ALEKS: Calculating reaction free energy under nonstandard conditions

Пікірлер: 11

  • @sarinacruz8971
    @sarinacruz89712 жыл бұрын

    I just wanted to say thank you so much for these videos! You’re the reason I was able to get through all my Aleks topics and you also helped me understand my chem 120 class this semester a lot better! ☺️🙌

  • @rxdntpto
    @rxdntpto8 ай бұрын

    Thank you for explaining that we don't have to worry about ALEKs wanting the answer in kJ while our answers are in kJ/mol lol. The whole reason I searched up this video was to find an explanation for that!

  • @RoxiHulet

    @RoxiHulet

    8 ай бұрын

    ALEKS is a tricky little bugger sometimes :)

  • @taniahenriques7710
    @taniahenriques77102 жыл бұрын

    what do I do if the problem gives me concentrations instead of pressures? help me roxi I love you

  • @RoxiHulet

    @RoxiHulet

    2 жыл бұрын

    ❤️ you can use concentration in place of the pressure

  • @sundyn9951
    @sundyn9951 Жыл бұрын

    If the problem gives the concentrations of the reactants, but only grams of the product (with no Liter value), how do I solve for the Q if I don't know the molarity of the given product in grams?

  • @RoxiHulet

    @RoxiHulet

    Жыл бұрын

    Is the product a solid? If so, it’s left out of the calculation of Q. Only use (aq) and (g) to solve for Q, just like K.

  • @sundyn9951

    @sundyn9951

    Жыл бұрын

    @@RoxiHulet okay! so then since the product is solid, would the numerator to solve for Q, be one?

  • @RoxiHulet

    @RoxiHulet

    Жыл бұрын

    @@sundyn9951 yep!

  • @ChristopherIvan98
    @ChristopherIvan988 ай бұрын

    I noticed towards the ending you changed the signs after getting -11448 j/mol. Why is that? How come you didn’t just do (-32.8 kj/mol) + (-11.448 kj/mol)? I tried and got the wrong answer but i want to know why 🤣

  • @RoxiHulet

    @RoxiHulet

    8 ай бұрын

    hey, I watched the video and I don’t see the point where I changed a sign. Could you be a little more specific?