Пікірлер

• 
  @manishplayz66874 күн бұрын

  How did u get the -1.26 anwser as a valid s ?

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  @mahanteshhalingali-mf9oq17 күн бұрын

  Amazing explaination sir

• 
  @user-lc8eo6rg4p2 ай бұрын

  Nice explanation sir, but in root locus how to get 's' values i didn't understand

• 
  @as-tutorials5537Ай бұрын

  Plz Go through the steps

• 
  @deepakravidas19832 ай бұрын

  Thank you sir Tomorrow is my exam

• 
  @as-tutorials55372 ай бұрын

  All the best👍

• 
  @DGXDX_2 ай бұрын

  Thank you sir Nice explanation you made it so easy to understand step by step 👍

• 
  @abhishekkumarpatel84553 ай бұрын

  Best explanation sir

• 
  @MR_UNKNOWN7094 ай бұрын

  Lot of help Sir 🎉

• 
  @Harsh-cq5yo5 ай бұрын

  Thx

• 
  @lavidolka28405 ай бұрын

  Exact process of calculation what I was looking for. Thanx a lot.

• 
  @aishuaishu43866 ай бұрын

  but sir is k value 10.39 how sir😢

• 
  @alihaider15636 ай бұрын

  How do we find out the values for K for which the closed loop poles are real?

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  @carultch5 ай бұрын

  Those are called break-in and break-away points. Given a transfer function of N(s)/D(s), the breakpoints will be found when the following equation holds true: N(s)*D'(s) - N'(s)*D(s)=0 We can do this for a system with 1 zero and 2 poles as an example. (s+6)/[(s + 5)*(s + 2)]. It is very difficult to do this analytically for higher order systems, as it means solving higher order polynomials, that may be impossible to solve by hand. N(s) = s + 6 N'(s) = 1 D(s) = (s + 5)*(s + 2) D'(s) = 2*s + 7 Construct equation to equate to zero: (s + 6)*(2*s + 7) - 1*(s + 5)*(s + 2) = 0 Solve for s: s = -8, the break-in point s = -4, the break-away point Given a closed loop made from K and G(s), the closed loop transfer function will be K*G(s)/(1 + K*G(s)). The denominator of this will equal zero at the two closed-loop poles. 1 + K*G(s) = 0 When G(s) = N(s)/D(s): 1 + K*N(s)/D(s) = 0 Solve for K: K = -D(s)/N(s) Thus, for our example: K = -(s + 5)*(s + 2)/(s + 6) Plug in breakpoints for s: at s = -4: K = -(-4 + 5)*(-4 + 2)/(-4 + 6) = 1 at s = -8: K = -(-8 + 5)*(-8 + 2)/(-8 + 6) K = 9 So at 1 and 9, we have poles that transition between being real, and being a complex conjugate pair. When K<=1, or K>=9, the poles are both real.

• 
  @249srihari47 ай бұрын

  thank u sir

• 
  @sanchu_s_diary7 ай бұрын

  Thank you so much Sir ❤

• 
  @sahilangra91807 ай бұрын

  What will be the initial slope for exponential factor

• 
  @mdashraf94097 ай бұрын

  nice explanation

• 
  @Suyash_Rasal8 ай бұрын

  Thanku sir ❤

• 
  @arunmk218 ай бұрын

  Thank you sir

• 
  @carlscaglione20228 ай бұрын

  Good work!

• 
  @hawaphiri9 ай бұрын

  Loving the video

• 
  @kulfranc97269 ай бұрын

  Am greatly humbled by d lecture

• 
  @penbook729011 ай бұрын

  done bro

• 
  @michelburrows606811 ай бұрын

  What a great explanation thanks.

• 
  @AkshayKumar-jq9ph Жыл бұрын

  Sir i am little bit confused about what is unknown angle

• 
  @swapniljadhav9494 Жыл бұрын

  at 22:25 the value of complex number is 118.02 you write -61.97 thats wrong

• 
  @as-tutorials5537 Жыл бұрын

  Check I have already mentioned in the video and corrected that. Please go through the complete video

• 
  @kamaliyaraj2880 Жыл бұрын

  Interesting and easy to understand ❤

• 
  @swapniljadhav9494 Жыл бұрын

  great Explanation

• 
  @New_movie007 Жыл бұрын

  T che valu chukle

• 
  @nazninsathi5332 Жыл бұрын

  The teacher is so excellent with his ausum tutorial vedio so helpful❤

• 
  @me-jz7uv Жыл бұрын

  Thank you sir.. from Nigeria.. having a paper in the afternoon🙏

• 
  @rakshithv23709 ай бұрын

  Hope you did well, Nigga

• 
  @Rohit2403-ek4sg6 ай бұрын

  Same bro we have paper tmmrw in india

• 
  @PiyushSharma-zz1ut6 ай бұрын

  ​@@Rohit2403-ek4sg mine too

• 
  @MohamedOuailCHARAOUI Жыл бұрын

  very good explanation, u deserve a lot of followers

• 
  @khaledshifullah434 Жыл бұрын

  Excellent ❤❤❤ wants more plz.

