Really hope he’s doing well and realizes how good and helpful this was to me.

@ScottKennedyMath

4 жыл бұрын

Thank you for the kind words Ana Marie!

Literally after a decade you're still saving a generation thank you so much mister!

absolutely goated video. dude explained in 10 min what my teacher couldn't clear up in 3 lessons

9 year difference yet it's explained better than my teacher! thank you!

You don't know how many times I was thanking you while watching this video😆. You made this difficult concept simple for me to understand finally. No joke, God bless you! 😭😭

This was such a good explanation! Super easy to follow and learn, lifesaver!!

Oh my gosh. You are amazing. I've learned a lot in 10 minutes.

You nailed it bro. Thank you so much, you answered all the questions i had.

This is so helpful!! Sending best wishes thank you so much !!

bros a savior fr

Thank you so much! You made it so easy to understand.

fantastic work Scott keep it up!

excellent lesson!!

thanks buddy, keep up the good work!!

hey i found a helpful video!!!

This is very helpful

thank you scott

what a lad. great lesson but also a great personality.

very helpful thank you :)

Thank you for this! Out of curiosity, which region from the U.S are you from? I'm guessing East Coast?

Nice video!!!!

thankyou so much

god damn that was a great lecture.

thank u!

LOVE YOU

TY

wowwwww thank youuuu

Sir may i ask what did u do on the 3:59 ? the t-5 and t-2?

James Madison says hello

Yeah

At 5:05 where did you get 2 and 5? Is it just a random pick of numbers or you did something?

@ScottKennedyMath

3 жыл бұрын

Those are the values of t where v(t) = 0 (*see 4:14). These are the locations where the particle may change directions since it needs to come to rest in order to change direction.

When you added up the total distances, one of those numbers was a negative number. Why did you still add instead of subtract?

@mississippichungo

8 жыл бұрын

+Skull Mann because hes looking for distance not displacement

why does a derivative of position become velocity and the derivative of velocity become acceleration? can any one explain i am not getting it!!

@ScottKennedyMath

4 жыл бұрын

Because derivative calculates rate of change at any defined point. The rate of change of position is velocity. Think change in position divided by change in time (dx/dt): distance divided by time is RATE (ft/sec for example)... The rate of change of velocity (how fast the velocity is changing) is acceleration.

what if he is looking for displacement

@VersedYT

7 ай бұрын

Then you wouldn't use absolute values, so you'd subtract the 27 (negative) from the 52.

📌03/22/24

why it became (t-5)(t-2)=0 ? confused. sorry