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thanks bhaiya
thanks for the video
I had watched all the time complexity videos but did'nt able to understand, then here i found a gem named babbar sher. So much love for u man. Just keep educating us, you'r an inspiration for us.❤❤🩹❤❤❤
completed this lectures ,
bhot mza aa rha h
Started 16/07/2024
Can anyone tell me what bool h
done on 17 July 2159
❤
Thank you bhayia ji,lots of love
1:04:45
Thankyou sir we loved it!!!
Started 15/07/24
The best teacher , the best guide Thanks a lot sir !!!
easy-peasy
4th vdo for today .. trying to complete this series 48 vdos left in 9 days as after that placement is starting
sir eska code kaha hai jo link hai usma bass tree tk ka hi code haii graph aur bakki lecture ka code ka link kaha hai
swad aa gya bhai :)
int arr[100]; int size; cout << "enter the size of array" << endl; cin>>size; cout << "enter the values in array" << " "; for(int i=0;i<size;i++) { cin>>arr[i]; } for(int i=0;i<size;i++) { int temp; if(i%2==0 && i+1<size) temp=arr[i+1]; arr[i+1]=arr[i]; arr[i]=temp; } for(int i=0;i<size;i++) { cout <<"after swapping :"<<arr[i]<<endl; } return 0; } I/p:12345 O/p:22444 what's wrong in this program?
2343 comments ho gaye 🤝 🥳
🙏🏻
10:49:06 Understood++ Completed whole CSS Alhumdulillah.Thank you sooo much a brother like instructor you are the BEST on whole YoutTube I have learnt alot in this video ♥
Great podcast thank u
sir es lecture ke handwritten notes kaha milenge ?
Started Today: 16th July 2024 🎉
Master Blaster sir Maza agya
sie maja aa gaya one video me sab hai
approach 2 leetcode pr TLE maar rhi
fantastric series i still have to do more question but it was fantastic
1:08:09 he mentions output questions on the screen, but they don't appear, right?
Not Working For S = 10, N = 9, M = 8. Great Video
❤❤❤
a=[1,3,4,5,34,54,345,45,86] n=0 for i in range(len(a)): if a[i]>n: n=a[i] else: pass print(n) for finding max value we can use max function but this just for logic building purpose
start: 6:14PM 7/16/2024
Thank you bhaiya
you are good as rajbhoj for me
Solution: void dfs(int node, unordered_map<int, bool> &visited, unordered_map<int, set<int>> &adj, vector<int> &component) { component.push_back(node); visited[node] = 1; for (auto i : adj[node]) { if (!visited[i]) { dfs(i, visited, adj, component); } } } vector<vector<int>> depthFirstSearch(int V, int E, vector<vector<int>> &edges) { unordered_map<int, set<int>> adj; for (int i = 0; i < edges.size(); i++) { int u = edges[i][0]; int v = edges[i][1]; adj[u].insert(v); adj[v].insert(u); } vector<vector<int>> ans; unordered_map<int, bool> visited; for (int i = 0; i < V; i++) { if (!visited[i]) { vector<int> component; dfs(i, visited, adj, component); ans.push_back(component); } } return ans; }
Maaza agaya bhaiyya
Thank you ❤ se
Thanks for the course it was great learning , thank you from the bottom of the heart
Handwritten wala link Kam Nehi kar rah fix kardo usko
47:00
25:27 HW CODE char ch; cout<<"enter the character to be characterized:"; cin>> ch; if(ch>='A'&&ch<='Z' ){ cout<<"the upper case value is"<< ch<<endl; } else if(ch>='a'&& ch<='z'){ cout<<"lower case"; } else if (ch>= '0'&& ch<='9'){ cout<<"numerical value"; } else{ cout<<"try again"; }
lovely
15:35
understood++
00:01 Introduction to functions and their importance in code efficiency 02:11 Function in JavaScript performs a specific task 05:19 Functions are essential for code readability and reusability. 07:07 Defining and using functions in JavaScript 10:58 Understanding Function Parameters and Arguments in JavaScript 12:57 Explanation of return functions in JavaScript 16:51 Understanding the importance of calling a function in JavaScript 18:44 Explanation of working of a function in JavaScript 22:03 Explaining function declaration and expression in JavaScript 23:37 Usage of arrow functions for returning values in JavaScript 26:55 Introduction to Arrow Functions in ES6 28:52 Understanding arrow function definition in JavaScript
.rightBox per hover kerne se transform property only .overlay per apply ho rhi h, image per nhi ..plz reply kya kru mai🙏🙏🤔🙄🙄😮💨
I am missing that, which part of code is handling that, we could not reach to (n-1, n-1), how will it return then ???