Congratulations for your video. Very well explained. It is difficult to find so good and professional plasticity explanations in internet. I’ve found out that the p-q diagram is very useful to visualize pressure dependency and to progress to Drucker-Prager models for example with tension-compression asymmetries.We are using more and more pressure dependent plastic models for metals in car crash finite element simulations. We need pressure dependent models to build up accurate fracture models.

Good Explanation. Appreciate the efforts to explain so nicely.

good one

Good explanation

excellent

great great

Thankyou

👍

@ 7.21 Why we are calculating the effective plastic strain rate tensor instead of effective plastic strain?

@engineering_software

Жыл бұрын

plastic deformation depends on loading history therefore the problem is solved incrementally.

in 11:28 , when calculating the normal (n), why did we divide by 2*sqrt(3/2 sigma':sigma') ?

@engineering_software

4 ай бұрын

Please note that we are making a derivation from sigma-e, which its definition contains square root.

@azz650

4 ай бұрын

@@engineering_software oh yes, thank you so much :)

Excellent Video I understand the concept of effective stress for various cases. how do you write effective stress equal to Sqrt(2/3 sigma':sigma'), any derivation is available?

@engineering_software

Жыл бұрын

2/3 can be found by this fact: In simple tension effective stress is equal to applied stress.

@selvamraj11

Жыл бұрын

@@engineering_software Thank you very much, This is my long-time doubt, it is clear Now. Still, I am wondering how they introduce the factor!

Hi, the equation of the linear hardening (time 2:44) does not match with the figure; the intercept of the line is less than sigma y.

@engineering_software

4 ай бұрын

Please note that in the formula plastic strain is used while in the curve horizontal axis shows total strain.