These would come from individual experiments where you are monitoring the rate of the reaction. For example, if you set up an experiment that monitors the absorbance of a product and plot it vs. time, the slope of that line would be related to the rate - if this is done under controlled conditions, that would be your V0
@hardikparmar2600Ай бұрын
How did you calculate the Vo. Please specify or make a video on that.
@isabelleheinken9762 ай бұрын
what about if its a mixed inhibitor? to calculate alpha can we use either the non-comp way or comp-way to finding the alpha?
@dr.g50432 ай бұрын
Yes, in a perfect scenario where alpha impacts Km and Vmax equally. I would expect this to be the case for most instances you'd see in a biochemistry course.
@ing.anthony70973 ай бұрын
Great video but wait! Why when we have several protons we take this into account, and when we have multiple electrons, we are only taking 1 electron (thats negative) resulting always in a negative potential energy? I dont know whats wrong and whats right but what i learned from this video is that the results will always be negative by that logic. Is this right?
@dr.g50432 ай бұрын
The idea is that we are trying to understand what variable impact the interaction between one electron and the nucleus. This is the foundational concept for understanding all of the periodic trends and essentially every basic concept that deals with the energy associated with electrons in an atom. We treat the nucleus as a single point charge with a charge of Z (The number of protons) and one electron as a single point charge (always a charge of -1). Things get much more complicated if you start thinking about multiple electrons. I hope that helps.
@ing.anthony70972 ай бұрын
@@dr.g5043Thank you for your reply! Yeah i see your point, but for the Helium case in the video you already represented 2 electrons but didnt take that into account in the equation. Why? Shouldnt it be (-2)? And my main question is, is the potential energy always negative? If we always have positive charge x negative charge, id assume that this would always be the case <0
@dr.g50432 ай бұрын
@@ing.anthony7097 Hi. It boils down to the idea that we are focused on one electron at a time - what is the energy that describes the interaction between one electron and the nucleus. Adding in more electrons is certainly possible and necessary as you move on in chemistry and physics, but the point of this video is to introduce the most basic aspects of understanding the simplest case scenario (one electron and the nucleus). Is the energy always negative? Yes, for the interaction between an electron and the nucleus because they have opposite charges, but it there is no limitation to the equation that the energy must be negative. For example, if you're investigating the interaction between two electrons, then q1 = -1 and q2 = -1, so the potential energy is positive.
@letumilechocho2313 ай бұрын
Does this mean that the approximation method is very wrong? Because the answers for Km and V max are very different
@dr.g50433 ай бұрын
Approximation is inherently flawed if your goal is to get a correct answer. However, it can be a very good guide in many instances. The dataset I show here intentionally creates a situation where the approximation is misleading because the dataset is not complete - the measured velocity does not approach Vmax. Consequently it is not possible to accurately estimate Vmax, which means the Km estimate is also flawed. Conversely, the Lineweaver-Burk approach also has some inherent issues that I don't discuss in this video which can result in incorrect Km and Vmax values.
@ryancordon58253 ай бұрын
Great explanation!
@AmruMagdy3 ай бұрын
Heptad Repeat 147hbb honey
@Its_InduB3 ай бұрын
how did you calculated experimental value of DF/DFmax?
@dr.g50433 ай бұрын
DF is the experimental value and DF max is the signal when it is fully saturated with ligand. So the Y-axis is a fraction of bound ligand.
@joeysegg74054 ай бұрын
thanks for filling in for my professor who does not show her work on her homework keys
@rassimsimou15946 ай бұрын
Good
@rassimsimou15946 ай бұрын
Good
@MR-backup7 ай бұрын
So I don't understand are Orders of Magnitude and Exponents the same or not? If so, then why do we use 2 different words for the same function? If not, then why do people use them as if they were?
@dr.g50437 ай бұрын
Good question and I'm not sure my explanation will be perfectly clear, but I'll try. Exponents can refer to any number raised to a power. Orders of magnitude specifically refers to power or 10. In the expression 2^3, the 3 is an exponent but not an order of magnitude. In the expression 2 x 10^3, 3 is still an exponent and 10^3 is an order of magnitude - three orders of magnitude (x 1000). I hope that helps.
@MR-backup6 ай бұрын
@@dr.g5043 It was perfectly clear. Appreciate it.
@isaackogan2697 ай бұрын
my hero
@izabelabzura17547 ай бұрын
Great video! Helps a lot
@dr.g50437 ай бұрын
Great to hear, thank you and I'm glad it helped!
