Why my maths teachers can't be this patient while explaining..?!

@jaysong3256

4 ай бұрын

Cause not every student understands this. They will be more confused :))

Thanks sir for u valuable lessons It's made easy to solve this type of questions I spent 20- 30 minutes to solve the 1 st one but after practicing 2 ,3 questions now I am able to solve this in just 2-3 minutes 🙏❤️🙏❤️🙏

Shit, if you were my math teacher during my highschool days. I would have secured some good marks. 😂

Way of explaining the concepts is awesome!

1.) I simply pre-memorized all 366 possible dates as a value from -3 to 3. 2.) Then I just add that to one of the 4 possible century codes of 2,0,-2, or 3 (7 possible century codes for Julian from -3 to 3) and finally, 3.) Add that to a pre-memorized value for each of the 100 years from 00 to 99. For example, my birthdate of March 19, 1982 goes: -2+3-3=-2 so Friday! Or shortcutting, I just cancel the 3 and -3, and -2 is Friday! The fastest way to do this is to pre-memorize all 100 year values from 00 to 99. Then I just add that to the century code and finally add that to a pre-memorized value for each of the possible 366 dates (these 3 values can be added together in any order you like). For example, June 15, 2012 would simply be: 2+2+1=5, so Friday! June 15 always has a value of 2 (pre-memorized) 2000's has a century code of 2 and, year 12 always has a value of 1 (pre-memorized) 2+2+1=5, Friday! Anytime leapyear happens just subtract one from the answer for January or February only, all other months stay the same! I calculate any day of the week using my method in less than a second, almost instantly to 2 seconds tops if I'm thinking a bit. I do both the Julian and Gregorian calendars in both AD and BC infinitely into the past or the future.I do other cool tricks that aren't heard of very often, for example since this calendar math can be viewed as just a simple addition problem, we can also solve for a missing value using subtraction! For example, if we already know the day of the week to be Friday for example, we can solve for a possible month/months or even a date from 1 to 31 or even a possible year or century. Example: Which month or months did Friday the 13th fall on in 1899? 1899 was a Tuesday year (-2+4=2) or (5-3=2). So, Tuesday was the 10th since 3 days later was Friday the 13th. So, 2+13+x=5 (Friday) x=4 because 15+(-10)=5 -10+14=4 Mod7 arithmetic Only January and October had a month code of 4 😁. So it only happened twice that year, in January and in October. Also we can say more intuitively that since 1899 was a Tuesday year, and Friday being 3 days later, which month/months had the Doomsday of 3,10,17,24,31? and obviously that is only January and October. If the question changed to what were all of the Fridays in January and October for example in 1899? We can say "the 6th, 13th, 20th, and 27th" If someone were to instead ask for example on Friday the 13th from 1883 to 1900 what year/years did that happen? We can say "only in 1893 and 1899" In this situation we just needed to find the missing year code of (4 or -3) and only 93 and 99 have that year code in that date range. Likewise, we could have instead solved for the century 😉 also if already given a year.

@surajmahale4187

Жыл бұрын

Great man !! can you share pre memorized values. i'm very excited

@surajmahale4187

Жыл бұрын

Can you please teach me your technique I'll be grateful forever.

@victorynews6184

Жыл бұрын

Sir i dint understood ua method,, aggarwalz sir tricks also much complicated , plz explain once

