Пікірлер

• 
  @MirubKhalid6 сағат бұрын

  Q:12 ka option b hai kia 11 electrons

• 
  @MuhammadAli-dy6kj10 күн бұрын

  How to make this type of video? Means background music 🎶 Please guide me, m interested

• 
  @studyRoom319 күн бұрын

  I am a teacher so I look at the book for questions like this

• 
  @MuhammadAli-dy6kj9 күн бұрын

  @@studyRoom31 great job, but I asking about the video editing tools.

• 
  @studyRoom319 күн бұрын

  @@MuhammadAli-dy6kj Yeah, it requires an app and that app is called (Kine Master)

• 
  @MuhammadAli-dy6kj9 күн бұрын

  @@studyRoom31 okay thanks

• 
  @studyRoom319 күн бұрын

  @@MuhammadAli-dy6kj triple tanx

• 
  @MuhammadAli-dy6kj10 күн бұрын

  Wow, it's very important MCQ'S. Thanks for sharing with us.

• 
  @studyRoom319 күн бұрын

  Much love 💞

• 
  @maheshb150912 күн бұрын

  Sir 12 quastio 10 worng correct anwsar 2m,/ss

• 
  @studyRoom3112 күн бұрын

  ♥️

• 
  @vishakhapathania286414 күн бұрын

  Nice pyq 👍👍

• 
  @studyRoom3114 күн бұрын

  ♥️♥️♥️

• 
  @shakeelahmedjunejo752218 күн бұрын

  12 A

• 
  @studyRoom3118 күн бұрын

  ♥️

• 
  @SajidNaeem-md3ob21 күн бұрын

  Best video ❤

• 
  @studyRoom3121 күн бұрын

  Thank you ♥️

• 
  @Haroon_khan_27822 күн бұрын

  First comment 😋🤤

• 
  @studyRoom3122 күн бұрын

  ♥️

• 
  @Haroon_khan_27822 күн бұрын

  All the best

• 
  @studyRoom3122 күн бұрын

  ♥️

• 
  @shoaibshakirkohistani406324 күн бұрын

  12 Quistion Ans is wronG its Ans is 2m/s

• 
  @studyRoom3124 күн бұрын

  ♥️

• 
  @Haroon_khan_27825 күн бұрын

  🎉🎉🎉🎉🎉🎉🎉

• 
  @studyRoom3124 күн бұрын

  ♥️

• 
  @Haroon_khan_27825 күн бұрын

  Thanks

• 
  @studyRoom3124 күн бұрын

  ♥️

• 
  @amir-u7v29 күн бұрын

  Q3 b&c

• 
  @studyRoom3129 күн бұрын

  🌻

• 
  @RasmitaMania-o5uАй бұрын

  12 no answer 2m/s²

• 
  @studyRoom31Ай бұрын

  🌻

• 
  @IlyasKhan-bd7gvАй бұрын

  F=10 Nm=5 kg2 lines; Line 1: cap F equals 10 space N; Line 2: m equals 5 space kg end-lines; 𝐹=10 N𝑚=5 kg Plug-in values  10 N=5 kg⋅a10 space N equals 5 space kg center dot a 10 N=5 kg⋅𝑎 Divide both sides by the same factor  10 N5 kg=5 kg⋅a5 kgthe fraction with numerator 10 space N and denominator 5 space kg end-fraction equals the fraction with numerator 5 space kg center dot a and denominator 5 space kg end-fraction 10 N𝟓 kg=5 kg⋅𝑎𝟓 kg Simplify  a=2 N/kga equals 2 space N / kg 𝑎=2 N/kg Convert units  a=2 m/s2a equals 2 space m / s squared 𝑎=2 m/s2

• 
  @studyRoom31Ай бұрын

  ❤️❤️❤️

• 
  @user-gp5ov5dd2jАй бұрын

  Nice one but zinc is also a transition metal

• 
  @studyRoom31Ай бұрын

  🌻

• 
  @FatimaBashir-r4sАй бұрын

  Least count of Vernier calliper is 0.1mm

• 
  @studyRoom31Ай бұрын

  🌻

• 
  @Aman_tv22Ай бұрын

  Sorry sir Question no 12 correct answer option A

• 
  @studyRoom31Ай бұрын

  Yeah, I understand

• 
  @user-hu3wi7fe1gАй бұрын

  kzread.info/dash/bejne/nH2VwbV9gc63ZLQ.htmlsi=qmH2AvqEdN7dgmNT

• 
  @wordsinpaperjournaljournalАй бұрын

  Q12 explanation??

