Olá. Inscreva-se no canal do Professor Paulo Flores (•◡•)
Este canal destina-se aos seus estudantes de Engenharia Mecânica e Biomédica, que são uma permanente e inesgotável fonte de aprendizagem, onde, com humildade e diligência, procura saber inspirar-se todos os dias.
Nasceu em Rossas - Vieira do Minho a 19 de dezembro de 1972. Obteve a Licenciatura em Engenharia Mecânica pela Universidade do Minho (1997), seguida de Provas Científico-Pedagógicas (2000), Doutoramento (2005) e Agregação (2011). Em 2009 concluiu um pós-doutoramento no Instituto Federal de Tecnologia da Suíça (ETH-Zurique), e em 2012 foi Professor Visitante na Universidade do Arizona (EUA).
Trabalha na Universidade do Minho desde 1995, sendo Professor Catedrático (2013) do Departamento de Engenharia Mecânica e investigador do Centro de Microssistemas Eletromecânicos (CMEMS). Recebeu prémios científicos em vários países e é (co)autor de mais de meio milhar de publicações científicas, técnicas e pedagógicas.
Пікірлер
😁 Resolução das Equações do Movimento: kzread.info/dash/bejne/ZWehu8FuqLa4edo.html
😁 Equações do Movimento: kzread.info/dash/bejne/aJ-FlLxqetPUdpM.html
😁 Newton e Euler - Vida e Obra: kzread.info/dash/bejne/gqh5us2ypJyuncY.html
😁 Terceira Lei de Newton - Lei da Ação e Reação: kzread.info/dash/bejne/rJNky6OqZLutkbg.html
😁 Segunda Lei de Newton - Lei Fundamental da Dinâmica: kzread.info/dash/bejne/rGeYlbqCZM6TibQ.html
😁 Primeira Lei de Newton - Lei de Inércia: kzread.info/dash/bejne/ZGGmu8p-ebDcoco.html
😁 Embriogénese da Dinâmica de Sistemas Multicorpo: kzread.info/dash/bejne/ZY2Dp5OaoaTMfdY.html
😁 Análise Dinâmica de Sistemas Mecânicos: kzread.info/dash/bejne/l4ya2dGdnrKcnMY.html
😁 Apollo 15 - Astronaut David Scott recreated Galileo’s experiment with a hammer and a falcon feather: kzread.info/dash/bejne/f2ejqdWtnsmZXdY.html
😁 Newton's 1st Law of Motion: kzread.info/dash/bejne/poN8ssyaqra8m9Y.html 😁 Newton's 2nd Law of Motion: kzread.info/dash/bejne/l3mWpcx_Y6jOnLg.html
😁 Newton's 1st Law of Motion: kzread.info/dash/bejne/poN8ssyaqra8m9Y.html 😁 Newton's 3rd Law of Motion: kzread.info/dash/bejne/aWqK16xmkq-Zk5s.html
😁 Newton's 2nd Law of Motion: kzread.info/dash/bejne/l3mWpcx_Y6jOnLg.html 😁 Newton's 3rd Law of Motion: kzread.info/dash/bejne/aWqK16xmkq-Zk5s.html
Aula muito completa e muito bem elucidativa.
Muito obrigado.
Grande flash ... :)
Obrigado.
PARABÉNS João pela excelente prova!!!
Sem dúvida. Obrigado.
for a rolling object, with mass m, descending a ramp with inclination teta, the linear acceleration is given by the following expression: a = (m*g*sin(teta)) / (m+(I/r^2)) where I denotes the rotational inertia or mass moment of inertia at the center of mass, and r is the radius below are the mass moment of inertia for several rolling objects: 1. Solid Sphere: 2/5 *m*r^2 2. Hollow Sphere: 2/3 *m*r^2 3. Solid Cylinder: 1/2 *m*r^2 4. Hollow Cylinder: m*r^2 thus, corresponding accelerations are: 1. Solid Sphere: a = 5/7*g*sin(teta) 2. Hollow Sphere: a = 3/5*g*sin(teta) 3. Solid Cylinder: a = 2/3*g*sin(teta) 4. Hollow Cylinder: a = 1/2*g*sin(teta) hence, in a race between these 4 rolling objects down in an inclined plane the results are: 1st place: Solid Sphere 2nd place: Solid Cylinder 3rd place: Hollow Sphere 4th place: Hollow Cylinder See demonstrative video of this race in the following link (instant of time 55min 05sec): kzread.info/dash/bejne/l4ya2dGdnrKcnMY.html
Nice and complete description. Thanks 🙂
@@JunFetao Many thanks.
Grande prova! Parabéns João.
Obrigado 😃
this is a very important experiment, and it tells the diameter does not affect the acceleration of the cylinder rolling down on the slope.
Many thanks.
