Пікірлер

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  @fydowirwanda87857 күн бұрын

  so amazing bro

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  @fydowirwanda87857 күн бұрын

  i like this so much

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  @aptonmukonde84309 күн бұрын

  I think the first formula is quite easy to use than the short method.

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  @randydollente965110 күн бұрын

  @BrainGainzOfficial Thank you for this video and series; I'm an older student getting back into math who never had experience in proof writing, so I very much appreciate your style and flow of presenting this subject.

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  @avrillellaine398914 күн бұрын

  Hello sir! May I ask if proof by cases is the same as the choose method? I’m confused about the two. The same goes for the Construction method and direct proofs. Are those two the same as well? Please enlighten me. Thanks.

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  @BGE9418 күн бұрын

  dude this is extremely funny but very very helpful thank you!

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  @user-db4dv3zp8k25 күн бұрын

  Thanks❤❤

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  @tofurkeydirky135927 күн бұрын

  Ok so it's been decided, Anthony Tucci is my actual math professor and I'm just paying to take exams

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  @braabraa4881Ай бұрын

  Best teacher in the universe ❤

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  @user-yt8ul4jk5zАй бұрын

  To finish the proof you just have to observe that the epsilon>0 is ARBITRARY: If the absolute disfference of two numbers is less than an ARBITRARY epsilon>0, then the two numbers must necessarily be equal.

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  @braabraa4881Ай бұрын

  Brilliant 🎉

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  @user-ob5dg8zt9hАй бұрын

  Display isnt clear

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  @estrellatrejo2363Ай бұрын

  thank you so much for doing this

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  @prince.c8458Ай бұрын

  This video was great!

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  @SanskrutiKarnawatАй бұрын

  What other universities offer a math heavy math education programmes?

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  @welllll...ok...2 ай бұрын

  Thank you. I have watched 6 videos on this topic, and this is the first one that explained these concepts in a way I could understand. Much appreciated!

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  @cilva7able2 ай бұрын

  If you think this is hard, try discreet math.

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  @cilva7able2 ай бұрын

  That’s not the TI inspire, and no, you would not be satisfied with a five dollar calculator. You obviously don’t know much about math otherwise you would know the difference.

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  @sebastianchakkalakalouseph41492 ай бұрын

  thanks for this

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  @Tojo-edits2 ай бұрын

  At Q 6.b i'm just confused at the period being 2pi/3 but you drew half of it, shouldn't there be a part of the graph going under the midline as well? Everything else was very helpful thanks!

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  @AungSanTint2 ай бұрын

  The explanation is clear and straightforward to understand. Thank you so much ! 😊

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  @ATHEERANGEL2 ай бұрын

  I adore u , you're my hero!

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  @riverevr68912 ай бұрын

  This is a really positive video, I too am a mathematics student, and recently I've been hit with the pretty common thought in society that studying maths isn't really useful...("should just be an engineer or computer scientist, etc,...".) Seeing you talk about doing what makes you happy and how important that is really hit home to me. Studying mathematics is the future that I want, and it's a future that I see myself being the happiest in. Yes, it is true that we will probably not be the richest, but being rich is truly defined as being happy and proud of the life that you're living. Thank you, Brain Gainz.

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  @keldonchase44922 ай бұрын

  I was wondering if this is another valid way to write the proof: Prove the transitive property: If a|b and b|c, then a|c for all positive integers a,b,c. Let’s analyze our first given. We know that a|b. What does it mean for a to divide b? Let l be any positive integer. lℤ+. This means that a times some integer l equals b. Algebraically, we can say: al=b Manipulating this expression to solve for a, we find that: a=b/l Let’s analyze our second given: We know that b|c. What does it mean for b to divide c? Let m be any positive integer. mℤ+. This means that b times some integer m equals c. Algebraically, we can say: bm=c What are we trying to prove? We are trying to prove that a|c. What does it mean for a to divide c? Let n be any positive integer. nℤ+. This means that a times some integer n equals c. Algebraically, we can say: an=c We are trying to prove that a|c. We are trying to prove that an=c where n is some integer. This means we are trying to demonstrate that n=c/a is an integer. We have n=c/a. Recall that c=bm and a=b/l. Let’s replace c with bm. Let’s replace a with (b/l). n=(bm)/(b/l) We multiply bm by the reciprocal of (b/l). n=bm*(l/b) The bs here cancel, leaving us with: n=ml Recall that m is a positive integer. Recall that l is a positive integer. Positive integers are closed under multiplication. This means that the product of two positive integers yields a positive integer. Thus, n must be a positive integer. Since we have confirmed that n is a positive integer, we have confirm that a indeed divides c. Can you let me know whether or not this proof is valid? Thank you :)

