Acid-base titrations | Chemical reactions | AP Chemistry | Khan Academy

In a titration, a solution of known concentration (the titrant) is added to a solution of the substance being studied (the analyte). In an acid-base titration, the titrant is a strong base or a strong acid, and the analyte is an acid or a base, respectively. The point in a titration when the titrant and analyte are present in stoichiometric amounts is called the equivalence point. This point coincides closely to the endpoint of the titration, which can be identified using an indicator. View more lessons or practice this subject at www.khanacademy.org/science/a...
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Пікірлер: 244

  • @shahadab6294
    @shahadab62943 жыл бұрын

    greetings for all those students that are teaching themselves, trying to understand and fighting, because they have useless professors or doctors! your truly strong and can do it :))

  • @swagatmalla6634
    @swagatmalla66347 жыл бұрын

    I study in one of the best schools of my country but I develop my understandings only through online vids...

  • @swarajsakharkar6103

    @swarajsakharkar6103

    5 жыл бұрын

    Swagat Malla why is this so relatable?

  • @mrlilnomad

    @mrlilnomad

    5 жыл бұрын

    This is so accurate. I graduate with a B.S. in Biology from a great school 3 years ago and only now do I fully understand these videos. Maybe we really just aren't ready for these topics at the ripe age of 18-19.

  • @unhuman537

    @unhuman537

    5 жыл бұрын

    Same here ,I read in one of the best coaching class of my state but I learn all things and concepts through online videos ...lol😂😂😂

  • @srikarvundavalli5934

    @srikarvundavalli5934

    4 жыл бұрын

    @@mrlilnomad well what about us having to study these topics at 15? 😂

  • @mrlilnomad

    @mrlilnomad

    4 жыл бұрын

    Twin Turboed just try to nail the big picture of every process. It’ll certainly help you along the way. I was watching some of these videos just days before my MCAT, and now I already have an interview with a medical school!

  • @mrlilnomad
    @mrlilnomad5 жыл бұрын

    I love how I already graduated w/ a B.S. in biology and I understand these issues so much more AFTER I am done with school. Now that I'm studying for the MCAT and actually watching videos all of these topics make so much more sense. Hate that I didn't apply myself in school. Fantastic vid.

  • @Kronangaurd
    @Kronangaurd4 жыл бұрын

    hearing someone other than your chem teacher say molarity hits different.

  • @jairustheadventurer3935
    @jairustheadventurer39357 жыл бұрын

    3 weeks until the end of chemistry! I am so freaking done with school this year. I am loosing my sanity!

  • @imheretofindasmr8990

    @imheretofindasmr8990

    6 жыл бұрын

    omg you do titration in schools?

  • @possesivepvp3982

    @possesivepvp3982

    6 жыл бұрын

    we do everything as a sophomore, its similar to AP chem but a little less in depth

  • @mistushipper

    @mistushipper

    3 жыл бұрын

    same accelerated chem is killing me

  • @sonyaharjani

    @sonyaharjani

    3 жыл бұрын

    i have one more week of school and i have my final test for chem tmrw :)

  • @Rydooky

    @Rydooky

    3 ай бұрын

    Yall are lucky I'm in triple acceleration I'm in 7th learning this shit

  • @AmineChM21
    @AmineChM218 жыл бұрын

    Please keep this up it is so helpful

  • @josephmaglipon6828
    @josephmaglipon68286 жыл бұрын

    It woulda been nice to have known this before taking my ap chem test yesterday

  • @tamamshud5879
    @tamamshud58797 жыл бұрын

    With the help of khan academy I will survive exams. Needless to say that my teachers are so unqualified😑

  • @rachaeleniola5059

    @rachaeleniola5059

    7 жыл бұрын

    ngn mA so true

  • @hmz01_

    @hmz01_

    6 жыл бұрын

    lol i feel u

  • @thefinal__sage5696

    @thefinal__sage5696

    5 жыл бұрын

    hahaha i feel u bro my sucks ass in both chem and bio

  • @naomii5482

    @naomii5482

    5 жыл бұрын

    The teachers are qualified but they don't do their job.

