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• 
  @cloudproblemssolved13 күн бұрын

  132 is basically (60 × 2) + (10 + 2) 120 +12 = 132

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  @prasw42819 күн бұрын

  the video is over when he says earth orbiting the sun 🤣, you deserved a thumbs down for being coward and telling lies.

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  @ammarorama22 күн бұрын

  absolutely fantastic video. kudos.

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  @seckert110029 күн бұрын

  Problem number 2 is really interesting. When the question is first shown on the screen at the start, it is A ∩ (B ∪ C) and (A ∩ B) ∪ (A ∩ C) around 24 second mark. However When we go to solve it, around the 9:30 mark it changed to A ∩ (B ∪ C) and A ∪ (B ∩ C) . I believe that A ∩ (B ∪ C) and (A ∩ B) ∪ (A ∩ C) is equal while A ∩ (B ∪ C) and A ∪ (B ∩ C) is not. I was coming up with a different answer and I believe that to be the reason why. That being said, this is still an excellent video and explains the concepts very well.

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  @grammarnazi9456Ай бұрын

  There's another error in Example 4: Cook could also be at 8.5 degrees North. lat = e - 90 + d and that would be valid too.

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  @csvaughenАй бұрын

  thanks for the feedback, but I think you are making an error by using lat = e - 90 + d. It should be either 90-e+d (northern hemisphere, and the choice for Cook) or 90-e-d (southern hemisphere) so this does require knowing which hemisphere you are in, but there are many natural cues for that.

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  @grammarnazi945620 күн бұрын

  @@csvaughen Your second formula doesn't reflect signs very well. I watched the derivation you provided and noticed that in your 'southern hemisphere' example you take positive theta for a latitude south of the Equator. So using your second formula 90-e-d, you get -8.5 deg, but since you considered theta positive for southern latitudes, then -8.5 deg would be 8.5 deg North. Also, one more thing: The criterion that decides which formula to use is NOT whether you are N or S of the Equator but rather whether you are N or S of 22.9 degrees (the parallel corresponding to the declination). It would be as you say when dec=0 (on the equinoxes).

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  @litt222222Ай бұрын

  But very good video for learning Thanks very much!

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  @litt222222Ай бұрын

  Longtitude example 3 looks to be a wrong calculation to get 75 degrees : 7 hours x15 degree/hour 105 degrees

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  @csvaughenАй бұрын

  yes, very true

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  @roberthuff3122Ай бұрын

  Excellent and informative video. The multiple approaches e not 2.8 as the time subintervals go to infinity over the year.

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  @mejiqalАй бұрын

  nice game and lecture

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  @VTGuilmonBeyblader2 ай бұрын

  Great job Scott and Alexis !! Definitely want to look at doing internship work at Lockheed Martin - they have hired many of our students and many more have interned at some point in their academic careers.

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  @Kounomura2 ай бұрын

  There is already a certain asymmetry between winning and losing, a shift in the direction of loss even if I win the same percentage as I lose. If I start with $100 and gain 1% (101% = $101), then lose 1% (101*99%=99.99), the end result is -1Cent loss.

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  @csvaughen2 ай бұрын

  yes, I've always found that result interesting, equal percent gains and losses cause a long term loss over time. Nevertheless, that does not change the results derived here.

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  @SuperJaypatterson2 ай бұрын

  Very good, I just wish I could follow along and understand it.

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  @csvaughen2 ай бұрын

  thanks, I can try answering any questions, this is a newer video on same topic kzread.info/dash/bejne/X2qd1Maqf9K1XZs.html

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  @roote4k1542 ай бұрын

  THANKS YOU FOR SHARING THIS VIDEO

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  @roote4k1542 ай бұрын

  THANKS YOU FOR SHARING THIS VIDEO

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  @roote4k1542 ай бұрын

  THANKS YOU FOR SHARING THIS VIDEO

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  @roote4k1542 ай бұрын

  THANKS YOU FOR SHARING THIS VIDEO

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  @doglao12363 ай бұрын

  Thank you very very very veeeery very much!!!!!

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  @gabrielpetricec21633 ай бұрын

  Can You provide a videó about Nanson Method for The voting even it isn't used anymore

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  @csvaughen3 ай бұрын

  Hi, thank you for your comment- I'm sorry, I'm not even familiar with the Nanson method - had to look that one up - interesting - a hybrid method!

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  @carolsaller4 ай бұрын

  Thank you for this wonderful explanation and demonstration! It will make my appreciation of the clock so much great when I visit next month.

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  @TheQuantumOxymoron4 ай бұрын

  What If: the three bodies are of different nature / substance? Like: Human - AGI - ASI Physical - Digital - Quantum At the same they are of similar natu as they "contain" each other. Just following generally different rules of behaviour. This is a pure speculation though.