The acceleration can be expressed as follows: a = (2/3) g sin (teta)
for a rolling object, with mass m, descending a ramp with inclination teta, the linear acceleration is given by the following expression: a = (m*g*sin(teta)) / (m+(I/r^2)) where I denotes the rotational inertia or mass moment of inertia at the center of mass, and r is the radius below are the mass moment of inertia for several rolling objects: 1. Solid Sphere: 2/5 *m*r^2 2. Hollow Sphere: 2/3 *m*r^2 3. Solid Cylinder: 1/2 *m*r^2 4. Hollow Cylinder: m*r^2 thus, corresponding accelerations are: 1. Solid Sphere: a = 5/7*g*sin(teta) 2. Hollow Sphere: a = 3/5*g*sin(teta) 3. Solid Cylinder: a = 2/3*g*sin(teta) 4. Hollow Cylinder: a = 1/2*g*sin(teta) hence, in a race between these 4 rolling objects down in an inclined plane the results are: 1st place: Solid Sphere 2nd place: Solid Cylinder 3rd place: Hollow Sphere 4th place: Hollow Cylinder See demonstrative video of this race in the following link (instant of time 55min 05sec): kzread.info/dash/bejne/l4ya2dGdnrKcnMY.html
@@ProfessorPauloFlores I appreciate for your detailed and informative complements, Dear professor.
@@exlife9446 You are welcome.
Grande jornada!!!
Muito obrigado.
Parabéns ao grupo vencedor da "Prova de Rapidez". Grande prova a do João Fernandes. :)
Parabéns a Todos!
Muitos Parabéns ao João.
@@FernandoFonseca-f7x Obrigado.
Parabéns ao Borges pela excelente prova e pela grande vitória na "Prova de Distânica" :)
Parabéns a Todos!
Grande Borges!!!
Obrigado.
@@FernandoFonseca-f7x Obrigado.🙂
A "Prova Surpresa" cria sempre um grande frisson nos participantes.
Parabéns a Todos!
Esta prova do "mata-mata" é sempre muito emocionante! Parabéns aos vencedores.
Parabéns a Todos!
Obrigado a todos os que contribuiram para a Race Party 2024.
Parabéns a Todos!
Very funny and enjoyable.
Many thanks.
It's true. Many thanks.
wow!!! What a competition :)
Many thanks!
Many thanks.
Nice lecture.
Many thanks.
Beautiful analysis. 🙂
Many thanks.
Simple explanation. Very often the things are simpler than they look initially.
Many thanks. Keep it Short and Simple (Kiss Principle) 🙂
@@ProfessorPauloFlores I agree. 🙂
Impressionante!!! 😆
Obrigado 😃
Grande lição, muito inspiradora. Obrigado pela partilha. 🙂
Muito obrigado.
Abordagem geral e simples. Muito bom. 😃
Muito obrigado.
Very funny 😁
Many thanks.
@@ProfessorPauloFlores You r welcome 😄
Nice summary of concepts. Thanks for sharing. 🙂
Many thanks.
Nice description.
Many thanks.
Great lecture.
Many thanks. I agree with you.
As always.
Terra-cotta warriors ... very impressive.
Thanks a lot.
Great Wall of China .... simply great.
Many thanks.
The topic of rolling friction is not easy. Nice description anyway. Thanks.
Many thanks for your comments.
Very well described! Congratulations and thanks.
Many thanks.
I enjoyed this animation. Thanks for sharing.
Many thanks.
Professor Lewin put the things simple and clear. 😇 Respect!!! 😁
Many thanks. I totally agree with you.
Great lesson from Dr. Lewin. Great mentor and physician. Big Thanks.
I thank you so much.
for a rolling object, with mass m, descending a ramp with inclination teta, the linear acceleration is given by the following expression: a = (m*g*sin(teta)) / (m+(I/r^2)) where I denotes the rotational inertia or mass moment of inertia at the center of mass, and r is the radius below are the mass moment of inertia for several rolling objects: 1. Solid Sphere: 2/5 *m*r^2 2. Hollow Sphere: 2/3 *m*r^2 3. Solid Cylinder: 1/2 *m*r^2 4. Hollow Cylinder: m*r^2 thus, corresponding accelerations are: 1. Solid Sphere: a = 5/7*g*sin(teta) 2. Hollow Sphere: a = 3/5*g*sin(teta) 3. Solid Cylinder: a = 2/3*g*sin(teta) 4. Hollow Cylinder: a = 1/2*g*sin(teta) hence, in a race between these 4 rolling objects down in an inclined plane the results are: 1st place: Solid Sphere 2nd place: Solid Cylinder 3rd place: Hollow Sphere 4th place: Hollow Cylinder See demonstrative video of this race in the following link (instant of time 55min 05sec): kzread.info/dash/bejne/l4ya2dGdnrKcnMY.html
Very simple and didactic demo.
Many thanks!
Very interesting. 🙂
Many thanks.
Very well described. Thanks Dr. Lewin. 🙂
Many thanks. I fully agree. Professor Walter Lewin is true educator and mentor.
Nice academic genealogy ... there are others, in fact.🙂
Many thanks.
This academic genealogy is very rich in terms of big names.
Many thanks.
Vídeo muito top 🙌🏻🙌🏻
Muito obrigado Sofia! :)