  • @unhuman537

    @unhuman537

    5 жыл бұрын

    Yes u r right.I sometimes think that why all school teachers are like this ....unqualified lol😂😂😂

  • @daniellejohnson5534
    @daniellejohnson55346 жыл бұрын

    ASDFHFJGKGKGL I just need to accept im getting a C in Chem. But it’s fine. I’m fine. EVERYTHING IS FINE GODDAMMIT

  • @natalyadonohue726

    @natalyadonohue726

    5 жыл бұрын

    Never, before have I related to a god damn comment more than this... holy crap

  • @notme9363

    @notme9363

    3 жыл бұрын

    @@natalyadonohue726 same except I'm failing

  • @septic7301

    @septic7301

    3 жыл бұрын

    getting B here

  • @edream2513soccer
    @edream2513soccer6 жыл бұрын

    Not all heroes wear capes 😅

  • @UserName-us1nm

    @UserName-us1nm

    4 жыл бұрын

    How do you know he doesn't wear one?

  • @ohitsme-_-7790

    @ohitsme-_-7790

    4 жыл бұрын

    @@UserName-us1nm 🤣

  • @mysticdragonex815

    @mysticdragonex815

    3 жыл бұрын

    He just wears pants

  • @mikecabbage7623
    @mikecabbage76232 жыл бұрын

    So basically we just identify the missing variable (e.g. the concentration or volume) then set it up as M= mol/L. Then we balance the chemical equation to see what the ratio between the acid and base is. Taking the ratio into consideration, we determine the missing concentration or volume by setting up another M=mol/L except with the originally unknown variable. Hopefully that was right?

  • @sarahjin5005

    @sarahjin5005

    2 жыл бұрын

    Sounds about right to me, it helped clear a bit of confusion from the MV=MV relationship. The number of moles of the acid is equal to the number of moles of the base shown by the equation

  • @ungepaul6476
    @ungepaul64767 жыл бұрын

    Thank you for uploading this video. Really helped me out..

  • @CrystalSillwind
    @CrystalSillwind6 жыл бұрын

    thank you for this video, I've just begun IB HL chemistry and it was already getting stressful, this video helped a lot!! thanks!!!

  • @yashdaryani8954

    @yashdaryani8954

    5 жыл бұрын

    shouldnt you have finished titration long before you came into IB?

  • @daak333

    @daak333

    5 жыл бұрын

    lmao at least not where I’m from, we’re finishing up topic 1

  • @kuriouskoopatroopa3129
    @kuriouskoopatroopa31298 жыл бұрын

    u helped me so much thank you for everything ! :D

  • @missgeekie9242
    @missgeekie92426 жыл бұрын

    I mean... Why did my chem teacher give the class a titration concentration table the day before a test for review without explaining it? Why does this look a little complicated, what am I doing here, why wont they let me sleep, why am I pulling an all nighter for this test, why did he give all the review the day before the test? Im going to be okay :D

  • @willhodge7921

    @willhodge7921

    5 жыл бұрын

    I am in the exact situation you are in right now. Never been taught titration so I'm here on a Sunday night before the Exam.

  • @mysticdragonex815

    @mysticdragonex815

    3 жыл бұрын

    no

  • @alwysrite
    @alwysrite7 жыл бұрын

    very well explained, thankyou

  • @ankur3015
    @ankur30154 жыл бұрын

    THANK YOUR SIR ! FOR CLEARING ALL MY DOUBTS ABOUT TITRATION. I'M GREATFUL!

  • @martinjulian5207
    @martinjulian52075 жыл бұрын

    I prefer the short cut method of MV=MV .The problem is that it only applies wen the mole ratio for both is 1:1.anyway thanks❤

  • @DavetutsAcademy

    @DavetutsAcademy

    4 жыл бұрын

    There is a wider formul that applies at all instances. It us given as CaVa / CbVb = Na / Nb That's way more comprehensive

  • @max3eey

    @max3eey

    Жыл бұрын

    Just put the coefficients in front of the M

  • @MarsPotatoes
    @MarsPotatoes7 жыл бұрын

    Why can't my teacher actually explain stuff to us like this is stead of giving us packets with reading

  • @mdtokitahmid2970
    @mdtokitahmid29708 жыл бұрын

    best ever video on titration!!!!!

