Thank you so much for illuminating how to do combined rate problems! I found these so confusing, but now I think I have a solid understanding and systematic approach. Thank you.

Thanks for sharing this Jeff.... It has cleared all of my doubts.

Thank you so much Jeff 🙏🏽

Hey, very clear examples! Please do more vids!!! :)

I love wrokig with charts. They just make sense to me

excellent explanation. Thank you!

great work jeff ! your work is seriously underrated

hey great job jefff You have been doing great Job Please further upload other concepts videos

wow, thanks for the explanation! your method is much faster :)

I find using the combined work formula: T = A.B / A+B is easier.

@Miftahul_786

3 жыл бұрын

Imagine using a second account to reply to your first comment

@jclarkmathclass9529

2 жыл бұрын

Yep, that's what I do.

Just did a video on this myself, on my Quant playlist.

Thanks ..It help me a lot.

Thank you

Sir..plz give more tough questions ..Thanks for this video..

Thanks alot jeff :)

many thanks

i wish you posted more often

Thanks !

Thanks alot :)

Very nice videos well done.. do u provide online classes?

Hi Jeff, How would I use the formula you've mentioned with this problem? Working together, 7 identical pumps can empty a pool in 6 hours. How many hours will it take 4 pumps to empty the same pool?

@wtyuocftsdf2168

5 жыл бұрын

Each pump's rate = 1/42. 4 pumps will take 42/4 or 10.5 hours

Hello Jeff, How can we apply the same above formula for the 700 + problem below, Lindsay can paint 1/x of a certain room in 20 minutes.what fraction of the same room can Joseph paint in 20 mins. if the two of them can paint the room in an hour, working together at their respective rates?

@MrAmbee007

6 жыл бұрын

lindsays rate=1/x by 1/3=3/x.rate of joseph can be calculated with the above formula to be 3/(3-x).now since we are asked for 20 min it would be 1/3-x. plz let me know if its right or wrong

@sapeduworld

5 жыл бұрын

Let assume x any value say 6 G paints 1/6 of room =20min G paints 1 room =120min G+J=60 min(last line) Taking LCM of both We get efficiency of B=1 To get fraction of room painted by J;take ratio.i.e.20/120=1/6.. Use options and use x as 6. If any option equals 1/6 that will be the answer.. Hope it will help you.

@wtyuocftsdf2168

5 жыл бұрын

Let 1/x be the fraction of the room that Lindsay can paint in 20 minutes. Let 1/y be the fraction of the room that Joseph can paint in 20 minutes. Lindsay's Rate= 1/(20x) rooms per minute Joseph's Rate= 1/(20y) rooms per minute Then from the Generic Equation we can write: 60/(20x) + 60/(20y) = 1 3/x + 3/y = 1 solving for 1/y we get 1/y= 1/3 - 1/x=(x-3)/(3x)

HARD