ABAQUS #2: A Beam with Springs and Line Load

Errata: The equation of the lineload should be -24x+120 and NOT -120x +600 as in the video. My apologies for the rookie mistake.
I show how to model a beam supported by two springs which is also subjected to a triangular line load using the popular abaqus modelling software. A 2D beam analysis is used.

Пікірлер: 30

  • @sdaesamesr6706
    @sdaesamesr67066 жыл бұрын

    These videos are awesome!

  • @sarojdebnath1112
    @sarojdebnath11126 жыл бұрын

    Great work man!

  • @theengineer6224
    @theengineer62244 жыл бұрын

    thank you for your help I want to make simulation for high performance concrete but i dont know what is the parameters that i need it to make simulation to HPC , Can you explain it to me ?

  • @archieotley4903
    @archieotley49033 жыл бұрын

    Hi, I really love your work and how your present it. I was wondering how you would go about finding the force in the spring that you used? Im doing a project where I need to find that force in relation to a buckling load. Many thanks

  • @tinng1756
    @tinng17563 жыл бұрын

    Hello, Can I ask that how can I add spring element at the middle of the beam? As When I add spring elements in the middle of the beam it doesn’t affect my simulation

  • @prawingajbhiye8816
    @prawingajbhiye88165 жыл бұрын

    thank you so much from india...

  • @user-te5ib7tg1d
    @user-te5ib7tg1d6 жыл бұрын

    Thank you!

  • @LeoneChong0574
    @LeoneChong05745 жыл бұрын

    i have a simple question, when you chose degree of freedom for spring, why you chose 2 degree instead of 1? Thanks for your video.

  • @TMsChannels

    @TMsChannels

    5 жыл бұрын

    Hi, Thanks for the comment. I chose 2 as the second degree of freedom corresponds to displacement in the global Y-direction (which in this case is the direction our springs are orientated in). 1 would be for displacement in the global X direction and 6 corresponds to the rotation about the global Z-axis. Hope this helps :)

  • @sarojdebnath1112
    @sarojdebnath11126 жыл бұрын

    Thank u very much

  • @nooraldeen4092
    @nooraldeen40926 жыл бұрын

    amazing video please slab reinforcee under static load please

  • @phaneendrakumar9637
    @phaneendrakumar96374 жыл бұрын

    Thank you soo much

  • @masoudazimi5941
    @masoudazimi59412 жыл бұрын

    It is imposible.why did the end of beam go up?

  • @hazemismaeel1488
    @hazemismaeel14887 жыл бұрын

    Thank you for this tutorial could you please simulate beam on elastic foundation in abaqus

  • @TMsChannels

    @TMsChannels

    7 жыл бұрын

    Hi, It's my pleasure. I shall put in on my list of videos :)

  • @hazemismaeel1488

    @hazemismaeel1488

    7 жыл бұрын

    Thank you very much in advance

  • @deepakkulange966
    @deepakkulange9666 жыл бұрын

    I think equation of line used is wrong.Equation of line must be y=-24x+120 where x varies from 0 to 5 mtrs

  • @TMsChannels

    @TMsChannels

    6 жыл бұрын

    You're right :) I will add a note to the video

  • @Machozz
    @Machozz3 жыл бұрын

    How do you calculate the spring stiffness?

  • @TMsChannels

    @TMsChannels

    3 жыл бұрын

    Hi, its given in the problem statement. In real life typically a spring has a given stiffness which is available from the manufacturer.

  • @Machozz

    @Machozz

    3 жыл бұрын

    @@TMsChannels Hello, thanks for the quick reply. If I were to replace a, let's say a roller support or a fixed support with a spring, how do I represent it in Abaqus?

  • @minhly650
    @minhly6506 жыл бұрын

    It appears that you made a little mistake of writing triangle load equation. The equation of the triangle load is -120e3*X + 600e3 = 5y => y = -24e3*X + 120e3, so your input at 11:18 must've been -24e3*X + 120e3. Hope to hear from you soon. Thank you

  • @TMsChannels

    @TMsChannels

    6 жыл бұрын

    Hi, I went and checked it and believe mine is correct. The 120 kN/m value given is the slope of the line. So you have y=-120e3X+c and you know that the point (5,0) lies on the line. By substituting that back you get c = 600e3, hence y = -120e3X + 600e3.

  • @minhly650

    @minhly650

    6 жыл бұрын

    Hi, I asked my instructor about this problem, He said if we set the center of the global coordinate system at the left end of the beam and we use it to write the equation of the line load, then we have the line load passing through two point (0,120) and (5,0). Generally, we have the equation of a line passing through two points A(xA,yA) and B(xB,yB) as follows: (x - xA)/(xA - xB) = (y - yA)/(yA - yB) In this case, we have the equation passing through (0,120) and (5,0) as: (x - 0)/(0 - 5) = (y - 120)/(120 - 0) => y = -24x + 120 Hope you recheck again. Thank you.

  • @TMsChannels

    @TMsChannels

    6 жыл бұрын

    Hi, you are indeed correct. My assumption that 120 was the slope is totally wrong. Its been a while since I looked at detailed analysis. I will add a note to the video and thanks for pointing it out :)

  • @jeremydoan2667

    @jeremydoan2667

    5 жыл бұрын

    Hello ! Do we need to keep "e3" when you type the expression? I typed: 120e3-24*X Thank you !

  • @Don_Quixote_1492

    @Don_Quixote_1492

    5 жыл бұрын

    @@minhly650 is the line passing thru (0,600) and (5,0) ?

  • @mohamedelzeadani3881
    @mohamedelzeadani38813 жыл бұрын

    👍🏻

  • @snijdertkswr
    @snijdertkswr6 жыл бұрын

    south african much?