ALEKS - Using Reaction Free Energy to Predict Equilibrium Composition
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Пікірлер: 15
@LesbianTuesdays5 жыл бұрын
Thank you. The ALEKS explanation for this problem was absolutely horrible
@auroraeredia99174 жыл бұрын
Thank you for posting this!! Can you do a video on "Using the Van Hoff equation to predict K at a Different temperature." There are two similar but different questions that frequently come up on that module. It's pretty difficult and the ALEKS descriptions is sub-par. Thanks as always .
@linandlen6 жыл бұрын
Thank you so much!!
@dawnngo76904 жыл бұрын
How were you able to use small x method? Is it because of the low calculated K value or because of the positive G, which indicates that this reaction does not happen spontaneously?
@strugglingcollegestudent
2 жыл бұрын
Same I have this question because we aren't given K
@jaysonnelson53964 жыл бұрын
Thank you for posting this!! Can you do a video on "Using the Maximum Work Theorem with Chemical Work." There are two similar but different questions that frequently come up on that module. It's pretty difficult and the ALEKS descriptions is sub-par. Thanks as always .
@TonyStJohn
4 жыл бұрын
Hi Jayson, I just uploaded two videos that tackle this topic for you! The first is a more basic example: kzread.info/dash/bejne/fox_zMiRqpaffdo.html And the second is a more involved/challenging example: kzread.info/dash/bejne/on6Dw9WkgqTYiKg.html Thanks for the request!
@user-uc4jo7yc8j Жыл бұрын
how did you solve for the pressure of cl2
@williamsandberg54673 жыл бұрын
very helpful for parts 1 and 2,
@emadahmad25732 жыл бұрын
can you please do this topic (Using the maximum work theorem with chemical work)
@TonyStJohn
2 жыл бұрын
Hey Emad, thank you for the request, I made two videos since this one is pretty tough! Example 1: kzread.info/dash/bejne/anaZs7Ntksq-gLg.html and Example 2: kzread.info/dash/bejne/gpd5q86AodLbito.html
@OLUWAMAYOWA.4 жыл бұрын
I wished you showed us the steps for solving K
@makenziebaldwin3260
4 жыл бұрын
Same, also would have helped if there were labels on the numbers in the equation
@myst_bass3290
2 жыл бұрын
A little late lmao, but do (41000J)/(-8.314*1332.15). Then take that number, which is around -3.7, and do e^-3.7.
Пікірлер: 15
Thank you. The ALEKS explanation for this problem was absolutely horrible
Thank you for posting this!! Can you do a video on "Using the Van Hoff equation to predict K at a Different temperature." There are two similar but different questions that frequently come up on that module. It's pretty difficult and the ALEKS descriptions is sub-par. Thanks as always .
Thank you so much!!
How were you able to use small x method? Is it because of the low calculated K value or because of the positive G, which indicates that this reaction does not happen spontaneously?
@strugglingcollegestudent
2 жыл бұрын
Same I have this question because we aren't given K
Thank you for posting this!! Can you do a video on "Using the Maximum Work Theorem with Chemical Work." There are two similar but different questions that frequently come up on that module. It's pretty difficult and the ALEKS descriptions is sub-par. Thanks as always .
@TonyStJohn
4 жыл бұрын
Hi Jayson, I just uploaded two videos that tackle this topic for you! The first is a more basic example: kzread.info/dash/bejne/fox_zMiRqpaffdo.html And the second is a more involved/challenging example: kzread.info/dash/bejne/on6Dw9WkgqTYiKg.html Thanks for the request!
how did you solve for the pressure of cl2
very helpful for parts 1 and 2,
can you please do this topic (Using the maximum work theorem with chemical work)
@TonyStJohn
2 жыл бұрын
Hey Emad, thank you for the request, I made two videos since this one is pretty tough! Example 1: kzread.info/dash/bejne/anaZs7Ntksq-gLg.html and Example 2: kzread.info/dash/bejne/gpd5q86AodLbito.html
I wished you showed us the steps for solving K
@makenziebaldwin3260
4 жыл бұрын
Same, also would have helped if there were labels on the numbers in the equation
@myst_bass3290
2 жыл бұрын
A little late lmao, but do (41000J)/(-8.314*1332.15). Then take that number, which is around -3.7, and do e^-3.7.