@thecalendarninja

Жыл бұрын

@@surajmahale4187 Grab any common year (not a leap year) calendar you can write on. Starting on January 1 write -2, then January 2 write -1, then January 3 write 0 The pattern goes -2,-1,0,1,2,3,-3 repeat all the way until December 31 which has a value of -2. Century Codes: 1600's, 2000's, 2400's and all multiple of 4 centuries: code 2 1700's, 2100's, 2500's and so on code 0 1800's, 2200's, 2600's and so on code 5 or -2 1900's, 2300's, 2700's and so on code 3 Year codes: *00 code 0 01 code 1 02 code 2 03 code 3 *04 code 5 or -2 05 code 6 or -1 06 code 0 07 code 1 *08 code 3 09 code 4 or -3 10 code 5 or -2 11 code 6 or -1 *12 code 1 13 code 2 14 code 3 15 code 4 or -3 *16 code 6 or -1 17 code 0 18 code 1 19 code 2 *20 code 4 or -3 21 code 5 or -2 22 code 6 or -1 23 code 0 *24 code 2 25 code 3 26 code 4 or -3 27 code 5 or -2 *28 code 0 29 code 1 30 code 2 31 code 3 *32 code 5 or -2 33 code 6 or -1 34 code 0 35 code 1 *36 code 3 37 code 4 or -3 38 code 5 or -2 39 code 6 or -1 *40 code 1 41 code 2 42 code 3 43 code 4 or -3 *44 code 6 or -1 45 code 0 46 code 1 47 code 2 *48 code 4 or -3 49 code 5 or -2 50 code 6 or -1 51 code 0 *52 code 2 53 code 3 54 code 4 55 code 5 or -2 *56 code 0 57 code 1 58 code 2 59 code 3 *60 code 5 or -2 61 code 6 or -1 62 code 0 63 code 1 *64 code 3 65 code 4 or -3 66 code 5 or -2 67 code 6 or -1 *68 code 1 69 code 2 70 code 3 71 code 4 *72 code 6 or -1 73 code 0 74 code 1 75 code 2 *76 code 4 or -3 77 code 5 or -2 78 code 6 or -1 79 code 0 *80 code 2 81 code 3 82 code 4 or -3 83 code 5 or -2 *84 code 0 85 code 1 86 code 2 87 code 3 *88 code 5 or -2 89 code 6 or -1 90 code 0 91 code 1 *92 code 3 93 code 4 or 03 94 code 5 or -2 95 code 6 or -1 *96 code 1 97 code 2 98 code 3 99 code 4 or -3

@thecalendarninja

Жыл бұрын

@@surajmahale4187 Grab any common year (not a leap year) calendar you can write on. Starting on January 1 write -2, then January 2 write -1, then January 3 write 0 The pattern goes -2,-1,0,1,2,3,-3 repeat all the way until December 31 which has a value of -2. Century Codes: 1600's, 2000's, 2400's and all multiple of 4 centuries: code 2 1700's, 2100's, 2500's and so on code 0 1800's, 2200's, 2600's and so on code 5 or -2 1900's, 2300's, 2700's and so on code 3 Year codes: *00 code 0 01 code 1 02 code 2 03 code 3 *04 code 5 or -2 05 code 6 or -1 06 code 0 07 code 1 *08 code 3 09 code 4 or -3 10 code 5 or -2 11 code 6 or -1 *12 code 1 13 code 2 14 code 3 15 code 4 or -3 *16 code 6 or -1 17 code 0 18 code 1 19 code 2 *20 code 4 or -3 21 code 5 or -2 22 code 6 or -1 23 code 0 *24 code 2 25 code 3 26 code 4 or -3 27 code 5 or -2 *28 code 0 29 code 1 30 code 2 31 code 3 *32 code 5 or -2 33 code 6 or -1 34 code 0 35 code 1 *36 code 3 37 code 4 or -3 38 code 5 or -2 39 code 6 or -1 *40 code 1 41 code 2 42 code 3 43 code 4 or -3 *44 code 6 or -1 45 code 0 46 code 1 47 code 2 *48 code 4 or -3 49 code 5 or -2 50 code 6 or -1 51 code 0 *52 code 2 53 code 3 54 code 4 55 code 5 or -2 *56 code 0 57 code 1 58 code 2 59 code 3 *60 code 5 or -2 61 code 6 or -1 62 code 0 63 code 1 *64 code 3 65 code 4 or -3 66 code 5 or -2 67 code 6 or -1 *68 code 1 69 code 2 70 code 3 71 code 4 *72 code 6 or -1 73 code 0 74 code 1 75 code 2 *76 code 4 or -3 77 code 5 or -2 78 code 6 or -1 79 code 0 *80 code 2 81 code 3 82 code 4 or -3 83 code 5 or -2 *84 code 0 85 code 1 86 code 2 87 code 3 *88 code 5 or -2 89 code 6 or -1 90 code 0 91 code 1 *92 code 3 93 code 4 or 03 94 code 5 or -2 95 code 6 or -1 *96 code 1 97 code 2 98 code 3 99 code 4 or -3

All this in one take, with such great explanation skills, is truly commendable. Keep up the great work sir.

