Пікірлер

• 
  @HadisMalekpour-zm6xyКүн бұрын

  You explain everything really well, even better than my teacher. 😁 Thanks 🙏

• 
  @nuclearrambo31672 күн бұрын

  I would use fourier transform

• 
  @individual1st6483 күн бұрын

  ive been trying for a few weeks to blindly get a line segment rotating at one endpoint, but i just couldn't figure it out (i knew it had to do with y=tan(a) but i didn't know what bounds i should insert) then i figured, maybe i just look up how to make a clock! and there we have it (thanks!)

• 
  @Halleluyah8311 күн бұрын

  Wow😮

• 
  @KSM94K11 күн бұрын

  Maybe I didn't understand it very well, why the Psi 1 and Psi 2 don't they cancel here? In the residue theorem proof something like that used to be cancelled

• 
  @Saqouro13 күн бұрын

  This is really helpful. Thanks

• 
  @KSM94K14 күн бұрын

  You're seriously underrated, nice explanation

• 
  @rashmipandey920115 күн бұрын

  Nice

• 
  @physicstube812415 күн бұрын

  I never thought the job could be done this easier 🎉

• 
  @marrom680815 күн бұрын

  If i want to reflect relative to what a is, i.e. if y = x then a = 1 and then we have ((1, 0), (0, -1)), does this mean ((1,0),(0,-a)), so i.e. a = 2 means ((1,0), (0, -2)) ?

• 
  @txikitofandango17 күн бұрын

  This is so wholesome

• 
  @luaiderar660024 күн бұрын

  I think I saw you outside melbourne central. Apparently you're my friends calc 1 tutor at unimelb lmaoo.

• 
  @qncubed324 күн бұрын

  :O

• 
  @kianheus248724 күн бұрын

  Hi, loving the videos so far! I also have a question: at 15:08 you say to simply assume the existence of a C^k atlast, but how does that work in practice? Surely you can't just assume one to exist out of the blue.

• 
  @weselise248927 күн бұрын

  you saved me thank you

• 
  @nicholasnick649929 күн бұрын

  Great video

• 
  @meruem6022Ай бұрын

  Hello @qncubed3 , I wanted to know if you have any bibliographical reference on solving the Basel problem using that method

• 
  @user-wu8yq1rb9tАй бұрын

  I missed you..... Just tell me where are you??!!

• 
  @buddychumpalfriendhomiebud9242Ай бұрын

  For a simpler method, substitute u=1/x , move around some things and replace u with x and you'll see that the integral is equal to its negative

• 
  @nizogosАй бұрын

  Can't you say that 1/abs(z^4+1) <1/abs(z^4) ? Simply because the right fraction has a smaller denominator, without going into triangle inequality stuff

• 
  @qncubed3Ай бұрын

  This only works if z^4 is positive. If z^4=-2 for example then you would get 1<1/2

• 
  @natnaelayele8388Ай бұрын

  The most helpful video on the topic in the entire KZread

• 
  @anshuagrawal7364Ай бұрын

  Amazing!!! Could you please continue posting more videos on Manifolds? 🙏🙏🙏

• 
  @BernhardBolzano985Ай бұрын

  Great work!Ad maiora semper...

• 
  @smftrsddvjiou6443Ай бұрын

  funny, but useless.

• 
  @iphilip1Ай бұрын

  Can you still show the analyse program that you have in your CAS link in you description or comments section

• 
  @mai1906Ай бұрын

  what a loser

• 
  @xxux1Ай бұрын

  Seems the link is not working😅

• 
  @iphilip1Ай бұрын

  yeah

• 
  @itisajem8645Ай бұрын

  Interesting the result looks like the reflection formula for the gamma function but with 1/n

• 
  @ayandas8299Ай бұрын

  Bro you are the goat

• 
  @nuclearrambo3167Ай бұрын

  cOnSeRvAtIvE vEcToR fIElD

• 
  @user-qk5ce5rr7uАй бұрын

  thank you, I ask you one more series expansion of tan(z) 31:17 I want to learn principle of this series of tan(z).

• 
  @Mouse-qm8wnАй бұрын

  Thanks a lot for great videos ❤😊. Can you please give examples of when to use this in real life or is it only relevant in general relativity?

• 
  @Caller8194Ай бұрын

  good video

• 
  @user-qk5ce5rr7uАй бұрын

  Great!,thank you for your lecture, would you explain series of tan(z)(31:17)? I don't know result of this series.

• 
  @LatifaEssaАй бұрын

  Vraiment c est super Je sais pas comment je peux remercier

• 
  @hyeonsseungsseungiАй бұрын

  5:34 It's easier not to reduse (s+i) or (s-i) because (i+i)^4 or (-i-i)^4 is 16, so thier denominator becomes rational.

• 
  @williammartin4416Ай бұрын

  Thanks!

• 
  @SarmadnessАй бұрын

  Great explanation, thanks!

• 
  @NeptoidАй бұрын

  The Jacob Collier of Physics

• 
  @GingerMathАй бұрын

  After two years I found this video and it makes sense!! Thank you <3

• 
  @anandarunakumar6819Ай бұрын

  Great explanation. Nice teaser to conformal technique.

• 
  @matejcataric2259Ай бұрын

  This channel rocks!! Greetings from Croatia.

• 
  @PlayingcivilizationАй бұрын

  Much easier with double integration I = \int_0^\infty \int_a^b sin(tx)/x dt dx = [using Foubini] = \int_a^b \int_0^\infty sin(tx) / x dx dt = \int_a^b pi/2 dt = pi/2 * (b - a)

• 
  @MuhammadYogavasАй бұрын

  Is it possible to prové it with only gamma function ? Because our Professor didnt teach us the Beta function yet

• 
  @richard_larrainАй бұрын

  0 is not a pole of logarithm

• 
  @PlayingcivilizationАй бұрын

  Hi Could you please do a video about integral from 0 to infty of ln(x)/((x+1)*x^{3/4}). I was trying to solve it using complex integration but failed to find proper contour:(

• 
  @devanshgupta3935Ай бұрын

  My final today had this exact integral. I did kind of figure out that we need to take a Gaussian integral to come to the result but used some QUESTIONABLE mathematics. Wish I'd watched this vid earlier. Anyways this channel is absolutely amazing! Please keep it up.

• 
  @Harshsharma5Ай бұрын

  soo cool.