  • @stevemoreno
    @stevemoreno5 жыл бұрын

    have a lab due in a couple hours hope i can learn this fast

  • @rosesidi4982

    @rosesidi4982

    4 жыл бұрын

    woow thats great

  • @rayirthsivakumar8202
    @rayirthsivakumar82024 жыл бұрын

    Fantastic Video!!! I was stuggling with this concept but now I understand.

  • @AminaSarfraz724
    @AminaSarfraz7243 жыл бұрын

    i missed my classes when we studied titration and this was so helpful, thank you!!!!!

  • @sabby1950
    @sabby19505 жыл бұрын

    this was so helpful! i'm so grateful thank you very much !!

  • @Mypersonalyoutube123
    @Mypersonalyoutube1235 жыл бұрын

    The whole video can be summarized as M1V1=M2V2

  • @wantedtofeelwanted3717

    @wantedtofeelwanted3717

    5 жыл бұрын

    or C2V2=C1V1

  • @wantedtofeelwanted3717

    @wantedtofeelwanted3717

    4 жыл бұрын

    @S S Patil thanks hon

  • @rioZtherealone

    @rioZtherealone

    3 жыл бұрын

    @@wantedtofeelwanted3717 bro what can you explain this

  • @wantedtofeelwanted3717

    @wantedtofeelwanted3717

    3 жыл бұрын

    @@rioZtherealone expalin what

  • @marvinguerrero5667

    @marvinguerrero5667

    3 жыл бұрын

    @@rioZtherealone He used the dilutions formula. But that only works when the mole ratio is 1 to 1

  • @anonymousash6678
    @anonymousash66784 жыл бұрын

    For those who don't know, Molarity is just the concentration but in the unit (Moles/Litre)

  • @amnakausar9306

    @amnakausar9306

    3 жыл бұрын

    tyy

  • @christianuli5607
    @christianuli56078 жыл бұрын

    What would be really helpful would be a video only showing examples which are visual with all three acid-base titrations.

  • @yumenoritsu
    @yumenoritsu8 жыл бұрын

    Thank you :)

  • @i_am_gods_child
    @i_am_gods_child3 жыл бұрын

    the quick method that you taught us at the end was really helpful thankyou so much!!

  • @thecalligraphist6457
    @thecalligraphist64573 жыл бұрын

    Such a wonderful video with awesome explanation, too good for beginners

  • @joshuadougall2544
    @joshuadougall25448 жыл бұрын

    Thanks, very clear and understable

  • @imgoingbackto-lv4fx
    @imgoingbackto-lv4fx7 жыл бұрын

    Hi, I'm trying to perform a titration to find the average amount of lactic acid concentration in yogurt and how much is in a certain amount of bacteria(such as streptococcus thermopilus). I am confused on what my standard solution would be, pls help?

  • @nurnashwazulaikha9292
    @nurnashwazulaikha92924 жыл бұрын

    all of your videos are very helping me to understand chemistry moreeee...tqqqqqqqqq

  • @faisalshaffi4818
    @faisalshaffi48188 жыл бұрын

    it was good 2nd method is more easy😊

  • @yetisage5200
    @yetisage52008 жыл бұрын

    i hate chemistry with a passion

  • @mazin_mubarak7769

    @mazin_mubarak7769

    8 жыл бұрын

    You are not alone

  • @zephyrzinnia3697

    @zephyrzinnia3697

    7 жыл бұрын

    With a Very VERY strong Passion !!!

  • @vishnuprasadvk9127

    @vishnuprasadvk9127

    7 жыл бұрын

    Yeti Sage I LOVE chemistry! Thanks to breaking bad lol

  • @vishnuprasadvk9127

    @vishnuprasadvk9127

    7 жыл бұрын

    James Lee haha yeah

  • @jairustheadventurer3935

    @jairustheadventurer3935

    7 жыл бұрын

    Yeti Sage I thought it would be cool, but know I understand the pain! 😠🔫

  • @dalilarobledodebasabe191
    @dalilarobledodebasabe1918 жыл бұрын

    Wow. Super clear and helpful. Thank you.

  • @sannalaharshavardhanreddy7567

    @sannalaharshavardhanreddy7567

    7 жыл бұрын

    Dalila Robledo De Basabe

  • @melissarainchild
    @melissarainchild4 жыл бұрын

    Now I understand, thanks for explaining :)

  • @wafaah7903
    @wafaah79037 жыл бұрын

    thanks a lot thats was amazing !

