Thanks!

@Alamaths

4 күн бұрын

Thank you so much.❤

I have watched a lot of videos but this one really impressed me. Excellent work Mr Alamaths. Makes you think

@Alamaths

5 күн бұрын

Wow, thanks

Nice

@Alamaths

6 күн бұрын

Thank you

Hello My Dear Family😍😍😍 I hope you all are well 🤗🤗🤗 If you like this video about How to solve this math problem Please like and subscribe to my channel as it helps me a lot，🙏🙏🙏🙏 ❤❤❤❤❤❤❤❤❤❤❤

This is a pattern which repeats. Look at the original equation. Its obvious zero is a solution. This is a combination of 4 consecutive integers. The difference is in signs..The explanation is more important than the solution. This pattern is often seen in tests for mathletes.

@Alamaths

5 күн бұрын

Thank you

Why don't you let a=x^2+17x+71 and b=x^2-17x+71? It will be much easier.

@Alamaths

3 күн бұрын

Okay. Next time thank you. Have you subscribed? ❤❤

(x+7)^2+3(x+7)=(x-10)^2+3(x-10)=>17x+70=-17x+70=>x =0

@Alamaths

Күн бұрын

Thank you. You must be a professor Have you subscribed?

Проще числитель и знаменатель умножить на выражение стоящее в числителе и ответ виден автоматом х равен нулю чуть преобразовавдробь

@Alamaths

5 күн бұрын

Yes, it is easy. Thank you so much. Have you subscribed? ❤

If you are not familiar to sumout any problem , why are you demonstrating like othes , steps are incomplete

@Alamaths

22 сағат бұрын

Thank you. Have you subscribed?

A primera vista sale x=0

@Alamaths

5 күн бұрын

Thank you so much

My answer before watching: x=0

@Alamaths

6 күн бұрын

Thank you

@jeffthebracketman

5 күн бұрын

Wrong 0/0 = undefined

@remixgameyt1172

5 күн бұрын

@@jeffthebracketman what? are you stupid? (x+7)(x+8)(x+9)(x+10)/(x-7)(x-8)(x-9)(x-10) if x=0 (0+7)(0+8)(0+9)(0+10)/(0-7)(0-8)(0-9)(0-10)=(7*8*9*10)/(-7*-8*-9*-10)=(1*1*1*1)/(-1*-1*-1*-1)=1/1=1

@harrymatabal8448

5 күн бұрын

Mr Remi you are another great man to admire well done

@ChavoMysterio

5 күн бұрын

@@jeffthebracketman the only roots that would make the equation undefined is 7, 8, 9 or 10.

X=0 solution évidente ! c n est pas la peine de continuer même c faut/ c b1 x=0 Vous faites durer la vidéo pour avoir des sous c pas gentil!!!

@Alamaths

Күн бұрын

Thank you. Have you subscribed?

@Alamaths

Күн бұрын

Are you a professor?

Numerator (x+7)(x+8)(x+9)(x+10) (x²+17x+70)(x²+17x+72) Let a=x²+17x (a+70)(a+72) (a+70)(a+70+2) Let y=a+70 y(y+2) Denominator (x-7)(x-8)(x-9)(x-10) (x²-17x+70)(x²-17x+72) Let b=x²-17x (b+70)(b+72) (b+70)(b+70+2) Let z=b+70 z(z+2) [y(y+2)]/[z(z+2)]=1 (y²+2y)/(z²+2z)=1 y²+2y=z²+2z y²-z²+2y-2z=0 (y-z)(y+z)+2(y-z)=0 (y-z)(y+z+2)=0

@ChavoMysterio

5 күн бұрын

y-z=0 y=z a+70=b+70 a=b x²+17x=x²-17x 2x²+34x=0 x²-17x=0 x(x-17)=0 x=0 ❤ x-17=0 x=17 ❤

@ChavoMysterio

5 күн бұрын

y+z+2=0 y+z=-2 a+70+b+70=-2 a+b+140=-2 a+b=-142 x²+17x+x²-17x=-142 2x²=-142 x²=-71 |x|=i√71 x=±i√71 ❤❤

@Alamaths

5 күн бұрын

But x=0 is the correct answer ​@@ChavoMysterio

@ChavoMysterio

5 күн бұрын

@@Alamaths remember, there are more than just one root, including the non real roots.

@Alamaths

5 күн бұрын

@@ChavoMysterio yes. Thanks