I think this is much simpler: 2^a - 2^b = 2016 >>> 2^a - 2^b = 2048 - 32 >>> 2^a - 2^b = 2^11 - 2^5. Therefore a=11 and b=5. Simples!
@johnchastain789015 сағат бұрын
If you plug the two complex solutions into the original problem and cube them, won't you wind up with a leftover i ? How can a complex number equal a real number?
@user-it6rm7cx6x22 сағат бұрын
That is, the answer is "the decimal logarithm of the golden ratio"
@michael636336Күн бұрын
A=1 by inspection
@geralynpinto5971Күн бұрын
Thank you very much. I have subscribed
@anannayКүн бұрын
Will be easier to use (4100-7)×(4100-1) 16810000-28700-4100+7 16777207
@FatmaSaniya-oj9mwКүн бұрын
Veryvery helpful videosir🌷🌷🌷🌷🌷
@GillesF312 күн бұрын
Yes, and there was also one other way to get the 3 roots (in R and C) of this "small" equation: x³ = 3³ ³√(x³) = ³√(3³) x = ³√27 ■ x = 3 --- euclidean division --- • dividend: x³ = 3³ => x³ - 3³ = 0 => x³ + 0·x² + 0·x - 3³ = 0 • divisor: x = 3 => x - 3 = 0 (x³ + 0·x² + 0·x - 3³) / (x - 3) = (x² + 3x + 9) x² + 3x + 9 = 0 Δ = 3² - 4·1·9 = 9 - 36 = -27 √Δ = ±i√27 = ±3i√3 • root #1: x = (-3 + 3i√3)/2·1 = -3/2 + (3/2)i√3 = 3/2(i√3 - 1) • root #2: x = (-3 - 3i√3)/2·1 = -3/2 - (3/2)i√3 = -3/2(i√3 + 1) ■ x = 3/2(i√3 - 1) ■ x = -3/2(i√3 + 1) 🙂
@adelsadek66292 күн бұрын
😢Bade problem
@adelsadek66292 күн бұрын
😢Bade problem
@nikolayguzman3312 күн бұрын
Conversion to powers with base is fastest method to solve problem.
@roberthayter1572 күн бұрын
Really good, thank you
@doublestone12 күн бұрын
In R hat diese Gleichung genau 1 Lösung und das sieht man ohne viel Rechnerei.
@stefanopicozzi8812 күн бұрын
What about expressing 4 = 2^2 and 8 = 2^3, which gives you, for the leftmost term (2^2)^8 / (2^3)^4 = 2^16 / 2^12 = 2^4 = 16. Then, the 2ns term is obviously the inverse of the first one, which immediately give 16 - 1/16 Seems a more straightforward start to me ... but that may be only me ;)
@PakMaths2 күн бұрын
That's also an approach......❣️❣️
@stefanopicozzi8812 күн бұрын
@@PakMaths That said (I should have ended my post this way), thx for this kind of contents breaking out computations into small, easily understandable steps ... as a math teacher I am well aware of how useful this is (and for having trie, and given up, I am well aware of how time consuming doing such a video is) <3
@aryabhattagamharia55862 күн бұрын
Very Very nice explanation sir 🎉🎉🎉🎉🎉
@jagadiswarchakraborty295Күн бұрын
Well done
@aryabhattagamharia55863 күн бұрын
Fantastic video sir 🎉🎉🎉🎉🎉
@istekharansari10643 күн бұрын
very very nice exponential equation sir🎉🎉🎉🎉🎉
@chittella13 күн бұрын
Feel a long process. Instead, we can derive the given equation to 81^3-81, and 81^3 is 531441, and here is your answer 531360.
@syedmdabid71913 күн бұрын
Id est 1,responsi.
@biswanathbera12604 күн бұрын
Can be done more easily by multiplying 1024^2×32-1.
@user-qp1ui4jk4r4 күн бұрын
Автор видео, наверное, не изучал геометрическую прогрессию. Приглашаем в 8-й класс нашей школы!
@jagadiswarchakraborty2954 күн бұрын
Well done
@mariuszluczkiewicz12324 күн бұрын
And what would it be like if we applied both sides of the equation to the power eπ - it should be a very interesting and simple solution to this complicated problem.
@istekharansari10644 күн бұрын
Very very nice exponential equation sir 🎉🎉🎉🎉🎉
@amitavadasgupta69854 күн бұрын
x^2+2x+5=0 give complex and no real.
