Пікірлер

• 
  @sercandurdu642Күн бұрын

  🤯😍

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  @peterthomas57924 күн бұрын

  Any programmer would immediately write 32768 + 4096 + 512 + 64 + 8 and add them up.

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  @ronnietwelvetoes18766 күн бұрын

  He just keeps repeating the same stuff - totally clueless

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  @iamhere23826 күн бұрын

  I think Super best tutor Ever...❤ Keep it up Sir... What is the need of 1k Subs...

• 
  @MathSync4 күн бұрын

  I am deeply grateful for your inspiring support.🤗☺️💕😍

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  @iamhere23826 күн бұрын

  Sir How the property of logarithum you used.....?

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  @iamhere23826 күн бұрын

  Waoooo....Two Methods.....❤😊

• 
  @iamhere23826 күн бұрын

  You Solved it Interestingly but i Solved it in Seconds.....❤

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  @MathSync4 күн бұрын

  That’s impressive! It’s always great to see different approaches to problem-solving. If you’re up for it, I’d love to hear about your method. Maybe we can learn something new from each other! 😊

• 
  @dardoburgos31796 күн бұрын

  a= 3

• 
  @oibender6 күн бұрын

  That could have been solved in 3 steps tops.

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  @johnnielson43418 күн бұрын

  This is why kids struggle with math. This was the most amazingly complicated and opaque solution possible.

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  @dhkim46218 күн бұрын

  root 12 = 2 root 3

• 
  @dirklutz28188 күн бұрын

  There are 2 more solutions: m=1.7649219... and m=-0.778373...

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  @sheobalaksingh99429 күн бұрын

  At the start itself this could have been multipled and divided by √108+√81

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  @edwinmot9 күн бұрын

  5^7/8=5^3x so 3x=7/8 and x=7/24 my god 8:34 minutes for this that's very ugly math, you can do this by heart

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  @iqbalbegum60410 күн бұрын

  Excellent

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  @MathSync10 күн бұрын

  Thank you for your kind words! I’m glad you found the content valuable. Stay tuned for more updates, and feel free to share any specific topics you’d like to see covered in future videos. 📚✨

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  @user-qy8re3yx3d10 күн бұрын

  a=3 Это видно из разложения на простые множители числа 702.

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  @ezzatabdo502710 күн бұрын

  Thanks too much, your illustration is optimum acceptable and simple state, thanks again

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  @MathSync10 күн бұрын

  I’m thrilled to hear that the explanations were clear and helpful to you! Your feedback is greatly appreciated, and it motivates me to continue delivering quality content. If there’s anything else you’re curious about or any other topics you’d like me to explore, please let me know. Happy learning! 🌟

• 
  @danielvandermaas282811 күн бұрын

  would it not just be way way easier to say that 5 = (125)^(1/3). Then substitute 5 for 125^1/3 in the original equation and write the square roots as a power of 1/2. Then just use standard calculation rules to get the correct power.

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  @Andnie11 күн бұрын

  isn't that pretty much what is done at 6:37 ?

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  @danielvandermaas282811 күн бұрын

  yes, but why the detour? Why not just write 5 as a power of 125 at the start and then simplifying the equation in just 2 more lines.

• 
  @eprogrammer210114 күн бұрын

  We can take integers from 0 to beyond in the negative spectrum, and boom i got -3

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  @henryalfred95515 күн бұрын

  这口算能力看着就着急，中国学生可以少写很多步骤，起码少一半时间做完

• 
  @MathSync15 күн бұрын

  謝謝你的誇獎！看到不同文化中不同的算術方法確實很有趣。解決問題的效率可能會有很大差異，觀察其他人如何解決數學挑戰總是一個學習機會。如果您有興趣探索各種數學技術，請隨時查看我的頻道以獲取更多見解和技巧！

• 
  @michaelf709316 күн бұрын

  No imaginary solutions?

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  @shabbydabbydo31417 күн бұрын

  Can't you do this much more quickly, ie cube root everything giving 2x +8=2. Then it's easy?

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  @georgesbv115 күн бұрын

  that's accidental that the solution means the other term of the sum is 0

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  @xgx89919 күн бұрын

  Really bad solution. Proper one: divide numerator and denominator by sqrt(3) to obtain (1-2)/(1+2)=-1/3. Math Sync - learn math before teaching one.

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  @iamhere23826 күн бұрын

  How You Solved in Comment...

• 
  @benjitsu846120 күн бұрын

  tried this in my head, I got (-6 +/- 6I√(3) )/-2, which is at least similar to the answer they got 😅

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  @ctsirkass20 күн бұрын

  You evercomplicated it for no reason. You just multiply the powers and you get immediately 8^4*8^2*8 = 8^7

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  @84com8320 күн бұрын

  How to invent or imagine something that only exist if you "believe in it" [yes I was taught something like that in school ( in the 1960-ties) but didn´t see why it was necessary to invent something that only existed in the mind of my teacher (at that time)] well, well things happen!

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  @ctsirkass20 күн бұрын

  I don't understand why all the trouble. 6^x=12 => x=log6(12).

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  @kakugan20 күн бұрын

  basic 10th grade high school math

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  @Dalroc20 күн бұрын

  Since both have to be positive, considering both the sum and the product are positive, if we're looking at real value'd solution we get a = 6-b => b(6-b) = 6b - b^2 which is strictly smaller than 36 for a,b <= 6 and therefore no real solutions exist and we have to look at complex solutions. Since the sum is real and not complex, the imaginary parts has to be equal but opposite, i.e we're looking for a conjugate pair where the real part is 6/2 = 3. So we have a = 3 + yi; b = 3 - yi ab = 9 + y^2 y^2 = 36 - 9 = 27 a = 3 + sqrt(27)*i; b = 3 - sqrt(27)*i And of course the second solution is simply switching the values of a and b around. So much unnecessary work in this video.