@bindu277

3 жыл бұрын

😄

@bindu277

2 жыл бұрын

@Fashion Hub kaha pr?

@sureshaggarwal

Жыл бұрын

Thanks a lot

Such a great video, I was searching for the same method for so long when I got your video sir ❤ Now the topic is clear 🔮 Thanks a lot sir 😊❤

Understood the concept extremely fast. Thank you so much, sir. Very well explained 😊😊

Very good explanation, this the only video I find without a table to be remembered, your work is appreciated sir, keep on doing the same

@answhiganswhig377

4 жыл бұрын

Exactly ! because he explains the logic of it. So you don't need to memorize figures you can get them by yourself 🤗

Just fantastic. Very clear explanation. Thank you very much

Thank you sir you literally saved me bcz after 3 days I had my exams and I was really scared but after watching your video I understood the concept very well

The video is very helpful for me. many many thanks to you sir. but I have a question. when you divide a century by 4, you minus by 1 of the result . you explained that 100 is not a leap year. my question is should we minus by 1 if the year is not divisible by 400 ??

The best explanation. I was so confused regarding this topic bt you explained it so well. Thank you so much for clearing my doubt.

Very good explanation sir ! Saw a similar question come in my bitsat mock test and when i saw it i got worried , though i am not worried anymore because of you! Thank you sir. 😄

Such a wonderful video I was searching from many years

Not only for children appearing for competitive exams, these tricks can help adults too. Great videos Sir !

@rojnibibi2975

Жыл бұрын

L

Easly understood sir ..nice way to explain the concepts...

Very helpful. Concise explanations and straight to the point with no background music. Just plain mathematics. Love it.

you made the concept so clear, thank you sir i understood the calendar problems :)

Sir actually I was a fan if the channel dear sir and there I found out the same trick as here but was not able to understand it now by chance I came across this channel and now I was able to understand that trick. Thank you sir from the bottom of my heart

Sure this works, but here's a simpler method that works for years 1900-2099. You only track one number throughout this method which makes it easy to do quickly in your head. The key is doing the mod 7 (remainder after dividing by 7), you can apply it any time to any number after step 2 through the calculation. 1) Subtract 1900 from the year. 2) multiply that number by 1.25 (add a quarter), round down, if its a leap year subtract 1. Reduce to mod 7. 3) walk through the completed months of the target year and add the mod 7 for that month (31 days=3, 30 days=2...). Reduce to mod 7. 4) add the target day of the month (or the mod 7 of it) and get the mod 7 for the sum. This is your day of the week (0=Sun, 1=Mon,.. 6=Sat). Here's an example for a date later this year, 2019-06-21. 1) 2019-1900 = 119 2) 119 + 29.75 = 148 (rounded down), 148 mod 7 = 1 3) 1 + 3 (Jan) + 3 (Mar) + 2 (Apr) + 3 (May) = 12, 12 mod 7 = 5 4) 5 + 21 = 26, 26 mod 7 = 5, Answer is 5 - Friday (if you prefer, 5 + (21 mod 7) or 5+0) For 1960-03-01 1) 60 2) 60 + 15 - 1 (leap year) = 4 (after mod 7) 3) 4 + 3 (Jan) + 1 (Feb) -> 1 (after mod 7) 4) 1 + 1 = 2 = Tuesday This method works because of 2 factors. Jan 1, 1900 is a Monday (day 1 on date 1), and in that year span there are leap years every 0.25 years so you can calculate your "odd days" with the multiply by 1.25 trick. The other advantage to this method is that it doesn't require any memorization other than the method itself and the number of days per month.

