Thank you Krish for putting efforts to explain this concepts.

Really appreciate your efforts to upload this video... great explanation sir:)

Null Hypothesis = 5 Alternative Hypothesis = not equal to 5 Significance level = 2%,1-1% either side... Area under curve using positive z-score table = 1-0.01=0.99=2.33(As per Z-score positive table) Decision Boundary = +- 2.33 Z-score = -2.53 Since Z-test value is less than -2.33 i/e. it is in the negative rejection region , So we reject the null Hypothesis ..

@salmanshaikh5851

11 ай бұрын

Bhai mere ko to abhi bhi palle nai pada Kaha se tune sikha batai gake?

@hades840

6 ай бұрын

it is one tail test look there is underline on less

@harshshukla980

Ай бұрын

decision boundary 2.05

@sarveshpandey9047

Ай бұрын

2.33 kha se aya z table me to diya he nhi h

Sir, I am very thankful to you for this video.🙂😇

great krish respect so much value

thanks for Uploading in Hindi.....its much more understaniding.....

Decision boundry= +-2.33 Z score = - 2.52 Conclusion - if z score is less than -2.33 or greater than -2.33 then we reject null hypothesis. So -2.52 >-2.33 we Reject null hypothesis..

pmean = 5, std = 0.5, smean=4.8, n=40; null hypothesis = pmean = 5 alternate hypothesis = pmean C.I = 1-0.02 = 0.98 z = -2.52 where the decision boundry is -2.06 as per the z table. So, we failed to accept the null hypothesis and the warranty should be revised

@alex-vq1yy

3 ай бұрын

can you explain how decision boundary = -2.06 how you calculated CI please explain

the explanation is too good sir

I got decision boundary between -2.33 to +2.33, z-score= -2.529, We will reject the null hypothesis means workers believe is true.

@sumitkoshti1171

3 ай бұрын

Yes

Please complete the statistics playlist.

since our entire area under the curve value is = 1 -0.98 = 0.02 since it's left tail test.. out z test value =-2.52 2.52

@rajsinghtomar8090

4 ай бұрын

no confidence interval how i solve plz reply

@ashishvinod2193

4 ай бұрын

@@rajsinghtomar8090 if confidence interval was not given then by default assume 98% confidence intervals

@sumitkoshti1171

3 ай бұрын

@@rajsinghtomar8090 bhai significance value is given 2% which is equal to 0.02, and by using significance value you can find CI from the formula significance value = 1-CI, 0.02 = 1-CI, CI = 1-0.02 = 0.98 which is 98%

بہت آسانی سے مشکل کنسپٹ سمجھایا ۔شکریہ

@EjazUddin786

3 ай бұрын

Hanji bilkul

Hi Krish, is it standard that we should always go with Z-test when sample size is above 30?

Ho = average warranty is 5 years. H1= average warranty is not equal to 5 years. Alpha = 0.02(Here it's less than 5 years ,so it's one tailed.) Area under curve = 1-0.02 = 0.098 Decision boundry = +-2.06 Z-score = -2.52 So Ho is rejected. So, the worker was right I think. Bulb will malfunction in less than 5 years.

@souravsinha18

11 ай бұрын

yes it is correct but decision boundary should be -2.06 not + - 2.06

@hardikanandani7377

11 ай бұрын

Correct.

@sumiturkude1395

11 ай бұрын

@@hardikanandani7377 how did you find decision boundary.?

@shashi_kamal_chakraborty

8 ай бұрын

@@sumiturkude1395 It's 1 - alpha = 1 - 0.02 = 0.98. Now, z-table look up for 0.98. Which is found to be -2.06

@KartikSharma12364

4 ай бұрын

A chocolate company claims that their new recipe for dark chocolate bars increases the average cocoa content from the previous recipe. They conducted a study where they sampled 50 dark chocolate bars and found that the sample mean cocoa content is 85%. The population standard deviation of cocoa content is known to be 8%. Test the company's claim at a significance level of α = 0.05. Solve this problem

can you make a video on cohort and case control as well?

Continue Sir Continue me sahi time per aaya hu bcz mera abhi 15 ma tutorial chalra hai😂🤣

You are amazing

A chocolate company claims that their new recipe for dark chocolate bars increases the average cocoa content from the previous recipe. They conducted a study where they sampled 50 dark chocolate bars and found that the sample mean cocoa content is 85%. The population standard deviation of cocoa content is known to be 8%. Test the company's claim at a significance level of α = 0.05. Anyone solve

for decision boundry i use this : for 2% significane 1-1 on both sides 1/100=0.01 , 1-0.01=0.99 and in z table value of 0.99 is 2.33 means +2.33 on right and -2.33 on left pls tell me am i correct ?

@rajatjuneja8367

4 ай бұрын

yes sir

This topic is For Data Analytics or Data science ??

I have a doubt, From other definitions I think that If we have the population standard deviation we can directly move for z test since we are concerned about the sample size only when we are talking about the sample standard deviation as for n>30 sample and population SD are similar. So, I think the flowchart would be a little different. Can anybody clarify this doubt please??

@harshitgupta6452

28 күн бұрын

Yes you are correct

Please complete full playlist

U = 5 sd = 0.50 n = 40 x bar = 4.8 so area = 1 - 0.02 = 0.98 z_value will be 2.06 (dission boundry) 4.8 - 5 ----------- 0.05 * root 40 = - 2.52 we reject the null hypotheses the worker was right

Null Hypothesis = Mean = 5 Alternative Hypothesis = Mean not equal to 5 Significance level = 2%,1-1% either side... Area under curve using positive z-score table = 1-0.01=0.99=2.33(As per Z-score positive table) Decision Boundary = +- 2.33 Z-score = -2.52 Since Z-score falls in the negative rejection area...we reject the null Hypothesis!!!