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  @csvaughen4 ай бұрын

  yes, fascinating to think about: the "bodies" measured by something other than mass and the "interactions" governed by something other than gravity. It seems like going from 2 to 3 bodies would always significantly complicate the interactions and this example, with mass and gravity, is just one illustration of that.

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  @Floodcho4 ай бұрын

  Ll l

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  @deniselucasblanchek63574 ай бұрын

  It would be incredible to see this in relation to true earth (i.e. geocentric ) Thank The Lord Our ancestors were not cosmologically deceived 🙏🏻

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  @sulimanemad92614 ай бұрын

  ❤

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  @leonbrunel66074 ай бұрын

  Thanks really helpful for my science fair

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  @Two-Scoops-2 ай бұрын

  kzread.info/dash/bejne/mK6tsNZ7lZSuZbg.html

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  @luminatuber4 ай бұрын

  Excellent video, its a thing of past but must know. Now they use gps, speed of light, lasers and atomic clocks for high accuracy using advanced matrixes.

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  @BertTotzke5 ай бұрын

  are you sure that declaration is 23.45 at tropic of cancer? what about 23.5?

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  @csvaughen5 ай бұрын

  Interesting question: From wikipedia: The Tropic of Cancer's position is not fixed, but constantly changes because of a slight wobble in the Earth's longitudinal alignment relative to the ecliptic, the plane in which the Earth orbits around the Sun. Earth's axial tilt varies over a 41,000-year period from about 22.1 to 24.5 degrees, and as of 2000 is about 23.4 degrees, which will continue to remain valid for about a millennium. This wobble means that the Tropic of Cancer is currently drifting southward at a rate of almost half an arcsecond (0.468″) of latitude, or 15 m (49 ft), per year. The circle's position was at exactly 23° 27′N in 1917 and will be at 23° 26'N in 2045. en.wikipedia.org/wiki/Tropic_of_Cancer

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  @BearDown275 ай бұрын

  Thank you for this!

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  @Foasperfect5 ай бұрын

  شكرا جزيلا🔥❤️❤️😮‍💨

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  @spacestray5 ай бұрын

  So thrilled to have stumbled upon your channel. It's a gold mine for an aerospace engineering student like me diving into Space Mechanics. Thank you for this amazing work!

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  @csvaughen5 ай бұрын

  super glad to know... presumably you also found this site? sites.google.com/view/kspmath

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  @spacestray5 ай бұрын

  @@csvaughen Yes I did, Thanks again!

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  @dr_devaprasad_reddy_kandukuri5 ай бұрын

  😂😂 didn't expect the medical questions 🎉🎉 much needed this thanks.

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  @Swhet5 ай бұрын

  Thank you for this creation. I am in the process of developing a semester elective Orbital Mechanics course for high school and plan to incorporate KSP into the class. Your workbook and videos are an inspiration and will help inform the lessons and activities I present to my classes. Cheers!

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  @csvaughen5 ай бұрын

  Awesome!! So happy to read this - exactly what I made this for - what lucky students to have you as a teacher and to have such an opportunity in high-school

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  @user-gt9mw3ou9e6 ай бұрын

  appreciate

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  @konturgestalter6 ай бұрын

  Love this series! i hope you continue making more of these!

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  @jankral77606 ай бұрын

  Thank you, only here is a little mistake: At time 30:13, instead of 100-2 should be 100-4, as these are two tickets, both costing 2+2=4

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  @csvaughen6 ай бұрын

  thanks for your comment, however (100-2) is correct because, in that event, you win $100 and pay for one ticket which costs $2, thus the profit would be $98. The chance of winning the $100 prize is based on 2 tickets out of 500 so the probability is 2/500. Still, we calculate outcome of that event based on winning one ticket (100 - 2) because question asks for expected value of a single ticket.

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  @rustymugg96587 ай бұрын

  It's the clock telling the truth.

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  @MrAdsfsadf7 ай бұрын

  I watched the whole thing, and actually understood it, very well explained! I think I understand more the novel plot now. I can also imagine this is one of the simple ways to simulate this, and relies on a bunch of assumptions. It would be cool to show this on some TV screen in the depths of a funky Amsterdam coffeeshop.

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  @csvaughen7 ай бұрын

  yes, that's great, so glad to know, thanks for feedback - yes, it's a step one here in the method of simulating, but all correct, and next level would be to get more accurate and precise in the calculations, I'm still working on that, and hope to post another video on that soon

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  @markTheWoodlands7 ай бұрын

  Chris, This is really good. I'm familiar with the topic, so that helped, but your coverage was great. I especially like the result of just changing the mass of one of the three bodies. One key point is that the simulation easily scales to N bodies. Whereas even if a math genius eventually creates a 3 body closed form solution, I cannot imagine anyone even trying to create an N body closed form.