@CuratedPile

5 жыл бұрын

I had @Sunanda Alapati reply to my comment, but I can't see it anywhere other than my notification. The question was about January 1, 2099 coming up as a Thursday using my method and Sunday using the video method. The correct day of the week is Thursday, I get that with either method, I don't know why you are getting Sunday. For the video method, you have no odd days for the century, 122 odd days for the year (74 normal years, 24 leap years) and 1 more day for the 1st. That leaves a 4 as the remainder which is Thursday.

@yashrupani1608

5 жыл бұрын

@Sunanda Alapati by the video method : 2099 2000 = 0 odd day 98 = 24x2(98/4*2odd days for leap year) + 74(1odd day for normal year)= 48+74 = 122 @ 122/7 odd day = 3odd days . Jan 1 = 1odd day .. i.e; 3odd day + 1odd day = 4odd day = Thursday ---- SOLUTION BY VIDEO METHOD

It is really very helpful sir. thank u so much

Good one i got a clear understanding of the concept, god bless this channel

What if when u add the odd days, it adds to a number less than 7. Because then you have no remainder then meaning no odd days

Well explained Thank you very much

I had no idea of odd days and even days before ... Now I got the clear idea.... Good explanation sir

I found exactly what I needed. Those videos with month codes were frustrating, but this solution is simple and doesn't require memorization. Thanks sirr!❤

Thankyou very much for helping out the basics with clarity

Now I can find the day of the week of a given date easily....thank you...

Thanks sir. You cleared the Concept. It's better to understand the Concept rather than going for shortcuts.

Thank you so much sir... I got each and every concept...!!

100% Working. Taking very less time after Practice

Can u please make our CSAT preparation easy by solving the PYQ by using easy tricks ❤️🙏❤️

Sir, you are best and precise in what you teach. Thank you so much for helping us understand this concept so easily and quickly. Thank you so much for your contribution and hard work. I will keep following you and learn from you. Thank you again. Your faithful student

have you made a video for writing a series using sigma and pi notation?

Thanks for posting such an informative video, Mr Aggarwal.

very helpful sir...thank u so much for this amazing trick and session

When i watched this vdo immediately i subscribed your channel. Then i wanted to know whether you are still making vdo s or not. So i went through your channel and saw your recent posts. It made me very happy because the world needs the teacher like you. I’m highly impressed by the way you make clear the concept. You are a real and true teacher. Please continue teaching online. The learners from abroad too can benefit from you.Thank you and best of Luck.

Thank you so much sir for this concept

a best explanation to understand these type of competitive problems

you the best teacher compared to the highly paid teachers in the coaching centres like carrer launcher,aakash etc you made my concept crystal clear thank you so much sir i was worried because i was not able to grasp the concept in carrer launcher in 4 long hours and i was searching on the internet for the exact same method for whole 1 day

@deepakydv209

2 жыл бұрын

Go on career will

@vijayasreevemula3028

2 жыл бұрын

Y

@nagajothijothi4772

Жыл бұрын

Ml

@RehanKhan-vc1bc

Жыл бұрын

I0jlqp0q7

@RehanKhan-vc1bc

Жыл бұрын

I0jlqp0q7

absolutely 💯💯 well explained concept

The Doomsday method (1970 Conway) requiring 3 tables, one sentence and two divisions by 4 and 12 and 3 additions is far easier/faster and much more versatile as it also gives anchoring dates...

@sureshaggarwal

6 жыл бұрын

Thanks for that....will try it.

@GoldenElixir8971

4 жыл бұрын

Too much to memorise and less to understand in doomsday

@jbsstudy1541

2 жыл бұрын

@@sureshaggarwal sir 2000 aru 2001,2002,2003 year ka keise

Thank-you sir very much fascinating trick

it was truly well explained. but in my opinion i dont really think i can do it without a paper and pen. and this takes a little bit more time then it should. still i learn quite a lot from this and i am thankful for that.

