sir, pls do a video on Columns and Footings ❤️ I love all your videos, very well explained

Thank you sirr!! nahihirapan akong mag catch up sa lectures ng prof namin

@lecturesnisirmars

2 жыл бұрын

Thanks po.:)

Sir , why do you use 0.9 in reduction factor to get Mn when we use fs=800 it should need to calculate it since its in transition region

I finally arrived here, but Sir why did you stop uploading RCD videos? 😢

@lecturesnisirmars

4 ай бұрын

Nawalan po ng time as I was assigned with new responsibilities at work. Pero I’ll try to find some time to continue the lectures sa RCD.

Make more videos engr. Specially sa structural analysis kay maoy critical

Sir, will it be always 0.90 ang reduction factor sa Mu1? Pag ganitong approach?

Sir bakit po ang gamit ng iba to get the maximum values of the section as singly ay strain=0.004? sa inyo po at kay sir Gillesania ay 0.005?

Salamat engr. Diri rako nakasabot sa subject nga RCD kay detailed jud kung gi unsa pagkuha

Sir ask lang po, if magde-design po kami ng beam completely based on floor plan. Kami na rin po ba yung magse-set ng d' namin, or may code provisions/formula po para dito?

Sir Mars? Wala na po bang continuation ang playlist na ito? I mean, is this the last topic?

Sir meron po kayo video about portal method? Wait po namin yun video upload.. God bless you

Sir pano po pag hindi po nagyield compression steel?

sir what will happen if fs and fy is not equal?

@CristianRamirez-qk2fy

2 жыл бұрын

Compute the fs' pre using epsilone y= fs'/ES

Sir paki recompute po yung value ng A's na 2044.01 mm^2 kasi yung lumabas sa calculator ko po ay 2.04399×10^-3 Sir diba pag raise to negative ay magiging 0.0024399?

@siraykimwellq.5479

2 жыл бұрын

Convert mo yung Mn2 mo to N-mm

in reality po, gumagamit po ba talaga ng singly reinforced beams knowing na kailangan ng stirrups? Parang imposible po kasing mag lagay ng stirrups kugn walang top bars. or pwede po idesign as doubly kahit na lumabas ay singly lang sya?

@lecturesnisirmars

Жыл бұрын

This is a good question. Yes, in reality meron talagang Singly Reinforced na design. Pero kahit singly sya, which is supposed to be isang side lang ng beam ang meron reinforcement, required na maglagay ng hangers para kakabitan ng stirrups. Pero kahit may hangers, still “Singly” pa din ang tawag dun, kahit nagmukha na syang doubly. Regarding sa 2nd question mo. If singly ang lumabas, singly dapat ang design, kung doubly ang lumabas, doubly ang design. Hindi ka makakapagdesign ng doubly kung singly ang lumabas sa computation kasi it means the maximum moment can be carried by tension bars aloneZ

@lecturesnisirmars

Жыл бұрын

This is a good question. Yes, in reality meron talagang Singly Reinforced na design. Pero kahit singly sya, which is supposed to be isang side lang ng beam ang meron reinforcement, required na maglagay ng hangers para kakabitan ng stirrups. Pero kahit may hangers, still “Singly” pa din ang tawag dun, kahit nagmukha na syang doubly. Regarding sa 2nd question mo. If singly ang lumabas, singly dapat ang design, kung doubly ang lumabas, doubly ang design. Hindi ka makakapagdesign ng doubly kung singly ang lumabas sa computation kasi it means the maximum moment can be carried by tension bars alone.

@lecturesnisirmars

Жыл бұрын

This is a good question. Yes, in reality meron talagang Singly Reinforced na design. Pero kahit singly sya, which is supposed to be isang side lang ng beam ang meron reinforcement, required na maglagay ng hangers para kakabitan ng stirrups. Pero kahit may hangers, still “Singly” pa din ang tawag dun, kahit nagmukha na syang doubly. Regarding sa 2nd question mo. If singly ang lumabas, singly dapat ang design, kung doubly ang lumabas, doubly ang design. Hindi ka makakapagdesign ng doubly kung singly ang lumabas sa computation kasi it means the maximum moment can be carried by tension bars alone.

@mangoes7329

Жыл бұрын

@@lecturesnisirmars hindi na po ba sinasama sa computation yung hangers na nilalagay? if thats the case, may standard po ba ito?

@lecturesnisirmars

Жыл бұрын

@@mangoes7329 Hindi na kasama sa computation ung hangers. Bale 12 mm ang minimum nyan. Para sa akin, if ever maging singly reinforced yung beam mo, tapos let’s say 3 bars na 12 mm ang nasa tension side. Bale 5 lahat na 12 mm ang dapat na reinforcement, yung 3 sa tension at 2 sa compression na need for hangers. In other words, yung hangers can be considered main bars.