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  @sinless2 ай бұрын

  repeated this for one hour on an 8sec loop now it's burned in my brain

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  @douglassmith94452 ай бұрын

  I’m getting 16.206 for #71. How am I barely off? Only typing the right side of the equation in the calculator.

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  @ezraclark17933 ай бұрын

  2:36 🤣 I'm definitely gonna remember to foil in the future LOL

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  @nojusb43773 ай бұрын

  I've learned far more from this review than I have in class😅. This man has the best most in depth explanations for every problem. Great job 💪

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  @wizgeek86503 ай бұрын

  Thank you so much!

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  @fmyrico3 ай бұрын

  pretty good singing voice 😂

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  @wizgeek86503 ай бұрын

  Bar far the best review on youtube for college level algebra

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  @wizgeek86503 ай бұрын

  AMAZING

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  @SimonSichivula3 ай бұрын

  Sir brian help on that one

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  @SimonSichivula3 ай бұрын

  How can you solve this this wuestions:Define a relation on R square\(0,0) by letting (x1,y1)equivalence (x2,y2)if there exists a nonzero real number m such that (mx2,my2).prove that relation defines an eqivalence relation on R square \(0,0).What are the corresponding eqivalence classes ?This equivalence relation defines the projective line,denoted by P(R), which is very important in geometry.

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  @SimonSichivula3 ай бұрын

  Great

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  @SimonSichivula3 ай бұрын

  Excellent

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  @arjunmohod52273 ай бұрын

  A relation R on a set of integers defined as aRb if and only if (a - b) is divisible by m, is a +ve integers. Show that R is an equivalence relation.

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  @UniteMunyanyiwa3 ай бұрын

  Thank u

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  @sunflowermulti-purposeco-o42733 ай бұрын

  Amazing it take me time until I came across this video 😂😂😂😂😂❤❤

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  @ericb56343 ай бұрын

  great video! Your introduction is really clear and insightful. A lot of times in math, we're just thrown problems and are expected to know the set-up every time with no context. This is where the beauty of math comes. My only contribution to the video would be to show how vertex form would look like...etc. as that is becoming a standard in school, but I honestly follow this method so much better. I think you mentioned that this was a geometric approach, so maybe I'm being too algebraic in my thinking. Thanks for the really great videos. I enjoy your complex polar-coordinate video as well, and it is a new concept for me that I am really intrigued by.

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  @varyable37583 ай бұрын

  Epic intro

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  @modernearthprophecy3 ай бұрын

  everyone: calc 3 is easier mfs that fw algebra: 🤬🤬🤬

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  @juyeon58552 ай бұрын

  i struggled with calc 3, got a 79😭

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  @awesomeivxn18253 ай бұрын

  swear bro you turned my grades around. God bless you

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  @meanderer98083 ай бұрын

  this is proof by contraposition

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  @emiiariilol3 ай бұрын

  Thank you ! I have finals coming up, this will help me.

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  @SaintHerald3 ай бұрын

  Shit makes me cry

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  @danielkelsosmith3 ай бұрын

  Absolute legend.

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  @LemuelYeboah3 ай бұрын

  The explanation is really simple Thanks

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  @wawayseh3 ай бұрын

  is the first proof biconditional? or are any of these proofs biconditional?

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  @frederickteye3 ай бұрын

  Thank you chairman