The method is good. Thanks for posting. I would like to understand the concept behind the odd days. I mean, the concept behind the circle ( 0-Sun, 1-Mon, 2-Tue ....). Why is 0 always a Sun and 1 always a Mon. It would be great help if you can provide an explanation behind this.

@themasterji8252

5 жыл бұрын

0 means 7 . When 7 is divided by 7 the remainder is 0 . 0=sunday is a serial number. I use 0 as saturday and use codes January as 0 February as 3 and so on. I can explain to you how January is 0 feb is 3 march 3 April 6 etc.

@robertowens6654

5 жыл бұрын

Odd days denote the number of days after completing any number of week cycles. We could say that *A week starts on Monday and ends on Sunday by this concept.* When you say year 2000 has 0 odd days it means by the end of the year, an exact number of week cycles has been completed. Which tells us that December 31 is a Sunday. A new week starts on 1 Jan 2001 (1odd day= Monday.) By the next day there would be 2 odd days which means it's the second day of a new week therefore Tuesday and so on.

great video ...thanks a lot sir

Outstanding explains.

Gd afternoon Sir! Though it is complicated, you explain so well,any lay man can understand. All d best. Tc.

@sureshaggarwal

4 жыл бұрын

WhatsApp 9896369963 for PDFs of short tricks

Way of explaination was really outstanding sir

Wonderful trick sir Thank you very much

TQ you so much sir

Thank you sir for all concept cleared in one video....

Sir you are the best Thank you so much

Thank you so much sir🙏

Kuch log kya kya tricks yaad karwa dete he, but this video is fully conceptual and remember for a long time, thank u

This is a normal method but explanation is simple. It is good for beginners..

Ek number..gajab

Sir I liked the video very much. The explanation was amazing , I learnt this trick after watching this video two times. Please upload more interesting tricks . Thank You

Thank you so much sir for the best explanation 🙏🙇‍♂️

Great.... Amazing, step by step, without any trick or jumps, very cool..

Really helpful, thanks a lot sir

very helpful sir thank you👍👍

Ty sir your method of doing this is really easy and there is no need to remember any code

Thank you 😊😊😊

Sir, you are great

thanks u sir❤

Thank you sir🙏. I am thinking why didn't our teachers teach these techniques when we were learning it for the first time. Then Life would be so much easier now

I don't think I can do it in 15 seconds. I lost track in the middle.

@AmarjeetNagra

4 жыл бұрын

Same here

@Abhirami1620

4 жыл бұрын

I lost trick at 7;52 sec

Calendar which are having the same calendar “Ordinary years” - after every 6 or 11 years. Leap years- after every 28years. Same calendar will be repeated!!

@dhiraj.govindvira

5 жыл бұрын

Hey, please help 1-11-2020 2020 = 2000 + 20 2000 ->> 0 20 ->> 5 leap + 15 normal so , 10 +15 = 25 25 % 7 = 4 odd days now , 3 + 1 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 1 = 26 26 % 7 = 5 so , total = 0 + 4 + 5 = 9 9 % 7 = 2 by 2 its tuesday but it's a sunday ???? why ???

@gaingamgangmei7887

5 жыл бұрын

Dhiraj ,, let’s us understand that the month is given till Nov which is incomplete year of 2020. For the calculations we have to take complete year ie2019 as per rule 2019 2000 + 19 /4 ( 4 leap year and 15 ordinary years 0+(4x2+15x1)+3+1(lepyears)+3+2+3+2+3+3+2+3+ (***1) 8+15+26= 49/7 = O odd day ie Sunday Follow my method times less consume to be honest Sir method is quit complicated (***) given date may be 15,17,25,35etc whatever may be always divided by 7( applicable when it’s (= or greater than 7) and put the remainder in that month..