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  @csvaughen7 ай бұрын

  thank you!! and yes - true - probably would have to be a mathematician from a higher dimensional space

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  @markTheWoodlands7 ай бұрын

  @@csvaughen - Hehe. Very good. OK - so I just watched a horseshoe (co-rotational) orbit courtesy of Elizabeth J. Tasker. Quite fun.

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  @triganden7 ай бұрын

  @1:02:51 Philadelphia should be 75.2W, not 74.2W

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  @csvaughen7 ай бұрын

  yes, correct!

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  @scottswisher42167 ай бұрын

  Bla bla …get onboard,draw your navigation on the inside of the sphere,you can see your destination on the other side of the sphere like the celestial sphere with the earth at the center and the starz on the inner surface of the sphere like a thin piece of tracing paper you can see through either side and then imagine cracking an egg looking inside a point on the horizon where the egg remains joined you can tracker ball on the surface of the southern hemisphere and the northern hemisphere of the eggshell represents the sky the viewing plane is the space opened by cracking the egg. The cosmic perspective

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  @globisdead8 ай бұрын

  Applications of graph theory: 31:24

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  @rhiannelopez79878 ай бұрын

  Thank youu so much!!!

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  @alanrapoport20909 ай бұрын

  What is the probability with 100 students that there are 15 pairs of birthdays and one trio? Secondly a question I can not begin to answer: what is the expected distribution among 365 students? Computer simulation? More than one right answer?

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  @csvaughen9 ай бұрын

  hmm, interesting questions... I once had a class that had 3 pairs of matching birthdays, and I was included in one of the pairs. I don't think I've seen a trio match before, that's fun...seems like you'd really need a big group for any chance of that... next time I teach the stat class, this could be a fun thing to explore, yes, with a computer simulation, that would be fun

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  @alanrapoport20909 ай бұрын

  Am an elderly retired physician. The answers to the 2 , 3,4 and 5 persons’ birthday problems ,at P= 0.50 are well known:23, 88, 187 and 314. How big was your class with three pairs?

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  @alanrapoport20909 ай бұрын

  I calculate that the largest group with a trio - without any pairs-is 34 with a P value of.01107876. Throw in 1 pair and the P value rises to .061696.

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  @alanrapoport20909 ай бұрын

  The problem above with 100 folks, 15 pairs and 1 trio gave me on my calculator P= .0160515. Took 3 1/2 minutes. How is it done in the real world?

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  @csvaughen9 ай бұрын

  @@alanrapoport2090 wow, this is great work, my class with 3 pairs was probably around 25 students.... honestly, I haven't really done any work on this topic beyond the basics I put into this video... and next, I'm not clear what you mean by "largest group with a trio without any pairs"... is the P value for this the probability of getting a trio (and no pairs) when you have 34 total people? Anyway, definitely this is a fantastic past time! I'm glad you found my video and found it interesting! I'll have to look up the 3,4 and 5 person b-day problems!

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  @r.firerunner70179 ай бұрын

  Thank yo Christopher. I have been wanting to find a way to determine both latitude and longitude by the sun. Great explanation and thanks for making the post on the two multiplication errors in examples 3 and 4. I am glad you did. Admitting the errors proves we are all human! Keep up the fantastic content.

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  @csvaughen9 ай бұрын

  thank you - yes, old video, if I did it now, I think I could do much better, some day I'll do a new version

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  @dustyg42619 ай бұрын

  This was extremely helpful; i was so stuck after listening to my college lecture. You broke it down better than my professor, so thank you

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  @nickfitzpatrick364210 ай бұрын

  how do you set this problem up for the tank being an ellipse?

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  @csvaughen9 ай бұрын

  yes - good question, that's the next step - it's really the same type of approach - you'll just need to get the equation of the ellipse, with center of ellipse at center of tank, solve for x or y, and find an area in one quadrant, from the axis to boundary of ellipse, and then everything follows in the same way as with the circle.

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  @ashutoshpandey846810 ай бұрын

  YOU'RE A MESSIAH

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  @globisdead10 ай бұрын

  Thanks professor. Now I know enough logic to become a lawyer

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  @martingarrish408210 ай бұрын

  This is very helpful! The usual method of explaining the eigenvalues of the state space representation in MatLab isn't intuitive for estimating the phugoid mode. Always good to do hand calculations rather than just trusting a more advanced model.

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  @csvaughen10 ай бұрын

  So glad to read this!! So glad it was helpful!

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  @P6009D10 ай бұрын

  How to translate Latitude and Longitude coordinates, to MGRS or UTM coordinates without a computer?

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  @csvaughen10 ай бұрын

  Yes interesting question- I’m sorry I don’t have any experience with that

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  @lupitatalksalot11 ай бұрын

  thank you!!!