Wrong--You made two errors that just happen to cancel each other out. y1 = 3 + 3i√ 3 not y1 = 3 + i√ 3 x1 = 6 - 3 - i√ 3 = 3 + i√ 3 not = 3 - 3i√ 3

We can also solve it algebraically, may be in a quicker way. We know (x - y)² = (x + y)² - 4xy. That means, (x - y)² = 6² - 4 (36) = -108. So (x - y) = ± √ (-108) = ± 6√ (-3) = ± 6i√ 3. We have now (x + y ) = 6 and (x -y) = ± 6i√ 3. Therefore, x1 = ½ (6 + 6i√ 3) = 3(1 + i√ 3) and x2 = ½ (6 - 6i√ 3) , i.e = 3(1 - i√ 3). Using these values of x1 and x2 in eqn. (1), our y1 and y2 will be 3(1 - i√ 3) and 3(1 + i√ 3) respectively.

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This is a poorly presented straightforward application of quadratic equation.

There is a difference between how to solve and solve for x and y

No real solutions. Equation 1 squared is x^2 + 2xy + y^2 = 36. Eq 2 says xy = 36. Substituting this leads to x^2 + 72 + y^2 = 36. This becomes x^2 + y^2 = -36 This never happens in the real world.

@Alamaths

14 күн бұрын

Where did you see x² + 2 xy + y² =36? 😂🤣

@jamesharmon4994

14 күн бұрын

@@Alamaths that's x + y = 6 squared.

@Alamaths

14 күн бұрын

No

@Alamaths

14 күн бұрын

Please watch the video to see how I solved it. Thanks

@jamesharmon4994

13 күн бұрын

@@Alamaths I've seen this solved in other videos. Your solution proves there are no real solutions, only complex ones.