@debkumarbose5683

4 жыл бұрын

I can't find the day of 19/01/1988

@musaed11

4 жыл бұрын

@@dhiraj.govindvira you shouldn't count the number of years as 2020 but 2019. so 2000>>0 and 19 >> 15 normal+ 4 leap = 15+8= 23----> 23 mod7=2 instead of 4 and then do the rest and it will sunday

@thebammer5166

4 жыл бұрын

@@debkumarbose5683 Tuesday. I don't need a perpetual calendar to tell me that when i already have one in my head.

Thank your Guruji, I can understand only in this time.

Really perfectly explain

This explanation is very clear, perfect, thanks for your patience.🤗 But I have a question : what is the use of knowing what day was what date ? 😉😉

@sureshaggarwal

4 жыл бұрын

Come and attempt a competitive exam in India....you would require no answer for your question 😄😆

@nihaal7750

3 жыл бұрын

Lol we have this in our exams moreover isn't it a fun skill to have anyway?

@kalia3364

2 жыл бұрын

@@sureshaggarwal 😀

Agarwal sir can you please explain the 14 - 7 - 2010 When I solve the above problem I get the answer as per your theory Thursday but actually answer is Wednesday. Please clarify my doubt

@ALLINDIAVIDEOS123

4 жыл бұрын

Watch my method

@vishnu_pradyu

4 жыл бұрын

no it comng wednesday only do it again

@niharikagamedhar1612

4 жыл бұрын

Even I got Thursday for the mentioned date.

@vishnu_pradyu

4 жыл бұрын

@@niharikagamedhar1612 no do it precisely you will get thursday

@proudly123

4 жыл бұрын

It's Wednesday 3 comes as answer

Hello does this work for any date in 1752. For example September 14, 1752?

Suresh, you are superb. Maths is so much fun with your tricks.My son loves them

watching this from Boston right now. Jai hind 🇮🇳

very good explanation sir. after understanding actually it can be solved in about 15 seonds

This is the best explainatory video on this topic. Thank you so much Sir.

sir thank you so much . great explanation

Hi sir, Can u pls check this date 06-08-2019 As per trick i got wenesday But actualy it is tuesday in the callender

@sandyy55555

6 жыл бұрын

Jayaraj V P At 2000= 0 odd days So we have 18 yrs and 8 months and 6 days In 18 yrs, 4 yrs are leap yr So we have 4*2= 8 And 18-4= 14 14+8= 22 odd days till 2018 And remaining 8 month and six days are 3+0+3+2+3+2+3+6=22odd days So we have total 44 odd days So we get 44/7= 2 reminder which is *TUESDAY*

Sir, Can u plz explain the same for 31/12/2017 as i am getting a different answer

@khatri9303

6 жыл бұрын

Kashif A kg tar 1)2000-0 odd days 2)2000-2016 = 4 leap years and 12 normal years = 12 +8(4×2) =20 odd days 3)till 31 december = 3+0+3+2+3+2+3+3+2+3+2+31=57 0+20+57=77 =77/7=0 odd day it was sunday

you are truly extraordinary sir........thank ful to you sir...always.......

Sir, based on your concept the day for date 22-02-2020 is coming Sunday, (D22+M4+ C6+Y20+Q5= 57/7 remainder is 1 and as per your week num. It is Sunday) where as 22-02-2022 is on Saturday.. please solve..

Thank you sir i was searching for this method.

@sureshaggarwal

4 жыл бұрын

Do share the links with your WhatsApp groups and contacts

Hello , may I ask? Why is 0 = Sunday, 1 = Monday, 2 = Tuesday, ect ? Thank you so much for your Trick .

@atulsain6170

6 жыл бұрын

Kristianto Raharjo because it was Monday on 1-1-1. :)

@Hongsen

6 жыл бұрын

This is predefined by calendar system we follow ( gregerion calender ) .

@gaingamgangmei7887

5 жыл бұрын

The initial Gregorian calendar 1-01-01 Monday..

@answhiganswhig377

4 жыл бұрын

Because when God created the world he finished his work and relaxed on the last day of it was a Sunday point of origin of the world, then the full process started to work on the next day the first day n°1 the Monday 😉 No i'm joking... But it works, right?

