Algebra RECTANGLE WORD PROBLEM - Let’s solve it step-by-step….

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Math help with how to solve an algebra word problem involving a rectangle and perimeter. For more math help to include math lessons, practice problems and math tutorials check out my full math help program at tcmathacademy.com/
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Пікірлер: 5

  • @je6845
    @je6845 Жыл бұрын

    Thank you for sharing your skills 💖

  • @legna6802
    @legna68022 жыл бұрын

    Excellent explanation!

  • @mattslupek7988
    @mattslupek79882 жыл бұрын

    Before watching the video, I did this in my head: L = 3w - 2 3w -2 + w = 30 4w -2 .= 30 4w = 32 w = 8 L = 3w - 2 >> 3(8)=24 >> 24 - 2 = 22 L = 22; w = 8 P = 2L + 2w 2(22 + 8) = 60 44 + 16 = 60

  • @tobyharnish8952
    @tobyharnish89522 жыл бұрын

    Again, this expert will try his best to solve this. 2(3w-2)+2w = 60 6w-4+2w = 60 8w-4 = 60 8w-4+4 = 60+4 8w = 64 8w/8 = 64/8 w = 8 If the width is 8, then the length is 3*8-2 = 24-2 = 22 Check: 22*2+8*2 = 44+16 = 60

  • @MrMousley
    @MrMousley9 ай бұрын

    Let's do this .. and then watch your video Call the width W and the length 3W - 2 and the perimeter is 60 .. which is the width twice plus the length twice So W + W + 3W - 2 + 3W - 2 = 60 8W - 4 = 60 8W = 60 + 4 8W = 64 W = 8 So the width is 8 and the length is 3 x 8 - 2 = 22 Check 8 + 8 + 22 + 22 = 60 YES !