29.3 Moment of Inertia of a Disc

MIT 8.01 Classical Mechanics, Fall 2016
View the complete course: ocw.mit.edu/8-01F16
Instructor: Dr. Peter Dourmashkin
License: Creative Commons BY-NC-SA
More information at ocw.mit.edu/terms
More courses at ocw.mit.edu

Пікірлер: 38

  • @ayushraj7254
    @ayushraj72543 жыл бұрын

    U taught this topic better than most of the teachers in Indian coaching who who prepare us for iit adv and stuff. Thank u😗

  • @awsomecube0078

    @awsomecube0078

    2 жыл бұрын

    Bruh I’m here for the same purpose

  • @Freakybananayo
    @Freakybananayo3 жыл бұрын

    clean explanation and straight to the point. thanks

  • @Qwertyuiopasdfghj771
    @Qwertyuiopasdfghj7716 жыл бұрын

    can't concentrate on the physics cause his backwards writing is too impressive

  • @mitocw

    @mitocw

    6 жыл бұрын

    He is writing normally but the video is flipped. You are now free to concentrate. ;)

  • @MurasakiBubble

    @MurasakiBubble

    5 жыл бұрын

    OMG.....all this time I thought they were writing backwards lol!!!! Mind blown

  • @gabriellasut5980

    @gabriellasut5980

    5 жыл бұрын

    Mind blown for the 2nd time

  • @user-rm1jm7pt2f

    @user-rm1jm7pt2f

    3 жыл бұрын

    @@mitocw still impressive tho

  • @sudarshann7194

    @sudarshann7194

    3 жыл бұрын

    @@MurasakiBubble it's russian technique

  • @sarthakthememegod
    @sarthakthememegod Жыл бұрын

    Thanks a Lot Sir, You made is so easy, as I saw a lot of derivations which has no explanation for dm

  • @tlili3990
    @tlili39902 жыл бұрын

    thank you! you explained it way better than my teacher did

  • @ratulhasan7136
    @ratulhasan7136 Жыл бұрын

    MIT: making worlds best tech people Also MIT microphone: we use raw audio with noise

  • @itsmorbintime3746
    @itsmorbintime3746 Жыл бұрын

    woah very nice explanation

  • @raghavendarb3101
    @raghavendarb31016 жыл бұрын

    How do we calculate if the disc is inclined at an angle to the vertical?

  • @virupannamedikinal
    @virupannamedikinal Жыл бұрын

    Thank you so much Sir

  • @harshalshinde9343
    @harshalshinde93434 жыл бұрын

    Why we have taken dm x r^2 only as difinetion of MI of rotational disc

  • @abhishekmeghwal6663
    @abhishekmeghwal66635 жыл бұрын

    Thanks

  • @nevilholmes5900
    @nevilholmes59005 жыл бұрын

    thanks

  • @moo9950
    @moo99506 жыл бұрын

    Since total mass is constant why couldnt we have integrated like this m ∫ r^2 dr from the definition of inertia

  • @MyNameIsThe_Sun

    @MyNameIsThe_Sun

    6 жыл бұрын

    The mass of the total disc is constant however when we consider smaller mass elements the only thing constant is the mass 'distribution'/'density'. So you can't take dm out of the integral!

  • @venky543211
    @venky5432114 жыл бұрын

    Sir can we slove moment of interia of a circle by considering triangle strip. If can please tell me how to slove

  • @Marjiance26

    @Marjiance26

    4 жыл бұрын

    If you want to compute that I think you're gonna use how you compute for the area of a shape in polar coordinates, so you start from θ=0 to θ=2π and then do the rest

  • @PanioGuitarCovers
    @PanioGuitarCovers5 жыл бұрын

    2:51 How can you say that the 2nd order differential dr is zero as dr approaches zero but the first order differential remains unchanged?

  • @rangerbeast

    @rangerbeast

    3 жыл бұрын

    for the ease of calculation he did that

  • @pamelaabede5535

    @pamelaabede5535

    3 жыл бұрын

    Considering the fact that dr is very close to zero, dr^2 can be approximated to 0 because it is way, way smaller by the same factor dr, which is already extremely small.

  • @mognokhan1701

    @mognokhan1701

    3 жыл бұрын

    Use a calculator. If r = 0.001 then r^2 = .000001 and so on and on. You can see that dr^2 will approach 0 within that limit.

  • @abdulsbadr
    @abdulsbadr5 ай бұрын

    How are you writing this ...I'm confused! Are you writing mirrored or flipping the image?

  • @final_motion

    @final_motion

    Ай бұрын

    Rotate 90 degree to left /right

  • @coderanger7708
    @coderanger77083 жыл бұрын

    Why should r be the integration variable, why can't m be the integration variable?

  • @LerAnd-hm9fe

    @LerAnd-hm9fe

    Ай бұрын

    Isn't the mass constant? Maybe that's why.

  • @kingk3302
    @kingk330211 ай бұрын

    The DM is the tricky part

  • @chirag9159
    @chirag91593 жыл бұрын

    This is wrong,,,Icm of disc is=MR^ 2/4

  • @kelvinadimas8851

    @kelvinadimas8851

    2 жыл бұрын

    no, its 1/2 mr^2

  • @Lucas-yh5zz

    @Lucas-yh5zz

    2 жыл бұрын

    i'm kinda late but 1/4 MR^2 are the momments of inertia tha correspond to the x and z axis that are parallel to the disc while 1/2 MR^2 is the momment of inertia of the y axis which is perpendicular to it

  • @theknight4460
    @theknight44603 жыл бұрын

    Thanks

  • @Alpha_10206
    @Alpha_10206 Жыл бұрын

    thanks