@aaronfinnegan4338 ай бұрын
Great work Dr. G! You really showed those Lewis Symbols who’s boss! 😂😮😂
@Carol-qu4he8 ай бұрын
thanksbgod I found it🖤🖤
@Carol-qu4he8 ай бұрын
brilliant explanation🔥🔥🖤🖤🖤
@alagiyawannamukaweti44488 ай бұрын
Your teaching is very clear....thank u a lot..💙
@ionloghin21728 ай бұрын
ur amazing, ty ty ty!!!
@yosefouad21168 ай бұрын
god bless you thanks!
@sneha77248 ай бұрын
Thank you so much..
@dr.g50438 ай бұрын
glad it helped!
@marzenasemaj72049 ай бұрын
Biochemistry...I am comming
@Brooke_Jewell249 ай бұрын
Serine Protease has come back to haunt me yet again. Came back here because your explanation is better than the textbook! Thanks!
@deniedbwayi247710 ай бұрын
Question does the p value change if the concentration in water is made the numerator / octane denominator
@dr.g504310 ай бұрын
Yes, it will invert (1/p)
@alifkhan511110 ай бұрын
So, so helpful! Thank you so much!
@04akramkhan1411 ай бұрын
❤️🔥Partition ᴄᴏᴇꜰꜰɪᴄɪᴇɴᴛ❤️🔥 with experiment Pharmaceutical Statistics ᴀᴠᴀɪʟᴀʙʟᴇ ᴏɴ ᴅᴏᴄꜱɪᴛy 🔥🔥🔥🔥
@crazyblah86711 ай бұрын
Solid gold video. 4 years old and still helping students like it was uploaded 2 hours ago. Thank you a million times!
@user-ky3qk5xx1i Жыл бұрын
저 엑셀을 만드는 방법을 알 수 있을까요?
@boitory6372 Жыл бұрын
Thank you very much.... I clearly understood...
@laurensharp246 Жыл бұрын
Is this at pH 7?
@dr.g5043 Жыл бұрын
No, this would be the structure in an organic solvent or the solid phase where functional groups do not speciate. At pH 7, the amines would be protonated (NH3+) and the carboxylic acids would be deprotonated (COO-).
@boitory6372 Жыл бұрын
Wow... U explained what my lecture failed to explain in 2hrs
@mattdrivas7608 Жыл бұрын
Thanks!
@estherabass7389 Жыл бұрын
i love the backbone formula you provided, it made this so so much easier! thank you!!
@henkaipan8 Жыл бұрын
Neatly explained.
@noahfinn5931 Жыл бұрын
the GOAT
@shawnanderson4496 Жыл бұрын
Thank you SO much. Saved me hours of reading a text just to not get anywhere lol
@alirsh2699 Жыл бұрын
👌👌👌👌
@elserch727 Жыл бұрын
Thanks
@emilbom5196 Жыл бұрын
Thanks for clear explanation
@user-mi8ux5zo6w Жыл бұрын
I don't understand how KI is 6.9 for the competitive inhibitor?
@dr.g5043 Жыл бұрын
In this example, alpha was determined to be 2.45. So doing a little algebra: 1.45 = 10/Ki. --->. 10/1.45 = Ki = 6.9
Пікірлер
so great !
How did you calculate Vo ?
These would come from individual experiments where you are monitoring the rate of the reaction. For example, if you set up an experiment that monitors the absorbance of a product and plot it vs. time, the slope of that line would be related to the rate - if this is done under controlled conditions, that would be your V0
How did you calculate the Vo. Please specify or make a video on that.
what about if its a mixed inhibitor? to calculate alpha can we use either the non-comp way or comp-way to finding the alpha?
Yes, in a perfect scenario where alpha impacts Km and Vmax equally. I would expect this to be the case for most instances you'd see in a biochemistry course.
Great video but wait! Why when we have several protons we take this into account, and when we have multiple electrons, we are only taking 1 electron (thats negative) resulting always in a negative potential energy? I dont know whats wrong and whats right but what i learned from this video is that the results will always be negative by that logic. Is this right?
The idea is that we are trying to understand what variable impact the interaction between one electron and the nucleus. This is the foundational concept for understanding all of the periodic trends and essentially every basic concept that deals with the energy associated with electrons in an atom. We treat the nucleus as a single point charge with a charge of Z (The number of protons) and one electron as a single point charge (always a charge of -1). Things get much more complicated if you start thinking about multiple electrons. I hope that helps.