• 
  @anasarshad3453 Жыл бұрын

  Love from Pakistan 🎉🎉🇵🇰🇵🇰🇵🇰

• 
  @user-nf4kj8yb7u Жыл бұрын

  Extremely helpful thankuu

• 
  @861tummalapallibindhuhemad5 Жыл бұрын

  Thank you sir

• 
  @user-xr5ts4vt9d Жыл бұрын

  Sir I didn't understand how s=-1.26& s= -4.7

• 
  @as-tutorials5537 Жыл бұрын

  −3s^2−18s−18=0 For this equation: a=-3, b=-18, c=-18 −3s^2−18S−18=0 Step 1: Use quadratic formula with a=-3, b=-18, c=-18. S=(−b ± (√b^2−4.a.c))/2.a Substitute a,b and c value in the above formula S=(−(−18)±√(−18)^2−4(−3)(−18))/2(−3) S=(18±√108)/−6 S=−3−√3 and s=−3+√3 S=-4.7 and s=-1.26

• 
  @gamingwithirfan3459 Жыл бұрын

  Superb ❤️

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  @shagullahmad2303 Жыл бұрын

  thank you so much sir💞💞💞💞💞💞💞💞💞💞💞💞💞💞

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  @AbhishekKumar-pr1hg Жыл бұрын

  Sir arrival angle 310.61 hoga

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  @as-tutorials5537 Жыл бұрын

  Yes

• 
  @ji23da29 Жыл бұрын

  Thank you sir, really helpful example.

• 
  @ASHISHSHARMA-uu4mv Жыл бұрын

  Stable system

• 
  @muhammadmahmoudahmadfoaad7280 Жыл бұрын

  where is the drawing of the locus after these calculations ?

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  @as-tutorials5537 Жыл бұрын

  kzread.info/dash/bejne/ZWuizrKJpci2pbQ.html Go through this video you will get idea to draw the locus after the calculations

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  @as-tutorials5537 Жыл бұрын

  kzread.info/dash/bejne/epZlsqyHmJrJnKw.html Go through last part of this video. You will get genral concept of angle of arrival

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  @muhammadmahmoudahmadfoaad7280 Жыл бұрын

  The way you explain it is very good but the last touch is the most important you didn't even point with the pen how the angle 282.53 will look like, also theta departure for the poles has not been calculated

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  @deeptidase363 Жыл бұрын

  Thank you so much sir🙏so calmly and nicely you have taught

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  @as-tutorials5537 Жыл бұрын

  Thanks and welcome

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  @jethalalfunTV8 ай бұрын

  ​@@as-tutorials5537sir all sums of root locus aasa ee solve hoonga method toon same rahegaa na

• 
  @as-tutorials55377 ай бұрын

  Yes

• 
  @siddheshwagh2300 Жыл бұрын

  if there is no s in the denominator how to solve

• 
  @siddheshwagh2300 Жыл бұрын

  mrans s/(s+3)(s+6)

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  @as-tutorials5537 Жыл бұрын

  No 's' in the denominator means no Poles at the origin. For s/(s+3)(s+6) in this numerator one zero that is s=0 and denominator 2 Poles that is s=-3 and s=-6. Therefore one pole s=-3 reaches to zero and another pole s=-6 move towards infinite path at an angle 180°

• 
  @TouheedK Жыл бұрын

  The complex poles are -0.5 j9.98. Could u please let me know why did u take +0.5 in angle calculation

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  @as-tutorials5537 Жыл бұрын

  Poles are s=-a+jb,s=-a-jb To calculate angle we need to consider S+a-jb=0, s+a+jb=0 that is by taking right hand side terms to left hand side. In this problem s=-0.5+j9.98,s=-0.5-j9.98 To calculate angle will we need to consider s+0.5-j9.98=0, s+0.5+j9.98=0 that is by taking right hand side terms to left hand side. There for + 0.5

• 
  @kishoreburle727 Жыл бұрын

  How to calucat breaking point

• 
  @as-tutorials5537 Жыл бұрын

  Go through this link. kzread.info/dash/bejne/kXuit9Vrp9rAZs4.html kzread.info/dash/bejne/g2WVsLKwp8XYaMY.html In this problem I have explained to calculate breakaway point

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  @amitzerikunthe7635 Жыл бұрын

  I watched all videos of root locus methods, i understood all the concepts, thank you once again sir ❤️

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  @amitzerikunthe7635 Жыл бұрын

  Thank u very much sir

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  @rohithj.e9254 Жыл бұрын

  thanks a lot

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  @karthikms5407 Жыл бұрын

  Tqew Sir. For urs wonderful explanation ♥

• 
  @hiteshadookarun8941 Жыл бұрын

  in this case also we have breakaway points?

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  @as-tutorials5537 Жыл бұрын

  In this problem you don't have valid breakaway point.

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  @as-tutorials5537 Жыл бұрын

  As you know in this problem. We got complex breakaway point. For complex breakaway point we have to check the valid breakaway point by angle condition. By angle condition method we got to know in this problem we got invalid breakaway point