Пікірлер

• 
  @ashwanikumaraggarwal191515 минут бұрын

  Excellent methodology.

• 
  @prabirsarkar50418 сағат бұрын

  Those who are aware this type of mathematics they all know the formula. So no need to explain. You can simplify the mathematic easily why you takin X

• 
  @thetjdman21 сағат бұрын

  This is THEE DUMBEST way of doing multiplication.

• 
  @victorhugomedinavaldivia149Күн бұрын

  NO VES QUE DS MAS LARGO QUE EL NORMAL???????????

• 
  @panagiotistsigos7562Күн бұрын

  Very clever!

• 
  @KnowledgeTricks470Күн бұрын

  Thank you 😊

• 
  @chukwuemekaosonwa1382Күн бұрын

  How dear

• 
  @KnowledgeTricks470Күн бұрын

  Just do multiply two terms 7 × 109 = 763 , and then divide by percentage 100 , 763/100=7.63 . That's it my dear ❤️

• 
  @karan42512 күн бұрын

  Is process applicanle to 99 number only?

• 
  @KnowledgeTricks4702 күн бұрын

  This trick is applicable for all two digits × two digits For example: 23×56 , 76×89 3 4 × 6 2 ------------------ 18 08 == 3×6 =18 , 4×2=08 3 0× ==3×2=6, 6×4=24, 6+24=30 ------------------- 2108 I hope you understand this .

• 
  @Er.Munesh3 күн бұрын

  🎉🎉🎉

• 
  @gauravsarone66565 күн бұрын

  15

• 
  @sunitanegisunita64625 күн бұрын

  18

• 
  @farkaszoltan35156 күн бұрын

  10

• 
  @JebinUnish6 күн бұрын

  10 the answer is.

• 
  @KaviKavi-wj6me6 күн бұрын

  10

• 
  @Nikioko8 күн бұрын

  x = 3.

• 
  @ahmethulisiarslan88299 күн бұрын

  x.ln3.lnx=ln30 and lnXx=ln 30/ln3 and lnXx=ln27 and Xx=27 x=3

• 
  @pas62959 күн бұрын

  Easy method is by induction method. First four or five each value apply to X .3 suits you satisfying the equation

• 
  @pas62959 күн бұрын

  X is 3

• 
  @walterwen297511 күн бұрын

  A Nice Algebra Math problem: 111/x + 111/x² - 11/x³ = 11; x = ? x ≠ 0, Let: y = 1/x; 111/x + 111/x² - 11/x³ = 111y + 111y² - 11y³ = 11 11(y³ + 1) - 111y(y + 1) = 0, (y + 1)(11y² - 11y + 11 - 111y) = 0 (y + 1)(11y² - 122y + 11) = (y + 1)(y - 11)(11y - 1) = 0 y + 1 = 0, y = - 1; y - 11 = 0, y = 11 or 11y - 1 = 0, y = 1/11 x = 1/y = - 1, x = - 1; x = 1/11 or x = 1/(1/11) = 11 Answer check: x = - 1: 111/(- 1) + 111/(- 1)² - 11/(- 1)³ = 11; Confirmed x = 1/11: 111(11) + 111(11²) - 11(11³) = (11)[(111)(12) - 11³] = 11; Confirmed x = 11: 111/11 + 111/11² - 11/11³ = [111(11 + 1) - 1]/11² = 11³/11² = 11; Confirmed Final answer: x = - 1, x = 1/11 or x = 11

• 
  @KnowledgeTricks47011 күн бұрын

  Nice 👍🏻

• 
  @jakehobrath772112 күн бұрын

  I’m confused, this problem has infinite solutions, ie… a=5.281…, b=0, c=0. Were integer solutions stipulated?

• 
  @jakehobrath772112 күн бұрын

  What I don’t like about these types of problems is that you have to know the answer to know what numbers are needed to find the answer

• 
  @GetMeThere112 күн бұрын

  How do you know how to write out the terms on (x+a)!. X could be anything. OK, I see it now.

• 
  @johnpaullogan136513 күн бұрын

  personally i factored x^2-2 to (x+sqrt(2))(x-sqrt(2)) as a difference of squares but yours is probably easier to follow

• 
  @evilotis0113 күн бұрын

  oh well done! that was beautiful to watch <3

• 
  @KnowledgeTricks47013 күн бұрын

  Tnq😊

• 
  @andreipatrascu194413 күн бұрын

  solution : 4 4 4 4 4 8 8 8 8 9 6 6 6 6 7 3 6 1 2 6 8 4 4 1 3 2 6 7 5 6 1 3 3 2 6 8 8 4 8 1 3 3 3 2 7 7 9 5 6 8 9 2 8 8 7 9 9 5 6 9 3 3 2 8 9 9 3 3 2 8 9 is there something wrong w this solution?

• 
  @elmurazbsirov761714 күн бұрын

  Bakıdan salamlar.Əla həll etdiniz.

• 
  @fighterguard14 күн бұрын

  That was WAY more convoluted than I expected. My solution was to separate the 1 (obviously), divide by 4, then by 11111, then by 3. Regroup, and very easily get a perfect square trinomial that factors to (66666+1)². Took me all of 2 minutes, and less than half of the steps you took. I'm not saying your solution is wrong. What I'm saying is that the best way to teach maths is not by taking a more complicated path, IMHO

• 
  @olegnst909814 күн бұрын

  Weird solution... left part is multiplication of 4 conseq integers. 1680 = 2*2*2*2*2*3*5*7 = 5*6*7*8 => ×=2

• 
  @jadehuynh723414 күн бұрын

  So smart! It's not easy to see the trick here is to take 9999/9. By the way? Why not use "=" but "=>"? 🤔

• 
  @ABC-Projekt14 күн бұрын

  Nice, thanks!