  • @syedakazmi5204
    @syedakazmi52047 жыл бұрын

    this is realy so helpful...thanku sir....

  • @RebenUsman94
    @RebenUsman948 жыл бұрын

    thanks...

  • @vetyancie
    @vetyancie4 жыл бұрын

    what a great explanation! thank you.

  • @anubhutisrivastava4581
    @anubhutisrivastava45816 жыл бұрын

    the different colors just make it so much interesting

  • @swyrl
    @swyrl7 жыл бұрын

    thank you for this

  • @Kencan254
    @Kencan2548 жыл бұрын

    Is the simplified method -MV base =MVacid only applicable when the reactant mole ratio is 1:1 ?

  • @lakshgupta70

    @lakshgupta70

    8 жыл бұрын

    Nopes, for any mole ratio

  • @bart5557

    @bart5557

    8 жыл бұрын

    That's what I tought at first as well, but the ratio is already embedded into the volume of both acid and base

  • @musataz

    @musataz

    7 жыл бұрын

    Yeah that's right.

  • @Jack-mc7qe

    @Jack-mc7qe

    6 жыл бұрын

    Actually the full formula when there is different stiotoimetric ratio is *(M1V1)/Stiotoimetric ratio of acid in reaction = (M2V2)/Stiotoimetric ratio of base in reaction* No need to say thanks😎

  • @CrystalFoxxx

    @CrystalFoxxx

    6 жыл бұрын

    Manteg Singh thanks!!! This was confusing me 😣

  • @asiyaheastman5733
    @asiyaheastman57337 жыл бұрын

    thank you very much this helped me alot

  • @katiemartin5158
    @katiemartin51584 жыл бұрын

    Thank you so much, this really helped me! :) :) :)

  • @053_abdulhannanbhat8
    @053_abdulhannanbhat86 жыл бұрын

    Gr8 video thanks helped a lot

  • @cathean19
    @cathean198 жыл бұрын

    Thank you.

  • @bronzedflames
    @bronzedflames8 жыл бұрын

    is the same process still used if the conc. of the base is unknown? :)

  • @CaPuGinoXD

    @CaPuGinoXD

    5 жыл бұрын

    itsrainingchan yeah

  • @nazzypazzy8390
    @nazzypazzy83906 жыл бұрын

    i think a more suitable indicator would be methyl orange great video btw

  • @ishikajain3979
    @ishikajain39793 жыл бұрын

    I really like the introduction. Thanks Khan Academy.

  • @famd1551

    @famd1551

    2 жыл бұрын

    It's not just me who come to his Videos to watch the introduction for Report

  • @sonnghiemthai9945
    @sonnghiemthai99456 жыл бұрын

    will the short cut way still work if the mole ratio were different

  • @SenorSkor
    @SenorSkor5 жыл бұрын

    You assumed early on that I knew how to "Solve for X" now I can't move forth with the rest of the video #whygodwhy #nowIknowwhyoneshowtheirwork

  • @zvlaz
    @zvlaz4 жыл бұрын

    Im so glad I only need one class of chemistry, ive always hated it

  • @nath7874
    @nath7874 Жыл бұрын

    how can you use phenolphthalien when hcl is a strong acid and naoh is a strong base. isnt that indicator only used for weak acid and strong bace?

  • @fallxnsquad33
    @fallxnsquad337 жыл бұрын

    What is the program you used?

  • @hitmanpx2237
    @hitmanpx22373 жыл бұрын

    Thanks I got it Explaination is awesome 🙂🙂🙂

  • @AmineChM21
    @AmineChM218 жыл бұрын

    God bless

  • @imanj1537

    @imanj1537

    6 жыл бұрын

    Gunbnelch Maui

  • @sarahjin5005
    @sarahjin50052 жыл бұрын

    awesome video! 😁 gave it a thumbs up 👍

  • @rishabhpandey3822
    @rishabhpandey38226 жыл бұрын

    very nice...👍

  • @mohammadghaziasgar3160
    @mohammadghaziasgar31603 жыл бұрын

    I can not find words to appreciate.

