😂😂

@yahya5022

Жыл бұрын

same bruh

God bless america

only issue is you dont really explain why youre doing what youre doing which is a bit confusing :/

@tonydebling

Жыл бұрын

An interesting philosophical point. In general the answer is to choose some laws of mechanics to allow us to write some equations, and then to solve the equations to find out the missing information that we are asked for.

hi sawaiz

@epicshibexd5049

3 жыл бұрын

lol

@tonydebling

3 жыл бұрын

Had to Google it but thank you.

does not matter i am gonna fail anyway

@haniakhakwani

Жыл бұрын

good luck! do your best we've got 6 hours

Bruh

thank you so so much!!