@amitavadasgupta69854 күн бұрын
a=1
@sushmaagarwal68044 күн бұрын
.a,s cost is 15 ❤❤❤❤❤
@TheKnowledgeOfScience5 күн бұрын
Super 🎉
@aryabhattagamharia55865 күн бұрын
Very Very useful video sir 🎉🎉🎉🎉🎉
@user-nx9wy5sh9w5 күн бұрын
無聊
@user-qy8re3yx3d5 күн бұрын
Сумма геометрической прогрессии. 66429.
@subasu4785 күн бұрын
1
@nikolayguzman3315 күн бұрын
IF 3^3 >0 Therefore K^3 >0 and K>0 What Kind is K? If K is Natural number (N), than K^3 = 3# | x^ 1/3 K=3; If K is Real number (R) then K^3-3^3=0 ...
@RealQuInnMallory5 күн бұрын
(k➖ 3k+1)
@ismail-dz98355 күн бұрын
just a question: If K^3=3^3 why you didn't use: if X^A=Y^A then X = Y why you prove it from the zero
@mariuszluczkiewicz12324 күн бұрын
Because any simple problem can be so entangled that it becomes unsolvable. Example above.
@gnanadesikansenthilnathan67505 күн бұрын
A simple nice problem
@fredsalter19155 күн бұрын
Logarithms rule!!!!!!
@sivaniray98095 күн бұрын
Those who know long a d how to see the log table can solve the problem easily. My question is do the modern students learn how to use log table?
@thebrazilian1276 күн бұрын
Sum of a finite number of terms of a geometric sequence
@pjaj436 күн бұрын
If you must do it that way then 45 = 3^2*5 divide both sides by 3^2 Then 3^(a-2) = 5 (a-2)log3 = log5 a=2+log5/log3
@pjaj436 күн бұрын
Interesting alternative method Let answer be x and square both sides x^2 = (4+sqrt(8))/(4-sqrt(8)) multiply top and bottom by (4+sqrt(8)) x^2 = ((4+sqrt(8))^2)/(16-8) x^2 = (16+8+8sqrt(8))/8 x^2 = 3+sqrt(8) x = sqrt(3+sqrt(8)) which surprisingly evaluates to the same result (1 + sqrt(2)) even though it looks nothing like it.
@kaliprasadguru19216 күн бұрын
Instead of going in for quadratic equation , use formula (a-b)²= (a+b)²-4ab to find out a-b. . We know a,+b .we knew a-b . From this a and b can be determined .
@istekharansari10646 күн бұрын
very very nice problem sir 🎉🎉🎉🎉🎉
@user-ts9kq4vn2u6 күн бұрын
Result may be presented in form 9(9^5-1)/8
@RRRSSS11117 күн бұрын
1
@robertloveless49387 күн бұрын
You could drive west across the city to get a McRib. OR you could drive east 1 block and get a McRib. THIS PARTICULAR SOLUTION was the drive across town option. JUST MULTIPLY IT OUT. Because each product is the factor of the next multiplication problem, it takes less time with pencil and paper than jumping through math hoops.
@lawrencejelsma81182 күн бұрын
Or what is the purpose of any type of calculator with exponent functions. The whole reason to design such a technological serving device is to compute a simple addition of exponents like this for doing your "by hand calculating" without using a calculator. As I watched this video on a computer interface my computer interface has a built in calculator with the exponent function capabilities.
@nucki2227 күн бұрын
a = ln(45) / ln(5)
@aryabhattagamharia55867 күн бұрын
X³-8 +x-2 =0
@PakMaths7 күн бұрын
Yes, this is another way to solve this Problem........
Пікірлер
I liked your teaching method
Thanks, Pak,
I think this is much simpler: 2^a - 2^b = 2016 >>> 2^a - 2^b = 2048 - 32 >>> 2^a - 2^b = 2^11 - 2^5. Therefore a=11 and b=5. Simples!
If you plug the two complex solutions into the original problem and cube them, won't you wind up with a leftover i ? How can a complex number equal a real number?
That is, the answer is "the decimal logarithm of the golden ratio"
A=1 by inspection
Thank you very much. I have subscribed
Will be easier to use (4100-7)×(4100-1) 16810000-28700-4100+7 16777207
Veryvery helpful videosir🌷🌷🌷🌷🌷
Yes, and there was also one other way to get the 3 roots (in R and C) of this "small" equation: x³ = 3³ ³√(x³) = ³√(3³) x = ³√27 ■ x = 3 --- euclidean division --- • dividend: x³ = 3³ => x³ - 3³ = 0 => x³ + 0·x² + 0·x - 3³ = 0 • divisor: x = 3 => x - 3 = 0 (x³ + 0·x² + 0·x - 3³) / (x - 3) = (x² + 3x + 9) x² + 3x + 9 = 0 Δ = 3² - 4·1·9 = 9 - 36 = -27 √Δ = ±i√27 = ±3i√3 • root #1: x = (-3 + 3i√3)/2·1 = -3/2 + (3/2)i√3 = 3/2(i√3 - 1) • root #2: x = (-3 - 3i√3)/2·1 = -3/2 - (3/2)i√3 = -3/2(i√3 + 1) ■ x = 3/2(i√3 - 1) ■ x = -3/2(i√3 + 1) 🙂
😢Bade problem
😢Bade problem
Conversion to powers with base is fastest method to solve problem.