  • @watchtrap
    @watchtrap7 жыл бұрын

    Thank you

  • @malaikaremedios784
    @malaikaremedios7845 жыл бұрын

    can you not do this in two steps using ratios? 20ml : 48.6ml 0.1 moles : x moles 20/0.1= 200 so 48.6/200= 0.243 M or will this not work every time?

  • @NeelSandellISAWESOME
    @NeelSandellISAWESOME4 жыл бұрын

    Thank you so much!!!!!

  • @muhammadazeemmohsin5666
    @muhammadazeemmohsin56663 жыл бұрын

    Love this.

  • @edgardahl5305
    @edgardahl53053 жыл бұрын

    You can also use: C1*V1=C2*V2? So it would be C1=0,1M, V1=48,6ml, V2=20ml, and C2=x You will have: (C1*V1)/V2=C2 (0,1M*48,6ml)/20ml=0,43

  • @informationperimeter652
    @informationperimeter6526 ай бұрын

    Thank you. For amazing explanation

  • @menahakim5169
    @menahakim516913 күн бұрын

    God bless your soul

  • @Gealamusic
    @Gealamusic3 жыл бұрын

    Thank you very much! :)

  • @derpishbadger6515
    @derpishbadger65158 жыл бұрын

    thanks

  • @abo-sr7ds
    @abo-sr7ds5 жыл бұрын

    Really thank u

  • @AstralApple
    @AstralApple3 жыл бұрын

    Hello I have a question. Beaker A contains a solution with a ppm of 3000. Beaker B contains 1 liter of pure water. If I take 10 mL of solution A and add it to beaker B for a final volume of 1010 mL in beaker B, what is the ppm of the new solution in beaker B? Thank you very much.

  • @SabrinaXe
    @SabrinaXe6 жыл бұрын

    Lol the moment he took out the calculator

  • @analatu260
    @analatu2604 жыл бұрын

    Thank you..

  • @songkev
    @songkev6 жыл бұрын

    I didn't understand what a standard solution, equivalence point, and that stuff was about - even though I got taught that in chemistry but I still don't understand it :(

  • @Mypersonalyoutube123

    @Mypersonalyoutube123

    5 жыл бұрын

    Standard solution- a solution whose molarity you know. (eg. a 2M NaOH solution)

  • @Mypersonalyoutube123

    @Mypersonalyoutube123

    5 жыл бұрын

    Equivalence point- when all the. "H+" of the acid combine with all the "OH-" of the base(eg. You would need 1 mol of HCl to neutralize 1 mol of NaOH)

  • @rosesidi4982
    @rosesidi49824 жыл бұрын

    thats great

  • @dannalouisse9311
    @dannalouisse93114 жыл бұрын

    you're better at this than my teacher

  • @xray2402
    @xray24024 жыл бұрын

    Please dear : if we have water tank has avolume of water 25000 liter ,and pH=4 ,And i want to add sodium hydroxide to the tank until reach pH=7...determine concentration of sodium hydroxide that you added to keep pH=7??

  • @abusafiankarifo9367
    @abusafiankarifo93674 жыл бұрын

    How can get the tutorial of double titrations

  • @pepitobenegas
    @pepitobenegas4 жыл бұрын

    You forgot to say that in order to find moles we multiply liter per M

  • @Dareshensvlogz
    @Dareshensvlogz3 жыл бұрын

    Comments here from 6 years ago 4 years ago 4 months ago 2 weeks ago and 1 day ago so its not a new problem but chemistry been stressing us out for years 🥲💀

  • @musataz
    @musataz7 жыл бұрын

    Chemistry's born to mess with minds.......:(...............titration calculations were easy though.....:P

  • @ssn2191
    @ssn21913 жыл бұрын

    Genius.

  • @brokenremedy7821
    @brokenremedy78214 жыл бұрын

    Isn't it much more straightforward to use C1V1=C2V2 and solve for the missing HCl concentration?

  • @theholyramonempire
    @theholyramonempire6 жыл бұрын

    I love the subject chemistry! Just not the way its taught.

  • @oliviaeisnor8845

    @oliviaeisnor8845

    5 жыл бұрын

    hate both

  • @haro1002

    @haro1002

    5 жыл бұрын

    chemistry is a hard subject to teach and understand. Chemistry is not logical like physic and math.

  • @xvixii3657
    @xvixii36574 жыл бұрын

    When the question says 'concentration', does the concentration refers to the 'mole' or 'molarity'?

