Why Supply Independent Biasing with A Proper Startup?
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Пікірлер: 12
@waqas3049 Жыл бұрын
Thanks , very well explained
@circuitimage
Жыл бұрын
Hi Waqas, thanks for the feedback and I'm glad you liked it. 😀
@tranhuuthong079 ай бұрын
Great tutorial, thanks Sir! ❤
@circuitimage
9 ай бұрын
Hi Hữu, Thank you for the feedback and I'm glad that helps.😀
@ajithsrighakollapu35695 ай бұрын
this is really a great video and please do more videos and create the playlists also .
@circuitimage
5 ай бұрын
Hi Ajith, thank you for the encouragment and suggestion. Sure and I'll update the playlists.
@ajiths1689
5 ай бұрын
Okay great , if possible can you create the separate playlist for PMIC, Mixed-Signal IC design ?
@circuitimage
5 ай бұрын
@@ajiths1689 Hi Ajith, thank you so much for the suggestions. I'll do. :)
@surajkulkarni68682 ай бұрын
but what is the equation for current for supply independent biasing ? how to set the current ?
@circuitimage
2 ай бұрын
Hi Suraj, Thank you so much for your good questions. You can derive the equation by yourself. FYI: I've listed here: Iout = 2 / (unCox(W/L)) * (1/Rs^2) * (1 - 1/ SQRT(mirror factor))^2
@maomao861311 ай бұрын
Great thanks for your sharing, CC!
@circuitimage
10 ай бұрын
Hi Maomao, you're very welcome, and I'm glad you liked it. 😃
Пікірлер: 12
Thanks , very well explained
@circuitimage
Жыл бұрын
Hi Waqas, thanks for the feedback and I'm glad you liked it. 😀
Great tutorial, thanks Sir! ❤
@circuitimage
9 ай бұрын
Hi Hữu, Thank you for the feedback and I'm glad that helps.😀
this is really a great video and please do more videos and create the playlists also .
@circuitimage
5 ай бұрын
Hi Ajith, thank you for the encouragment and suggestion. Sure and I'll update the playlists.
@ajiths1689
5 ай бұрын
Okay great , if possible can you create the separate playlist for PMIC, Mixed-Signal IC design ?
@circuitimage
5 ай бұрын
@@ajiths1689 Hi Ajith, thank you so much for the suggestions. I'll do. :)
but what is the equation for current for supply independent biasing ? how to set the current ?
@circuitimage
2 ай бұрын
Hi Suraj, Thank you so much for your good questions. You can derive the equation by yourself. FYI: I've listed here: Iout = 2 / (unCox(W/L)) * (1/Rs^2) * (1 - 1/ SQRT(mirror factor))^2
Great thanks for your sharing, CC!
@circuitimage
10 ай бұрын
Hi Maomao, you're very welcome, and I'm glad you liked it. 😃