• 
  @timkokesh196815 күн бұрын

  Rather than submit yourseld to all this algebra, you could just do a square root by hand like a normal person.

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  @reyallen310815 күн бұрын

  and that's why only few are great mathematicians

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  @timkokesh196815 күн бұрын

  @@reyallen3108 Having been around more than my share of great mathematicians, I can assure you that every single one of them would have taken the square root by hand (not much harder than long division) rather than fiddle with the algebra’s involved in this solution.

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  @fighterguard14 күн бұрын

  The vast majority of people don't know how to calculate square roots manually. Although, this is far too complicated a path to the answer. There is a far quicker and easier algebraic method that is also a lot simpler than manually calculating the square root. And it also fulfills the purpose of TEACHING ALGEBRA, which is the whole point of this exercise.

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  @timkokesh196813 күн бұрын

  @@fighterguard Sadly, you’re right. I didn’t learn how to calculate square roots manually until I was a senior in high school, and I had gotten a 5 on the Math AP as a sophomore. Why this isn’t taught before algebra boggles the mind.

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  @fighterguard12 күн бұрын

  @@timkokesh1968 I think it's because calculating square roots by hand is a lot more difficult and cumbersome than long division, while also being a lot less useful overall. What I mean is that no other maths concepts extend from manual square root calculations, whereas long division is closely related to many algebraic concepts. Besides, estimating a square root by eye (or by Fermi estimation) to within an acceptable margin is far easier than estimating a long division. And that's because, in a square root, you're trying to find a number that is intimately related to the one number you're given, whereas in long division you're given two numbers with no obvious relation at all (because, if the relation is obvious, then there's no need for the long division anyway)

• 
  @michaelbartsch317415 күн бұрын

  I just stumbled upon this ... very cool - nice explanation

• 
  @KnowledgeTricks47015 күн бұрын

  Tnq 😊

• 
  @Spiderslullaby15 күн бұрын

  3^4. 😊

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  @wafflaaar106715 күн бұрын

  amazing

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  @KnowledgeTricks47015 күн бұрын

  Tnq 😊

• 
  @Faithyouth-zl2uv16 күн бұрын

  Draw before 3 a 7 and the plus in the middle of 4 and 3

• 
  @peterotto71217 күн бұрын

  Schwachsinnige Aufgabe

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  @slavikhont482117 күн бұрын

  Не понятно. Почему 4умножить на 3.обьясните

• 
  @KnowledgeTricks47017 күн бұрын

  When we have first place digits are same multiply 3 × 3 = 9 add + 3 = 12 4×4 =16 +4 = 20 we got like this , that's y I am directly multiplying 3 with next number like 3×4 = 12, 4×5 = 20.

• 
  @4_nikk_attor17 күн бұрын

  I have a "CALCULATOR"

• 
  @honggyu021817 күн бұрын

  옛날 70년도 초반 일본에서 한국인이 선풍적 인기를 끌었던 김현문이란분이 창안해서 방송에도 많이 나왔던 내용입니다 두자리수. 앞자리가 같고 뒷자리 합이 10이되면 무조건 곱하고 앞의수 하나 올려서 곱하면 됩니다. 26×24 는 6 4 곱하고 3 2곱해서 624. 이렇게 ᆢ뒷자리수 합이 10초과 미만일때 계산법을 알고있습니다 ᆢ 그당시 우리는 주산으로 계산했는데 ᆢ이걸보고 배워서 4자리수 곱도 한줄로 암산하고 그랬죠

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  @rahiles543017 күн бұрын

  4225

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  @carmenbarburpena29217 күн бұрын

  4225

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  @pas629517 күн бұрын

  Ais9 and Bis 4

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  @torstenbroeer179717 күн бұрын

  My problem was, I thought you meant ^40 . A video with such a bad handwriting is just BULLSHIT!

• 
  @RandomGuyOnYoutube-oe5yt18 күн бұрын

  3^4

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  @user-uo4vk3pd9r18 күн бұрын

  3의3승 더하기 4의 3승

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  @KnowledgeTricks47017 күн бұрын

  3 ^4 = 81

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  @estrelapcdf214618 күн бұрын

  :(

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  @user-zg5ib6zw3j18 күн бұрын

  37+44

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  @KnowledgeTricks47017 күн бұрын

  3^4 = 81

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  @bryanheisler194718 күн бұрын

  ÷

• 
  @KnowledgeTricks47017 күн бұрын

  3^4

• 
  @RidPlays19 күн бұрын

  3 to the power of 4

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  @walterwen297519 күн бұрын

  Math Olympiad: √a + √b = 10, √ab = 10; a, b = ? √b = 10 - √a, √ab = (√a)(10 - √a) = 10√a - (√a)² = 10, (√a)² - 10√a = - 10 (√a)² - 2(5)(√a) + 25 = - 10 + 25, (√a - 5)² = 15 = (√15)², √a - 5 = ± √15 √a = 5 ± √15, a = (5 ± √15)² = 25 + (√15)² + 2(5)(√15) = 40 ± 10√15 √b = 10 - √a = 10 - (5 ± √15) = 5 -/+ √15, b = (5 -/+ √15)² = 40 -/+ 10√15 Answer check: a = 40 ± 10√15, 40 -/+ 10√15: √a = 5 ± √15; √b = 5 -/+ √15 √a + √b = 10 = (5 ± √15) + (5 -/+ √15) = 10; Confirmed √ab = (5 ± √15)(5 -/+ √15) = 25 - 15 = 10; Confirmed

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  @The_rooks20 күн бұрын

  3 to the 4th