@@dr.g5043Thank you for your reply! Yeah i see your point, but for the Helium case in the video you already represented 2 electrons but didnt take that into account in the equation. Why? Shouldnt it be (-2)? And my main question is, is the potential energy always negative? If we always have positive charge x negative charge, id assume that this would always be the case <0
@@ing.anthony7097 Hi. It boils down to the idea that we are focused on one electron at a time - what is the energy that describes the interaction between one electron and the nucleus. Adding in more electrons is certainly possible and necessary as you move on in chemistry and physics, but the point of this video is to introduce the most basic aspects of understanding the simplest case scenario (one electron and the nucleus). Is the energy always negative? Yes, for the interaction between an electron and the nucleus because they have opposite charges, but it there is no limitation to the equation that the energy must be negative. For example, if you're investigating the interaction between two electrons, then q1 = -1 and q2 = -1, so the potential energy is positive.
Does this mean that the approximation method is very wrong? Because the answers for Km and V max are very different
Approximation is inherently flawed if your goal is to get a correct answer. However, it can be a very good guide in many instances. The dataset I show here intentionally creates a situation where the approximation is misleading because the dataset is not complete - the measured velocity does not approach Vmax. Consequently it is not possible to accurately estimate Vmax, which means the Km estimate is also flawed. Conversely, the Lineweaver-Burk approach also has some inherent issues that I don't discuss in this video which can result in incorrect Km and Vmax values.
Great explanation!
Heptad Repeat 147hbb honey
how did you calculated experimental value of DF/DFmax?
DF is the experimental value and DF max is the signal when it is fully saturated with ligand. So the Y-axis is a fraction of bound ligand.
thanks for filling in for my professor who does not show her work on her homework keys
Good
Good
So I don't understand are Orders of Magnitude and Exponents the same or not? If so, then why do we use 2 different words for the same function? If not, then why do people use them as if they were?
Good question and I'm not sure my explanation will be perfectly clear, but I'll try. Exponents can refer to any number raised to a power. Orders of magnitude specifically refers to power or 10. In the expression 2^3, the 3 is an exponent but not an order of magnitude. In the expression 2 x 10^3, 3 is still an exponent and 10^3 is an order of magnitude - three orders of magnitude (x 1000). I hope that helps.
@@dr.g5043 It was perfectly clear. Appreciate it.
my hero
Great video! Helps a lot
Great to hear, thank you and I'm glad it helped!
Great work Dr. G! You really showed those Lewis Symbols who’s boss! 😂😮😂
thanksbgod I found it🖤🖤
brilliant explanation🔥🔥🖤🖤🖤
Your teaching is very clear....thank u a lot..💙
ur amazing, ty ty ty!!!
god bless you thanks!
Thank you so much..
glad it helped!
Biochemistry...I am comming
Serine Protease has come back to haunt me yet again. Came back here because your explanation is better than the textbook! Thanks!
Question does the p value change if the concentration in water is made the numerator / octane denominator
Yes, it will invert (1/p)
So, so helpful! Thank you so much!
❤️🔥Partition ᴄᴏᴇꜰꜰɪᴄɪᴇɴᴛ❤️🔥 with experiment Pharmaceutical Statistics ᴀᴠᴀɪʟᴀʙʟᴇ ᴏɴ ᴅᴏᴄꜱɪᴛy 🔥🔥🔥🔥
Solid gold video. 4 years old and still helping students like it was uploaded 2 hours ago. Thank you a million times!
저 엑셀을 만드는 방법을 알 수 있을까요?
Thank you very much.... I clearly understood...
Is this at pH 7?
No, this would be the structure in an organic solvent or the solid phase where functional groups do not speciate. At pH 7, the amines would be protonated (NH3+) and the carboxylic acids would be deprotonated (COO-).
Wow... U explained what my lecture failed to explain in 2hrs
Thanks!
i love the backbone formula you provided, it made this so so much easier! thank you!!
Neatly explained.
the GOAT
Thank you SO much. Saved me hours of reading a text just to not get anywhere lol
👌👌👌👌
Thanks
Thanks for clear explanation
I don't understand how KI is 6.9 for the competitive inhibitor?
In this example, alpha was determined to be 2.45. So doing a little algebra: 1.45 = 10/Ki. --->. 10/1.45 = Ki = 6.9
understandable and helpful. thank you
Great tutorial! Very succinct
This was so helpful! Thank you so much.
Thankyou so much for a great video!
Nice explanation. Thank you. Subscribed.