Wow, I have learned more watching this series in one night then I did in an entire month of class. Thanks for the effort you put into these, and I'll definitely be sharing these with my group.

@Leah4sci

6 ай бұрын

You're very welcome, happy to help! and thanks for sharing!

I can't describe how much you are helping me with my study for exam and i just want to say thank you that you are exist you truly have a beautiful talent and pasion 💜keep going

@Leah4sci

3 жыл бұрын

Wow, thank you! I'm so happy to hear that my videos are helping you, let me know how your exam turns out!

Quite a clear presentation! Thanks for your hard work. :D

@Leah4sci

3 жыл бұрын

My pleasure!

Thank you so much for creating these clear, concise, and organized videos! It's helped me understand and absorb information so much more efficiently. Keep up the great work!

@Leah4sci

3 жыл бұрын

You're so welcome! I'm so glad that my resources have been helpful to you!

I was to skip to her next video when she said “but we are not done yet”. She got me 5:13

@Leah4sci

Жыл бұрын

Fake out! Haha, just a small bit left after that. Thanks for watching!

You deserve a noble price❤

@Leah4sci

9 ай бұрын

Aww thanks!

Thank you leah. God bless you

@Leah4sci

5 ай бұрын

You're very welcome!

thank you so much this is so much easier to understand now!!!

@Leah4sci

5 жыл бұрын

Glad I could help!

Your. Ppt. has. Really. Helped. Me. A. Lot. Thanks

@Leah4sci

6 ай бұрын

You're so welcome, happy to help!

Amazing series! Could you also make a series about nucleophilic aromatic substitution?

@Leah4sci

2 жыл бұрын

I cover that in the orgo study hall leah4sci.com/join

Thanks for such a nice explanation 😊

@Leah4sci

5 жыл бұрын

you're welcome :)

fantastic i love this plzzz do more videos for reaction mechanism

@Leah4sci

4 жыл бұрын

I have lots more! Use this to match my resources to what you are studying: leah4sci.com/syllabus

thank you you are amazing , so helpful thank you so much

@Leah4sci

6 жыл бұрын

You're very welcome!

Amazing explanation😍

@Leah4sci

5 жыл бұрын

I hope it helped you understand the topic better.

Thanks so much for sharing that information 🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸🌸

@Leah4sci

3 жыл бұрын

You are so welcome!

In the last step of the mechanism why didn't the so3- (on the benzene) abstract the h+ from the hydronium ion

@muiz5638

5 жыл бұрын

I think it might be because the hydrogen in OH is more positive than the one in H3O+ due to the negative charge drawing electrons from three sources as opposed to one making those hydrogens less delta positive than the one on OH, and the SO3- attacks the more positive charge (OH hydrogen).

Quick question, but when doing the mechanism to find the superelectrophile why did you use 2 sulfric acids. I thought we only had one avaliable.

@Leah4sci

2 жыл бұрын

Catalysts in solution are never limited, they're poured in by the thousands (millions?)

The same thing could have happened in the previous reaction I.e nitration where we used sulphuric acid

@sheikhsaimaalavieasha8557

3 жыл бұрын

Yes... We ignore SO3 there.! Strange chemistry

@Leah4sci

7 ай бұрын

When you have 2 potentially reactive groups, ask yourself which one is more reactive, that's typically the one you'll see added

in the beginning, why did you react two H2SO4 molecules together when only one is given?

@josphellihsilak4588

6 жыл бұрын

N G because theres more than 1 in solution. Same as if there was h3o, the solution contains many of everything in it.

@Leah4sci

4 ай бұрын

Molecules never show up in singles. Anytime you see numbers it's there to tell you a ratio. This means that 1 reactant and 1 reagent means you have millions at a ratio of about 1:1

can the so3- on benzene abstract the H from bezene to restore aromaticity and form Ar-SO3H?

