Young Laplace Equation

An introduction to the Young-Laplace equation. One of a series of videos using lightboard technology developed at Imperial College London. I would like to thank Ollie Inglis, Hywel Jones and Lekan Ladipo from the Digital Media Centre in the Faculty of Engineering at Imperial College London for their help producing this and the other lightboard videos.

Пікірлер: 18

  • @anubhavarora3282
    @anubhavarora328210 ай бұрын

    Sir your way of explaining is truly fabulous. I am grateful to you for providing such a quality content

  • @user-ck2ew2oq7z
    @user-ck2ew2oq7z7 ай бұрын

    Finally I understand the basis behind the 2σ/r. Thank you for sharing your knowledge, Professor.

  • @DANGJOS
    @DANGJOSАй бұрын

    You make it look easy, thanks!

  • @IndiraYessenaliyeva
    @IndiraYessenaliyeva Жыл бұрын

    Crystal clear, thank u 🙏

  • @agamjain9138
    @agamjain9138Ай бұрын

    Thank you sir❤

  • @Fawad.ANizamani
    @Fawad.ANizamani Жыл бұрын

    OH MY GOD you are back

  • @pizzalove4693
    @pizzalove46933 ай бұрын

    Very nice explanation Thank you for such quality content

  • @manikmehta2090
    @manikmehta20903 ай бұрын

    ❤️❤️thanks sirr

  • @zq88
    @zq88Ай бұрын

    Hello, Professor. Thanks for your video! Can you explain how to determine the curvature sign? My understanding is that if the curvature center is in the denser phase, then it is positive. Is that right?

  • @BoffyBlunt

    @BoffyBlunt

    Ай бұрын

    I think you have this the wrong way round. We define the capillary pressure as the difference in pressure between the less dense phase and the denser phase, then positive curvature is when the less dense phase bulges out into the less dense phase (think gas and water).

  • @zq88

    @zq88

    Ай бұрын

    ​@@BoffyBlunt Thank you sir! I think I've got it.😃

  • @User-Tal1951
    @User-Tal19519 ай бұрын

    Hi I need to ask something. How to reach you? Thanks

  • @BoffyBlunt

    @BoffyBlunt

    9 ай бұрын

    You can email me at m.blunt@imperial.ac.uk

  • @coldchickennoodles5575
    @coldchickennoodles55753 ай бұрын

    I still don't understand the equation, can someone explain pls

  • @BoffyBlunt

    @BoffyBlunt

    3 ай бұрын

    What specifically would you like help with? I can try to clarify points that you are confused with.

  • @coldchickennoodles5575

    @coldchickennoodles5575

    3 ай бұрын

    @@BoffyBlunt Thank you so much for answering. I just find the 'dv' part in the first equation you presented slightly confusing and the V=4/3(pi)r^3

  • @BoffyBlunt

    @BoffyBlunt

    3 ай бұрын

    @@coldchickennoodles5575 The dV comes from work - the work done from basic physics is PdV where P is pressure and dV is the change in volume. The equation V - 4/3(pi)r^3 is the equation for the volume of a sphere in terms of its radius r.

  • @noodles8439
    @noodles8439Ай бұрын

    I understand everything except that the professor can write backwards.