• 
  @studyRoom31Ай бұрын

  The percentage error in a measurement quantifies how much the measured value deviates from the true value, expressed as a percentage of the true value. The formula to calculate the percentage error is: Percentage Error=(∣True Value−Measured Value∣True Value)×100\text{Percentage Error} = \left( \frac{|\text{True Value} - \text{Measured Value}|}{\text{True Value}} ight) \times 100Percentage Error=(True Value∣True Value−Measured Value∣)×100 Given: True Value = 2.60 m Measured Value = 2.58 m Let's plug these values into the formula: Percentage Error=(∣2.60−2.58∣2.60)×100\text{Percentage Error} = \left( \frac{|2.60 - 2.58|}{2.60} ight) \times 100Percentage Error=(2.60∣2.60−2.58∣)×100 First, find the absolute difference:

• 
  @studyRoom31Ай бұрын

  @@wordsinpaperjournaljournal 2.60−2.58∣=0.02|2.60 - 2.58| = 0.02∣2.60−2.58∣=0.02 Next, divide this difference by the true value: 0.022.60≈0.007692\frac{0.02}{2.60} \approx 0.0076922.600.02≈0.007692 Finally, multiply by 100 to get the percentage: 0.007692×100≈0.76920.007692 \times 100 \approx 0.76920.007692×100≈0.7692 So, the percentage error is approximately: Percentage Error≈0.77%\text{Percentage Error} \approx 0.77\%Percentage Error≈0.77%

• 
  @wordsinpaperjournaljournalАй бұрын

  Left ventricle

• 
  @studyRoom31Ай бұрын

  Correct ✅

• 
  @johnsonworldwings7899Ай бұрын

  Very good

• 
  @studyRoom31Ай бұрын

  Much love ❤️

• 
  @vidhimishra-dy4rgАй бұрын

  20 k a hoga

• 
  @studyRoom31Ай бұрын

  Determine the net displacement direction and distance: Moving 10 meters north is a positive displacement in the north direction. Moving 5 meters south is a negative displacement in the north direction. Calculate the net displacement: Net displacement = 10   meters north − 5   meters south = 5   meters north Net displacement=10meters north−5meters south=5meters north Magnitude of the displacement: The magnitude of the displacement is the absolute value of the net displacement. Magnitude of displacement = ∣ 5   meters ∣ = 5   meters Magnitude of displacement=∣5meters∣=5meters Thus, the magnitude of the displacement is 5 meters.

• 
  @studyRoom31Ай бұрын

  Correct answer option A

• 
  @mushtaqali5981Ай бұрын

  Nice mcq

• 
  @studyRoom31Ай бұрын

  🌻

• 
  @syedsaliman2195Ай бұрын

  Q12 is also wrong

• 
  @studyRoom31Ай бұрын

  Yeah sure.It is the correct answer option A

• 
  @syedsaliman2195Ай бұрын

  Question 9 you discuss speed and acceleration not centripetal acceleration

• 
  @studyRoom31Ай бұрын

  I am so sorry Brother, I don't understand what you are talking about, explain to me a little so that I can answer you.

• 
  @syedsaliman2195Ай бұрын

  @@studyRoom31 sir g my question is that in your question is confusion b/c you talking about the speed and acceleration not centrepetal acceleration plz don`t mind and check your answer

• 
  @studyRoom3117 күн бұрын

  @@syedsaliman2195 Acceleration is defined as the rate of change of velocity with respect to time. Velocity includes both speed and direction. If an object is moving at a constant speed, its speed does not change. However, for the object to have zero acceleration, its direction must also remain constant. Thus, when an object moves at a constant speed in a straight line (constant velocity), there is no change in its velocity, and hence its acceleration is zero. In summary: Constant speed implies no change in the magnitude of velocity. For acceleration to be zero, the direction must also be constant. Therefore, constant speed in a straight line results in zero acceleration.

• 
  @nandinipowerstar9981Ай бұрын

  Nice thanks❤

• 
  @studyRoom31Ай бұрын

  🌻

• 
  @Sneha_roy123Ай бұрын

  Thankuuu sir 🙏 its nice ....nd very gud for basics 👌 😊

• 
  @studyRoom31Ай бұрын

  🌻

• 
  @yashyash7376Ай бұрын

  Sir ye ocet k liye bhi h kya?

