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Trusses Method for Beginners to Understand | Basic Fundamentals to understand about FEA | Part-01

Basic trusses problems with solutions in fem.
#featrusses
#basicconceptoftrusses
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Пікірлер: 25

  • @necromancer3362
    @necromancer33624 жыл бұрын

    i m studying mechanical engineering in North Maharashtra University, Your lectures cleared my concepts about this subject..

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Thank You So Much, It's my pleasure..🙏

  • @onyiboemmanuel6060
    @onyiboemmanuel60603 жыл бұрын

    You are doing a great Job on us. Thanks a lot Sir.

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    pleasure. .🙏

  • @semihtuncer12
    @semihtuncer123 жыл бұрын

    Thank you so much ..

  • @manas4653
    @manas46534 жыл бұрын

    I am studying Civil engineering in VGTU which is in a European country called Lithuania and i just wanted to say your videos are very helpful, I hope your channel grows more .Good luck and thank you.

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Thank You So Much for your Wishes and Support.

  • @user-cs9mi7vd6c
    @user-cs9mi7vd6c Жыл бұрын

    Wonderful

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Жыл бұрын

    🙏💕

  • @prashantshelke9314
    @prashantshelke93144 жыл бұрын

    ‌A hollow shaft whose internal diameter is half of the external diameter is subjected to maximum bending moment of 2KN -m at a section and constant torque of 4KM-m all along its length. If yield stress of the material is 280 MPa and factor of safety is 3.0, what should be minimum safe diameter of shaft?

  • @kochatube4513
    @kochatube45133 жыл бұрын

    hi Dear Mahesh, I appreciate the way of teaching style and the detailed understanding of the concepts, especially for FEM analysis. Dear, Mahesh I want to ask one question. my questions related to spring elements. in the case of the one-dimensional spring element, some problems are assembled by spring, in this case, the stiffness of the spring is directly given. dear Mahesh is that the value of the spring is evaluated by this formula 8fd3n/gd4 or all of the spring element is changed into equivalent spring element evaluated by EA/L formula. the other question, how to differentiate a two-dimensional element from plate and shell elements b/c they are also 2D elements. thank you, I am waiting for your answer.

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    Please visit the Channel Description for more information

  • @yogeshkadam8160
    @yogeshkadam81604 жыл бұрын

    अप्रतिम सर...तुम्ही स्पष्टीकरण चांगले करता...👍

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Could you please translate into English

  • @yogeshkadam8160

    @yogeshkadam8160

    4 жыл бұрын

    @@MaheshGadwantikar awesome sir...good explanation..

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Oh ...!! Thank You, Yogesh..

  • @HAPPYKUMAR-jd2bc
    @HAPPYKUMAR-jd2bc3 жыл бұрын

    thnks sir ...............

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    👍 All the Best

  • @ankurupadhyay7731
    @ankurupadhyay77314 жыл бұрын

    Hello Sir, Hope you are fine.... Sir plz...can you make some videos releted to CFX & CFD

  • @MaheshGadwantikar

    @MaheshGadwantikar

    4 жыл бұрын

    Hello Ankur, Thank You for your valuable feedback. I will come up with CFD shortly

  • @ankurupadhyay7731

    @ankurupadhyay7731

    4 жыл бұрын

    @@MaheshGadwantikar i am waiting sir

  • @iamchandrasekharreddy2294
    @iamchandrasekharreddy22943 жыл бұрын

    sir (L=x2-x1/length of the element) but you said L=x2-x1/2

  • @MaheshGadwantikar

    @MaheshGadwantikar

    3 жыл бұрын

    What you said it's correct. X2-x1/ length of the Element

  • @mitchellberends103
    @mitchellberends103 Жыл бұрын

    Where is part 2 of this video?

  • @MaheshGadwantikar

    @MaheshGadwantikar

    Жыл бұрын

    I think no part 2 for this