For more algebra tutorials, please see my new channel "Just Algebra" bit.ly/just_algebra

You covered more in this video than my math teacher does in a full hour and a half 😂

@Caleb-sp3fb

Жыл бұрын

Strait facts

@blueberrygranger8890

Жыл бұрын

nah fr bro

I wish this man taught all my classes

This is the first person I've known who does 7 hours of math on there bday.

As a parent trying to assist her online math learning 7th grader THANK YOU! Your explanation was perfect and you showed every step.

thank you so much, you explained it so much better than my actual math teacher:)

Your dexterity at the white-board is phenomenal and your explanation is clear, concise and completely convincing: thank you.

Very Helpful! I think this is exactly what I've been trying to figure out, and it was explained very well!

Thank you so much! This was very helpful and your explanation was very easy to follow!

I'M NOT EVEN JOKING. I HAD AN ASSIGNMENT DUE AT 12 AND THANK YOU THANK YOU FOR HELPING ME UNDERSTAND THIS STUFF lol

Thank you this was very helpful, especially when you explain where the numbers came from when writing the equation itself at the end.

Thank you very much! I was struggling with my physics homework because I forgot how to write the equation of a parabola. This really helped me. :))))

great work my man, u helped me a lot, keep up the good work!

bro this guy is so good, i literally learned so much and he is such a great teacher, keep up the amazing work dude

You taught me more in 4 minutes than my teacher could in four days, thank you so much

Another way to do this is to set Y = a(X-b)(X-c) and find a, b and c. Note that if X= b and/or X = c we have Y = 0. So take b = 1 and c = -5 and you end up with Y = a(X-1)(X-(-5)). In order to find a you should require that one of the points (0,5) or (-2,9) is on the graph. Substitue for X = 0 and Y = 5 and you see that 5 = a(-1)(5) or 5 = -5a. This gives you a = -1. The equation is Y = - (X-1)(X+5). This, of course, is identical to the solution in the video.

@-mynkz6451

3 жыл бұрын

k

@aleena158

2 жыл бұрын

What if the prabola we are dealing with has no X intercept or only one? Is there any direct way like this one u wrote to get the standard ax^2 + bx + c ? Or do we have to open and solve the form shown in vid?

broo this man makes it look sooo EAASY.. And my teacher em doing some calculas type of shit to find the vertex.. LOL

I was struggling to understand the material until i found this video, thanks a lot 😂🙏🏽

Thank you!!! I have a unit math test tmr and didn’t understand nothing but now I will do great🙏🏽

excellent, simple and smart explanation.

thank you for the basic break down, you simplified it more that all my teachers did through high school.

Thank you so much man, this is very clutch

Thank you so much for this lesson, it helped me so much and I could understand everything perfectly

Thanks you answered all the questions I had about this without having to struggle to raise my hand

Thank you so much this really helped me with my math

Super helpful video. Thanks a ton!!!!

Thank to so much for this explanation!! 🙌

Very clear! Thanks mate

Thank you so much this was so helpful.

This was SOOO HELPFULL

Thank you, great explanation.

U made this so easy thanks keep it up

Hello , thank you so much for the help man

srsly thank you so much, i was having such a hard time understanding, and i understood perfectly in this video

thank you, u helped me alot

thank you so much. Its very helpful

Thank You !!!

Awesome video helped a lot

Thank you!!

Thank you man❤

Thank you!

engaging and interactive, man is a literal chad

Thank you. I know you produced this video 6 years ago and your teaching skills have improved immeasurably. However, I think it would have been helpful if you explained that you tackled the problem initially by completing the square, as most of us would be more familiar with this approach when asked to write down the equation, given the turning point/vertex (or vice versa). Otherwise, well done and keep up the good work.

Thank you so much.

thank you so much you saved my life bless you

super helpful. thank you.

Thank you so much

THANKYOU SO MUCH!!

thank you very much dude

Thankyou soo much 😢💖

Thanks man!