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  @E.h.a.b20 күн бұрын

  It may be easier if you use the following approach: a + b = 6 ----> [1] a b = 36 ----> [2] (a - b)^2 = (a + b)^2 - 4 ab (a - b)^2 = 6^2 - 4 * 36 Froma [1] and [2] (a - b)^2 = 36 ( 1-4) (a - b) = +/- 6 √(-3) a - b = +/- 6 i √3 ----> [3] 2a = 6 +/- 6 i √3 From [1]+[3] a = 3 +/- 3 i √3 2b = 6 -/+ 6 i √3 From [1]-[3] b = 3 -/+ 3 i √3 (a, b) = { (3 +3 i √3, 3 - 3 i √3) , (3 -3 i √3, 3 + 3 i √3) }

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  @Abhishek4EV320 күн бұрын

  Agreed. This video is totally stupid for explaining absolutely nothing. Those who don't know about i, won't understand anything from it.

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  @ctsirkass20 күн бұрын

  You made a mistake @2:17 you should have written (x-7)[(x²+7x+49)+1] instead of (x-7)[(x²+7x+49)]+1. In the next step you made a second mistake that corrected the first one so no harm is done in the end.

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  @immischannel174720 күн бұрын

  Tried solving it in my head, then realised the solution must be a complex number. So I gave up calculating it in my head.

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  @Abhishek4EV320 күн бұрын

  Yep an inaginary number.

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  @jonb402020 күн бұрын

  If that wasn't a complete waste of time and effort, what was it? And what does the weird upside down "?" mean? 😵‍💫

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  @Abhishek4EV320 күн бұрын

  Literally my thoughts after watching the thumbnail😂 before even starting the video.

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  @Abhishek4EV320 күн бұрын

  That's iota. It is used for imaginary numbers.

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  @jonb402020 күн бұрын

  @@Abhishek4EV3 Thank you. Would you maybe help me some more here please, if you can. Is there actually an answer to this equation? Or is that imaginary too?

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  @Abhishek4EV320 күн бұрын

  @@jonb4020 There is an answer. It's just not a good video for the explanation of the answer. Also it's not clear what are we supposed to find? a-b? a and b? a²-b²? So it should be put in the video to make it clear for everybody to understand.

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  @jonb402020 күн бұрын

  @@Abhishek4EV3 Well I'm prepared to believe you, though I can't see it. But then, I'm just a simple interpreter! It seems from the video that we are supposed to find the values of a and b. But the issue for me is that if a + b = 6, then neither a nor b can exceed 6, individually. By elimination of the possibilities, the maximum number that a x b can be is 9 (3x3) and that therefore one or other of the two statements is false. Therefore trying to work it out as if they are both true is, as I mentioned in my first comment, a waste of time.

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  @eliashilger706720 күн бұрын

  The third part of step 2 should be negative b squared plus 6b minus 36 shouldn't it?

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  @jaggisaram491421 күн бұрын

  8^7

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  @iamhere238221 күн бұрын

  NICE One....❤

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  @MathSync20 күн бұрын

  Thank you for your kind words! I’m glad you enjoyed the video. If you’re interested in more mathematical insights and problem-solving strategies, feel free to check out my channel. I strive to make complex concepts accessible and engaging. Hope to see you there! 😊📚

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  @kk44422 күн бұрын

  I was solving this problem during 10 seconds: a = -7, b = 6

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  @MathSync20 күн бұрын

  That’s impressive speed! It’s great to see such quick problem-solving skills. Keep it up, and you’ll master even the toughest of challenges in no time! 👍

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  @kk44420 күн бұрын

  @@MathSync Thank you

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  @pas629522 күн бұрын

  Ais -7 and Bis +6.

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  @MathSync22 күн бұрын

  My second chennal Please show support by like and subscribe: youtube.com/@8minutesexplainer?si=tsZkdtz1kcJgETVn

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  @borishalilov943522 күн бұрын

  to dramatic, for that simple math

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  @mhm290822 күн бұрын

  What a long winded way of doing it!.. Keep it in 8's not both with powers of 2, and you can do it in much fewer steps. You get 8 to the 7th power readily

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  @iamhere238222 күн бұрын

  Good Olympiad....🎉

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  @drisslahlou272623 күн бұрын

  X=log48/log4

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  @mks-learning-easy23 күн бұрын

  Nice Solution 😊. Keep it up!

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  @yodogyz24 күн бұрын

  homie can do complex eqautions but finding an audio input was just too much

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  @rabiulhaque807724 күн бұрын

  a is equal to 16 and b equak to 1

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  @ctsirkass20 күн бұрын

  Seems that a is equal to 3, not 16.

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  @hunghuynh484625 күн бұрын

  Dài dòng lòng vòng 😂😂

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  @anton-ke4qz19 күн бұрын

  More straight?

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  @Mb-logic25 күн бұрын

  Good

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  @erwinkurniadi185026 күн бұрын

  Do you use a calculating machine? Do people have to memorize log2, log3, log4, and so on?

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  @MathSync25 күн бұрын

  Calculators can be very helpful tools, especially for complex calculations! As for logarithms, while it’s not necessary to memorize values like log2, log3, log4, etc., understanding how to calculate them and their properties can be incredibly useful in mathematics and its applications. 😊

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  @lihuazeng764026 күн бұрын

  Beautiful! Thank you!🤩

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  @MathSync25 күн бұрын

  “It’s my pleasure! I’m really glad you liked it. 😊”