@Leah4sci

4 жыл бұрын

At which specific point in the video? (Timestamp please)

I just didn't understand where the positive charge came from? Wouldnt O form a dative covalent bond with the H+ coming from the other acid molecule using one of its 2 lone pairs and so would still have 8 electrons?

@Leah4sci

6 ай бұрын

Following the octet rule isn't reason enough for an atom to be neutral in charge. I'm unfamiliar with the term "dative", but if you're speaking of the positively charged oxygen on the protonated sulfuric acid, then it has a positive formal charge because 6 valence electrons for oxygen minus the 5 electrons that it has directly attached to it leaves us with a +1 formal charge. For more on calculating formal charge, make sure to see my tutorial at Leah4sci.com/Formal

@bray8949

6 ай бұрын

@@Leah4sci ah ok omg tysm! Btw in A levels we said that a dative covalent bond = coordinate covalent bond. In our syllabus it was actually used much more over the latter. Oh and BTW thank you so so so much for your tutorial videos I remember struggling to understand when I was still studying for my A levels and finding your videos. They were always so extremely helpful and every time helped me to immediately understand whatever it was that my lecture notes or even private lesson notes did not explain in enough detail. THANK YOU!

Mam my quetion is :Attack of nucleophile and electrophile in benzene same time??

@Leah4sci

3 жыл бұрын

I'm sorry, I don’t believe that is what I said. This is an electrophilic aromatic substitution reaction. Which step of the mechanism do you have a question about? Could you leave me a time stamp?

@MODEOFACTION-eu5hw

3 жыл бұрын

1)when benzene undergoes electrophilic aromatic substitution such as sulfonation, the benzene molecules acts as ? A)an electron acceptor. B)an electrophil C) an nucleophile. D) Isomer 👆👆Mam, please Tell me the correct answer of this Multiple choice question?

I don't understand the part where oxygen has 3 lone pairs and has a negative charge whereas it's positive 1 lone pair. why?

@Leah4sci

Ай бұрын

To calculate the formal charge of an oxygen, we take the number of valence electrons of a neutral atom (which is 6) and subtract the lone pair electrons as well as half of the bonding electrons. In the case of the oxygen with 3 lone pairs, that leaves us with 6 valence electrons minus 6 lone electrons minus 1 in the bond. That's 6-7 = -1 In the case of the oxygen with 1 lone pair, we have 6 valence electrons minus 2 lone electrons minus 3 in the bonds. That's 6-5 = +1. To review this concept, make sure to see my Formal Charge tutorial at Leah4sci.com/Formal

what other subjects you teach ??

@Leah4sci

3 жыл бұрын

I cover all the science subjects for the MCAT: leah4sci.com/mcat/

great videos

@Leah4sci

6 ай бұрын

glad you like it!

Does this work with cyclobutadiene?

@Leah4sci

2 жыл бұрын

This video doesn't address that particular question, and unfortunately I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

@jesscorbin5981

2 жыл бұрын

@@Leah4sci thank you

u r goood..thank u so much...

@Leah4sci

6 жыл бұрын

You're welcome :)

best really very very good

@Leah4sci

4 жыл бұрын

Glad you enjoyed it

thanks .

@Leah4sci

5 ай бұрын

You're welcome!

thank you :-)

@Leah4sci

6 ай бұрын

You're welcome!

Thanks a million, my teacher gave us the products but didn't give the mechanism 😐

@Leah4sci

4 жыл бұрын

Glad I could help fill in the gaps!

This playlist is... Rhenium Aluminum Gold... So, I say: Thank Yttrium Oxygen Uranium. (And with that, the good puns Argon)

@Leah4sci

7 ай бұрын

lol, You're welcome, happy to help!

NO

@Leah4sci

4 жыл бұрын

No?

tf would i do without you

@Leah4sci

2 жыл бұрын

Aww, thanks!

thank you you are amazing , so helpful thank you so much

@Leah4sci

3 жыл бұрын

You're so welcome!