Thank you broo

bro, I have been struggling to solve these damn problems, but you saved me!!!!!!!

Thank you so much, you saved me man

Thank you man, Sincerely.

Thank you! Gracias

this came in clutch, i literally have an exam about this in like no time

thank you sir

Thank you

Helpful

thank you!

Thanks

sir, you save my life. I appreciate your video hahaha.

omg I was the 1500 like exactly and this video was super helpful I understood it super well thanks to the video

If we are not given the points on y axis then how can we make the equation..?

AWESOME!!!!!!!

THANKK YO SOO MUCH. ITS D LAST DAY OF OUR DEADLINE. AND THANKZZ TO U SIR, I FINALLY UNDETSTOOD IT.

My good sir thank u so much

thank you

awesome 👍

I have similar questions like this. But the turning point (vertex) is not given. How can I find that without the equation only from the graph?

I never thought I'd be using parabolas to optimize my builds in a video game, but here I am, lmao.

Yes but in the case that I have the equation but not the parabola what can I do??

very nice

thank you very much and how could one get the focus and the directrix from an equation in vertex form

Thank youuuuuu

i would die for this man

this guy is straight up cooking

The best!

can I use f(x) instead of y?

It might just be me but, why is his voice so stimulating?!?!?

mans marker switching skills tho😹😹 But well explained m8🙌🏽🙌🏽

I'm kinda confused if you don't know the number for h (x coordinate for the vertex). How would you complete the vertex formula?

@diyasinghall

2 жыл бұрын

Use the parabola formula (y-k)^2=x-h with the input your teacher gives u the h& k will be ur vertex points

Thanku

thanks man got it very well

thank yew❤️❤️❤️

i'm gonna pass my exam, ToT, thank you so much 😊

he taught it less than 10 minutes amazing!

Thank you so much 😊

HE USED A BLUE PEN

In the beginning I wasn’t understanding and in the end it seemed like I was in the beginning

Damn i met this question a while ago and i used my own method which was to multiply (x+5) with (x-1) to construct the quadratic equation

Hipppity hoppity I took my moms credit card

@TheLoomCrafters

5 жыл бұрын

QWERTY was a great night out of the way we got it one day and I got a good day and a good up way too long haha is that a big deal to get a little more than

what if the graph doesn’t give you the vertex value?

Bringing me out the mud fr

vertex is [-2 , 9] (v = h , k) y intercept is [0 , 5] x intercepts are [- 5 , 0] and [1 , 0] We have a "frowning" parabola. so we know that a is of a negative value So the vertex formula is y = -1(x+2)² + 9 (vertex form is y = a(x-h)² + k) The quadratic formula is y = -x² - 4x + 5 We know the a term is -1 because of the formulas x = h + √(-k/a) and x = h - √(-k/a) so lets prove it: x = -2 + √(-9/-1) negative divided by negative is positive so that means √9 which is 3 so x = -2 + 3 and x = -2 - 3. or the x intercept is the xy coordinate [1 , 0] and [-5 , 0] which is true for both cases. now prove the quadratic form: -1(x+2)(x+2) + 9. gives us -1(x² + 4x + 4) + 9 which finally is -x² - 4x -4 +9 or -x² -4x + 5 In order for there to be x intercepts the k term MUST be either the opposite sign of the a term OR k must equal 0. (otherwise you are taking the square root of a negative number. imaginary is ok for solving the equation, but it does not translate to the graph and it shows there is no x intercept) Made a couple mistakes and only caught them because I proved my equations. Always prove and show your work. If your teacher is worth their salt they will see where you are coming from and may advise you of where you messed up. Anyways it has been a long time since I've done this stuff and I only do them for fun to keep my brain sharp.

Man Is literally giving me 5 head math power

if the vertex is at the origin (eg, coordinates 0,4) is 0 still h and k still 4 or does it change?

Wait, my teacher said that you cannot have a negative sign of the value of a, but if it is negative sign, you need to change the sign of all value. Im so confused 😭🙏 Please answer

omggg i get it noww