Really good, thank you
In R hat diese Gleichung genau 1 Lösung und das sieht man ohne viel Rechnerei.
What about expressing 4 = 2^2 and 8 = 2^3, which gives you, for the leftmost term (2^2)^8 / (2^3)^4 = 2^16 / 2^12 = 2^4 = 16. Then, the 2ns term is obviously the inverse of the first one, which immediately give 16 - 1/16 Seems a more straightforward start to me ... but that may be only me ;)
That's also an approach......❣️❣️
@@PakMaths That said (I should have ended my post this way), thx for this kind of contents breaking out computations into small, easily understandable steps ... as a math teacher I am well aware of how useful this is (and for having trie, and given up, I am well aware of how time consuming doing such a video is) <3
Very Very nice explanation sir 🎉🎉🎉🎉🎉
Well done
Fantastic video sir 🎉🎉🎉🎉🎉
very very nice exponential equation sir🎉🎉🎉🎉🎉
Feel a long process. Instead, we can derive the given equation to 81^3-81, and 81^3 is 531441, and here is your answer 531360.
Id est 1,responsi.
Can be done more easily by multiplying 1024^2×32-1.
Автор видео, наверное, не изучал геометрическую прогрессию. Приглашаем в 8-й класс нашей школы!
Well done
And what would it be like if we applied both sides of the equation to the power eπ - it should be a very interesting and simple solution to this complicated problem.
Very very nice exponential equation sir 🎉🎉🎉🎉🎉
x^2+2x+5=0 give complex and no real.
a=1
.a,s cost is 15 ❤❤❤❤❤
Super 🎉
Very Very useful video sir 🎉🎉🎉🎉🎉
無聊
Сумма геометрической прогрессии. 66429.
1
IF 3^3 >0 Therefore K^3 >0 and K>0 What Kind is K? If K is Natural number (N), than K^3 = 3# | x^ 1/3 K=3; If K is Real number (R) then K^3-3^3=0 ...
(k➖ 3k+1)
just a question: If K^3=3^3 why you didn't use: if X^A=Y^A then X = Y why you prove it from the zero
Because any simple problem can be so entangled that it becomes unsolvable. Example above.
A simple nice problem
Logarithms rule!!!!!!
Those who know long a d how to see the log table can solve the problem easily. My question is do the modern students learn how to use log table?
Sum of a finite number of terms of a geometric sequence
If you must do it that way then 45 = 3^2*5 divide both sides by 3^2 Then 3^(a-2) = 5 (a-2)log3 = log5 a=2+log5/log3
Interesting alternative method Let answer be x and square both sides x^2 = (4+sqrt(8))/(4-sqrt(8)) multiply top and bottom by (4+sqrt(8)) x^2 = ((4+sqrt(8))^2)/(16-8) x^2 = (16+8+8sqrt(8))/8 x^2 = 3+sqrt(8) x = sqrt(3+sqrt(8)) which surprisingly evaluates to the same result (1 + sqrt(2)) even though it looks nothing like it.
Instead of going in for quadratic equation , use formula (a-b)²= (a+b)²-4ab to find out a-b. . We know a,+b .we knew a-b . From this a and b can be determined .
very very nice problem sir 🎉🎉🎉🎉🎉
Result may be presented in form 9(9^5-1)/8
1
You could drive west across the city to get a McRib. OR you could drive east 1 block and get a McRib. THIS PARTICULAR SOLUTION was the drive across town option. JUST MULTIPLY IT OUT. Because each product is the factor of the next multiplication problem, it takes less time with pencil and paper than jumping through math hoops.
Or what is the purpose of any type of calculator with exponent functions. The whole reason to design such a technological serving device is to compute a simple addition of exponents like this for doing your "by hand calculating" without using a calculator. As I watched this video on a computer interface my computer interface has a built in calculator with the exponent function capabilities.
a = ln(45) / ln(5)
X³-8 +x-2 =0
Yes, this is another way to solve this Problem........
Very Very nice exponential equation sir 🎉🎉🎉🎉🎉