Пікірлер

• 
  @nicilyasАй бұрын

  thanks a lot

• 
  @catfish4825Ай бұрын

  Great explanation and trick

• 
  @notz444yn2 ай бұрын

  THANKKK UUUU

• 
  @aniquaamir72342 ай бұрын

  Thank you for showing the show

• 
  @leahariel8283 ай бұрын

  this is so helpful thank you!

• 
  @noobmaster-gc2nd3 ай бұрын

  the second one is wrong, it’s not a strong nucleophile so it can’t be sn2

• 
  @user-gv6zd9zv7w5 ай бұрын

  why did you have to put a 1 over the 0.0625mol

• 
  @talalsiddiqui2205 ай бұрын

  thank you for making this awfully worse for me to understand :)

• 
  @user-dd6ft5wm7i5 ай бұрын

  That was so good

• 
  @funnyshorts65645 ай бұрын

  This is very very helpful thank youuu

• 
  @brantleyharriman56235 ай бұрын

  This is really good!

• 
  @sandra109545 ай бұрын

  Does the 4 th one have a plane of symmetry? Then will it be optically inactive and achiral? If it is achiral how can it have stereoisomers?

• 
  @jasperchen30626 ай бұрын

  How do you know that’s it’s B->A and not B -> c

• 
  @DahAcademy6 ай бұрын

  This is a multiple choice scenario, and you are given 4 potential options where one of them is correct. A pathway where substances "A" and "C" are switched in the final answer is possible and would be a correct answer if it was provided. Keep in mind, this question is asking about pathways, not the pathway. Since that option wasn't available, you eliminate all the options that could not possibly be the answer and remain with the final choice available which fits the scheme.

• 
  @jasperchen30626 ай бұрын

  @@DahAcademyi agree with your response but is there a way to differentiate if it was not a multiple choice, thank you so much for the fast reply. The branching aspect towards the next “supplement/intermediate” is giving me a hard time. I HOPE YOU ARE DOING WELL IN YOUR CURRENT ENDEAVORS

• 
  @DahAcademy6 ай бұрын

  ​ @jasperchen3062 if it was not multiple choice, you would need more information to differentiate. For instance, you would need to know what would happen to the mutants if you provided both substances C & D. Given the mechanism we see, mutant 1 would show growth because even if you cut off "A", providing both C and D would allow the organism to survive. At the same time, you would see that mutant 3, which is cutting off "C" grows if you provide substance "C", doesn't grow if you provide substance "D", and grows if you provide both. This would indicate that C is not at a branching point and is independent of substance "D", so it wouldn't be placed where substance "A" is. You get the idea? With more information, you can narrow down the results. Since the information is limited, you have a set amount of options you can pick from.

• 
  @jasperchen30626 ай бұрын

  @@DahAcademythank you so much I truly appreciate the time you took for the response!!! The response helped in clearing up the questions that I had :))))(

• 
  @paulhetherington38546 ай бұрын

  /p''' R' aerodyn {8:6 | 6:8 rcv'''L'' stach archz}/ /> fr r'''band {8:6} PR-WV''' mrkd band wdth stachx/ /fr: xyz = flkrm(M''iitTn''') lb'''(arch > cvkL'''r thrmlx mrkz) by cnvx kov band ad {dn: wr || wrls hlf EFI || thrchl mid strk}/

• 
  @patrycjaprzedwojska10727 ай бұрын

  very helpful, thank you! :)

• 
  @patrycjaprzedwojska10727 ай бұрын

  thanks, that really helped!

• 
  @JohnDoe737367 ай бұрын

  This is for polar protic solvent?

• 
  @gerrythekay8 ай бұрын

  You can also go from an acid chloride to a ketone by reacting at low temperature with a Grignard reagent. This is the Eberle Kahle ketone synthesis.

• 
  @angelarebollar39488 ай бұрын

  Thank you for breaking it down so simply! I was having a hard time figuring it out until this video

• 
  @freedomisinmyhead9 ай бұрын

  Thank you, this is clearly explained ! ❤

• 
  @szxnv9 ай бұрын

  Dang that explanation was great! I'm appreciative of it :)

• 
  @anthonytan614310 ай бұрын

  Absolute goat!!!!!!!!!!!!

• 
  @aaliyahvarona540910 ай бұрын

  are these the only two things we compare for basicity?

• 
  @luciocardenas286910 ай бұрын

  How do you the red eyes are dominant?

• 
  @Ahsankhan-dz5hg11 ай бұрын

  Soon

• 
  @Ahsankhan-dz5hg11 ай бұрын

  Sir plz make a video on reactivity of organic compounds plz

• 
  @Ahsankhan-dz5hg11 ай бұрын

  Sir In number 7 ring where oxygen and nitrogen lone pair takes place in ring and ring became anti aromatic

• 
  @Ahsankhan-dz5hg11 ай бұрын

  So plz tell me why lone pairs of both atoms takes place in ring

• 
  @Ahsankhan-dz5hg11 ай бұрын

  And also you say that Nitrogen lone pair is basic I can't understand if nitrogen lone pair takes place in ring then how and why it is basic

• 
  @q.c8674 Жыл бұрын

  Just an addition, for the farthest bottom-left example, one of the two bonds between carbon and oxygen (C=O) would become a lone pair on oxygen as carbon can not form more than 4 bonds.

• 
  @AryaChandra-vk8xn Жыл бұрын

  Resonance rules ☝️

• 
  @tobiomotayo8011 Жыл бұрын

  Good job

• 
  @devonstarks7079 Жыл бұрын

  This thing will help in my university entrance exam. Thank you so much

• 
  @daviddewford8862 Жыл бұрын

  Your channel is a freakin Gem. Thank you so much good Sir. 🛐

• 
  @devonstarks7079 Жыл бұрын

  This is a freakin gem 💎

• 
  @user-ij4ld3xk2l Жыл бұрын

  The greatest explain in the world that I ever seen 😮❤❤🎉🎉

• 
  @logankain8356 Жыл бұрын

  Thank you for showing the whole show ☄️☄️☄️

• 
  @mohamedbenlashher4510 Жыл бұрын

  Congratulations my brother

• 
  @BetterCallZeyad Жыл бұрын

  U s a v ed my life

• 
  @jeonjeonggukk Жыл бұрын

  how do I know the charges of the amino acids when protonated/deprotonated?

• 
  @nkm748911 ай бұрын

  You have to look at their R groups. The R group is what differs one aminoacid from another.

• 
  @estabrqalmaloul683 Жыл бұрын

  Thank you

• 
  @cannoles Жыл бұрын

  Great explanation ty

• 
  @amansoni4488 Жыл бұрын

  Nice

• 
  @victorkipkoechrotich8569 Жыл бұрын

  Thanks so much it's really helpful

• 
  @araafmannan5065 Жыл бұрын

  what about hydride shifts in the second example

• 
  @michaelacheampongsr4836 Жыл бұрын

  Great video. Thank you

• 
  @eeui Жыл бұрын

  You saved me , much appreciated 🤍

• 
  @shiken69420 Жыл бұрын

  Thanks

• 
  @hagerhaitham8856 Жыл бұрын

  That was amazing , please do moreee of theses please basicity assessment videos

• 
  @queennmo Жыл бұрын

  THANK YOU SO MUCH!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

• 
  @camiladealvarez1685 Жыл бұрын

  dude this made pI so easy thank you so much

• 
  @randamustafa2891 Жыл бұрын

  why are vinylic radicals unstable? would you consider them the "most" unstable when given a set to rank?