  • @eyes9514

    @eyes9514

    4 жыл бұрын

    molarity probably

  • @CompanhiadosFermentados
    @CompanhiadosFermentados4 жыл бұрын

    But the problem is that Phenolphtalein only changes color when the pH reaches 8,2, way beyond 7. So you are always measuring a higher acid concentration than it realy is.

  • @androlitoV
    @androlitoV4 жыл бұрын

    Thanks for doing this. My teacher's 💩

  • @park_mina3115

    @park_mina3115

    3 жыл бұрын

    Hahahahaha me 2

  • @cicmilVII

    @cicmilVII

    3 ай бұрын

    Often happens that pupils don't pay attention in the class, don't concentrate or don't put enough effort in the class. Most of the time pupils don't dare to interrupt when they don't understand in order to ask more explanation ( I was also often afraid to ask, not knowing if the question is "good" or it is me that was not following or being not so clever at that moment or not being up to date with previous lessons it is difficult to show that you din't prepare or follow previously). I see difference in private class 1 on 1 or just few pupils, then discussion happens more easily and the result is better even the teacher is the same. Same, when someone watches youtube video most of the time is motivated to understand and does it on his own pace which is not often the case in the class. I recommend to ask in class, teachers like that, because it means that someone is trying and listening. Just few thoughts on "my teacher is crap" ( which might as well be the case :)

  • @edsilstefanoordidor2247
    @edsilstefanoordidor22477 жыл бұрын

    Is the molarity of NaOH 0.1000 M always constant?

  • @nataliechanoi3251

    @nataliechanoi3251

    7 жыл бұрын

    Ordidor no

  • @estebanperez3807

    @estebanperez3807

    7 жыл бұрын

    It is not because molarity depends on volume and the number of moles (n). The number of moles (n) depends on mass (grams).

  • @creeperroese
    @creeperroese4 жыл бұрын

    Wait how did it go from 0.0486 to 0.00486? What did he do to change the places again? 4:32

  • @ONExANDxONLY
    @ONExANDxONLY6 жыл бұрын

    I thought to find the concentration your need to c=n/V??? you seems to C=nxV??? i dont get this

  • @skateboarderlucc

    @skateboarderlucc

    5 жыл бұрын

    concentration (Molarity)=Moles/volume moles=Molarity*volume=(moles/volume)*volume (volume cancels out).

  • @sprinklydonuts1903
    @sprinklydonuts19035 жыл бұрын

    How did he know what the molarity of the base was?

  • @mohdak99momo
    @mohdak99momo7 жыл бұрын

    I love you

  • @PriomTheKchgr
    @PriomTheKchgr7 жыл бұрын

    When you went to find the concentration of HCL, why didn't you use the formula concentration = mass/volume? Wouldn't that have worked? Concentration's unit is in grams per cubic decimeter or in mols per dm^3

  • @chaytonsheargold3210
    @chaytonsheargold32105 жыл бұрын

    why did you divide by 4.86 by 20?

  • @smp219
    @smp2194 жыл бұрын

    Pls higher the volume

  • @sairamk5959
    @sairamk59597 жыл бұрын

    👍👍👍

  • @ariellahakimi5033
    @ariellahakimi50335 жыл бұрын

    Much easier way is mass times volume of acid = mass times volume of the base. You will get the same answer

  • @dennisc5607

    @dennisc5607

    5 жыл бұрын

    Ariella Hakimi Ya I know!!!!!!!!!! I saw him do this and was like why??

  • @Rydooky

    @Rydooky

    3 ай бұрын

    ​or understanding of topic

  • @yashdaryani8954
    @yashdaryani89545 жыл бұрын

    i fucking love you khan academy

  • @jennyritz4611
    @jennyritz46116 жыл бұрын

    I was so happy with this as a link to show my students until you got to 7:30 and told them it's acceptable to use M1V1 = M2V2. You don't START with the context that it works only for 1:1 reactions and that it is not an acceptable general case for titrations. Most of the time, students stop watching after they figure out the way to do the problem! I suffered through EIGHT YEARS of titrations being set up as dilution problems regardless of the mole ratio, and this just perpetuates that error. You have to present the context FIRST, or, better yet, don't present the method that way at all!