• 
  @DatttrayАй бұрын

  Nice 😊 question

• 
  @studyRoom31Ай бұрын

  🌻

• 
  @sonu_birthlia.Ай бұрын

  Ans.of 12th qus. Wrong 2m/ss is correct

• 
  @studyRoom31Ай бұрын

  Yeah sure! To determine the acceleration of an object when a force is applied, you can use Newton's second law of motion, which is given by the formula: F=ma F=ma where: F F is the force applied, m m is the mass of the object, a a is the acceleration of the object. Given: Force F=10 N F=10N Mass m = 5 kg m=5kg We need to find the acceleration a a. Rearranging the formula to solve for a α: a=Fm α = m F Substituting the given values: a=10 N5 kg α = 5kg 10N a=2 m/s2 a=2m/s 2 So, the acceleration of the object is 2 m/s2 2m/s 2

• 
  @MuhammadUmair-mq1koАй бұрын

  Thank you😊😊❤

• 
  @studyRoom31Ай бұрын

  🌻

• 
  @AhmadUmerL552 ай бұрын

  All is well sir ❤❤❤batameez student kabhi kamiab ni hotay

• 
  @studyRoom312 ай бұрын

  Much love 💓

• 
  @asiaKhan-us9ls2 ай бұрын

  Es trah ky channel monitize hoty hn????

• 
  @studyRoom312 ай бұрын

  I don't know

• 
  @ghulamfareedrajperghulamfa12922 ай бұрын

  12 me a Hoga

• 
  @studyRoom312 ай бұрын

  Yeah sure!To determine the acceleration of an object when a force is applied, you can use Newton's second law of motion, which is given by the formula: 𝐹=𝑚𝑎 F=ma where: 𝐹 F is the force applied, 𝑚 m is the mass of the object, 𝑎 a is the acceleration of the object. Given: Force 𝐹=10 N F=10N Mass 𝑚=5 kg m=5kg We need to find the acceleration 𝑎 a. Rearranging the formula to solve for 𝑎 a: 𝑎=𝐹𝑚 a= m F Substituting the given values: 𝑎=10 N5 kg a= 5kg 10N 𝑎=2 m/s2 a=2m/s 2 So, the acceleration of the object is 2 m/s2 2m/s 2 .

• 
  @GfhfhgKhan2 ай бұрын

  Nice Mcqs sir/m

• 
  @studyRoom312 ай бұрын

  🌻

• 
  @AmeenKhan-xm2cw2 ай бұрын

  Sir All is well so always be happy

• 
  @studyRoom312 ай бұрын

  🌻

• 
  @user-og1sl5qf1c2 ай бұрын

  answer are wrong

• 
  @studyRoom312 ай бұрын

  Which answer is wrong tell me to see the book quickly?

• 
  @sonu_birthlia.Ай бұрын

  Ans.of 12th qus. Wrong 2m/ss is correct

• 
  @sugirthavathana7192 ай бұрын

  With voice wanted sir/madam

• 
  @studyRoom31Ай бұрын

  Ok

• 
  @Munazahaneef2 ай бұрын

  Question 23 need correction

• 
  @studyRoom312 ай бұрын

  Without a list of properties provided, I'll just list some common properties of metals, and you can let me know if any of them need corrections or if you have a specific list in mind. Conductivity (electrical and thermal) Ductility Malleability Lustre (shininess) High melting and boiling points High density Reactivity with acids Metallic bonding

• 
  @Munazahaneef2 ай бұрын

  @@studyRoom31 ok

• 
  @Munazahaneef2 ай бұрын

  Some metals show brittle characteristics due to their slip systems. The more slip systems a metal has, the less brittle it is, because plastic deformation can occur along many of these slip systems.

• 
  @AmirKhan-re1jm2 ай бұрын

  I think left Atrium

• 
  @HamdanKhan-ii2wl2 ай бұрын

  Thank U for your help

• 
  @studyRoom31Ай бұрын

  Triple tnx

• 
  @Aman_tv222 ай бұрын

  I think Third law

• 
  @studyRoom312 ай бұрын

  Wrong

• 
  @wordsinpaperjournaljournalАй бұрын

  @@studyRoom312nd law

• 
  @AmeenKhan-xm2cw3 ай бұрын

  So very fantastic

• 
  @studyRoom31Ай бұрын

  🌻