Activation Energy Diagrams

How to interpret both exothermic and endothermic activation energy diagrams.

Пікірлер: 12

  • @theimpossibledream14
    @theimpossibledream14Ай бұрын

    The best explanation I found on YT thank you😊❤🙏👍

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Ай бұрын

    Hi Krueger, I am so glad. Thank you for your comment:)

  • @user-sc7fh1de3f
    @user-sc7fh1de3f5 ай бұрын

    Thank you for helping understanding 🙏God bless you I really appreciate that

  • @OldSchoolChemistry

    @OldSchoolChemistry

    5 ай бұрын

    Hi Abar, Think you for the blessing! I am proud of your hard work. God bless you in your efforts:)

  • @hoanhtrinh4863
    @hoanhtrinh48633 жыл бұрын

    Thank you for the knowledge you've imparted

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    cr7, My pleasure. I hope your class goes well!!

  • @asisababun7543
    @asisababun75432 жыл бұрын

    Thanks for the video great apron explanation

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Asis, I am so glad you liked the apron example. I think the contextualizations helps students. Please subscribe if you have not already. Thanks!

  • @roxanneal-nimri8534
    @roxanneal-nimri85343 жыл бұрын

    You are sooooo helpful! Thank you

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi Roxanne, I’m so glad. Thank you for your comment!!😊

  • @roxanneal-nimri8534

    @roxanneal-nimri8534

    3 жыл бұрын

    @@OldSchoolChemistry of course! I have a question though. If you have a 3 step mechanism and you have 2 fast ones, do you solve for the intermediate in both of them and then plug that in to the slow step rate law?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    @@roxanneal-nimri8534 Hi Roxanne, you only use the fast step that occurs before the slow step. Only fast steps that precede the slow step will go into equilibrium. There is usually only one fast step before the slow step. If there are multiple fast steps before the slow step then you are correct. When finding the overall rate law you can ignore the fast steps that happen after the slow step. I hope that helps!