@rokhaiyasultana9728

11 ай бұрын

i got the sme ans!!

@souravsinha18

11 ай бұрын

No it is not a 2 tailed test so alternative hypotheis should be mean less than 5 years

@salmanshaikh5851

11 ай бұрын

Bhai mere ko to abhi bhi palle nai pada kaha se tune sikha pata gake?

@sauravjha1714

11 ай бұрын

@@souravsinha18 check your answer... My answer is perfectly right!!

@souravsinha18

11 ай бұрын

@@sauravjha1714 no bro I did this I am sure this is right why are u taking 1-1% on both sides when the worker says that the bulb lifetime will decrease you should take it on decreasing side and then calculate it

Thank you for such an amazing lecture

@KartikSharma12364

4 ай бұрын

My decision boundary is not getting correct ,can you help me

@manjeshtiwari7434

4 ай бұрын

@@KartikSharma12364 what's issue?

@manjeshtiwari7434

4 ай бұрын

@@KartikSharma12364 if accept area is 98 how can be reject 49 and 49, out of 100 98 is accept area so we have 1% reject area on both side u need to rewatch

@KartikSharma12364

4 ай бұрын

@@manjeshtiwari7434 what's the correct answer of decision boundary and z test

@KartikSharma12364

4 ай бұрын

​@@manjeshtiwari7434decision boundary=2.33

make more video correlation regression and probability in stats

V nice Sir

sir what do we do when we do not have a 2 tail test condition ??

Here bulb manufacturers question is a one tail test question because , worker believe that bulb will malfunction in less than 5yrs . So Null hypothesis= H0 = 5yrs alternate hypothesis = H1

Sir kal paper hai aur ye pura samajh hi nahi aa raha tha, thank you🙏

(Z Test = -2.53)H0 has been rejected as (Z test VAlue is not in C.I range/Decision Boundry) so worker believe is correct.

wait for course completion !

Sir please stat ki playlist continue rakho

Please complete the statistics playlist

Sir konse video ha hypothesis check karne wali

Sir how formulas are derived?

Hare Krishna 😊 Thank you so much for this vidoe 😊😊😊

Thankyou so muchh,such a nice explaination!! best video for Hypothesis testingg......🤌

Hello sir thank you for explaining You have mentioned in conclusion if z test is less than 1.96 or greater than 1.96 then we reject Null Hypothesis but as results came 2.31 which is greater than 1.96 so we should accept the Null Hypothesis. I am now confused can you please clarify thanks in advance

@itshimanshucreation8076

8 ай бұрын

Bro unhone bola hai ki we accept to reject the H0 if z test is lessthen or greater then 1.96.

@vedchaudhari6587

5 ай бұрын

if it lies in range of 1.96 and -1.96 then accept it else for anything either greater or smaller , reject it.

Sir anova test pr video banao baki ke saare test statistic 7 days live me hue he cover pr anova test nahi hua he

Fabulous sir ..can I contact personally

please continue video on ml

if population standard deviation is given and sample size is less than 30, then Z test???please clarify.

@robinsunuwar6852

3 ай бұрын

you should go with t test if the sample size will be less than 30 we have to perform t test its basic rule.

Sir CHI SQUARE AND ANNOVA KA VIDEO Bna dein mera paper ha iska next month 10th november ko

Why do we consider sample size 30 for differentiating between Z test and T test. Why not some other number ? Why not 'x' percentage of the population ?

@raufurrahim878

Күн бұрын

30 data points should provide enough information to make a statistically sound conclusion about a population. This is known as the Law of Large Numbers, which states that the results become more accurate as the sample size increases. The 30 is a rule of thumb, for the overall case, this number was set by good statisticians.

Is This playlist enough to learn statistics for data analytics ?

@Prashantchaudhary-kf1fb

4 ай бұрын

yes bro

next video pl. sir

pls provide lecture notes

If std not given and sample size more thn 30,thn which test is to be used?

@CrocksJam

4 ай бұрын

if population std mean not given then we use t-test directly

Sir what about f test

Paired and unpaired ka concept????

According to my calculation HO is accepted

Do any one get the z test value?? I'm getting my z test value which is +0.037 and decision boundary values as +3.1 and -3.1 , So i have to accept the null hypothesis Do anyone get any answer??? Sir am i correct??

@sumitkoshti1171

3 ай бұрын

Nope, Decision boundary is +-2.33 and Z test value is -2.53, As -2.53

For a two-tailed test with a 98% confidence interval, you would use 0.01 (or 1%) for the purpose of arriving at the z-score. This is because the remaining 2% is split equally between the two tails of the distribution, leaving 1% in each tail. So, you’d look up the z-score that corresponds to an area of 0.99 in a standard normal distribution table. However, for a one-tailed test with a 98% confidence interval, you would use 0.02 (or 2%) to find the z-score. This is because the entire 2% is located in one tail of the distribution. So, you’d look up the z-score that corresponds to an area of 0.98 in a standard normal distribution table. When in doubt, it’s generally safer to use a two-tailed test. This is because a two-tailed test is more conservative and does not assume a direction of the effect.

Actuall fanda ya to kisi ko pata nahi hai ya wo samjhane me inko takleef hai. Maths bhi theory ki tarah padha rahe hai😂

"promo sm" 🤗

Worst tutorial for z test This should not take more than 7-8 mins. Pls don't go into so much detail. Instead you would have solved 4-5 problems in 25 min.