@chidanandapoojari1117

2 жыл бұрын

@@answhiganswhig377 😂😂😂

Thanks a lot sir..you made it very simple and effective...

Thankful to you

This is one of the hard question in competitive exams.This trick is very beneficial for me .

@themasterji8252

5 жыл бұрын

I could help you to fo it in 5-6 seconds. And For me it takes 1-2 seconds

@dhiraj.govindvira

5 жыл бұрын

@@themasterji8252 how ??

Well, I can't do that in 15 seconds, but here's my approach. After using it many times, I can "think" it a lot faster than I can explain it. 1956 Aug 15 = what day-of week (DOW)? Every 28 years there's an exact repeat of the calendar (so long as no Gregorian century non-leap year is crossed; last one was 1900; next is 2100, so we're safe here). 1956 + 2·28 = 2012; so 1956 Aug 15 = 2012 Aug 15 And every forward jump of one year adds one DOW, so long as no leap day (LD) is crossed. Each LD adds one additional DOW. That means that jumping to the same date, either 5 or 6 years forward, preserves DOW, depending only on how many LD's are crossed (5 y + 2 LDs or 6 y + 1 LD, makes 7 days either way = same DOW). August 2012 is just past a LD. So 2012 Aug 15 + 6 years = 2018 Aug 15 has the same DOW. Now as I write this, it is Jan. 12, 2019, Saturday. Add 3 days to make the day-of-month match: 2019 Jan 12 Sat. + 3 days = 2019 Jan 15 Tue. Now go back to August 2018, for which we must add the days of Dec. backward through August: 31 + 30 + 31 + 30 + 31 = 153 = 7·22 - 1 so subtracting those 153 days, adds one to the DOW. Therfore, 1956 Aug 15 was Tue + 1 = Wednesday. This doesn't show how to do a general DOW problem, however. For that, I have a number of other tricks; such as which months within a calendar year, match: Non-Leap: Jan = Oct Feb = Mar = Nov Apr = July Sep = Dec May, June, and Aug, don't match any others. Leap: Jan = Apr = July Feb = Aug Mar = Nov Sep = Dec May, June, and Oct, don't match any others. Always: May = the following Jan June = the following Feb When the latter year is non-leap: Aug = the following May Sep = the following June Oct = the following July Nov = the following Aug For longer-range problems, you must take account of missing leap days in those Gregorian exception years - century years that aren't 400-divisible. And that the Gregorian calendar repeats every 400 years. (Because 400 Gregorian years = 146097 days = 20871 weeks.) Anyway, this is just what works for me; and although it may not work for you, if it does, go ahead and use it. A few additional notes: 1) A lot of what Suresh is doing here is based on mod 7 arithmetic; if you know how to do that, a lot of his explanations can be greatly simplified. Of course, he's assuming an audience many of whom aren't familiar with modular arithmetic, so he couldn't make those simplifications. 2) If you have access to a JDN (Julian Day Number) calculator, you can just convert the date in question to JDN, then take that mod 7. That remainder corresponds to: 0=Mon, 1=Tue, ..., 6=Sun. Note carefully that JDN is *not* what is often mistakenly called, "Julian Day," which is actually just day-of-year, 1 to 365/366. JDN was invented by historian Joseph Scaliger in 1583 (the year after the introduction of the Gregorian calendar) in order to convert all the multifarious calendars that were used by various nations and empires throughout history, to a single day-counting system. Today it is used in astronomy to time certain types of recurrent astronomical events; and by the various space programs to keep track of what spacecraft are doing. In these arenas, it includes fractional days, the "zero" of which is noon UT. E.g., JDN 1 = Jan.1, 4713 BC (Julian Calendar). JDN of Jan. 12, 2019 (Gregorian Calendar) is 2,458,496. 3) This video really amounts to a way to find a similar sort of count, starting on each Jan.1, 400n, all of which are Saturdays. And I think it's more amenable to general use than my own method. Fred

@AshokYadav-zq2kd

5 жыл бұрын

Sir can you explain it in hindi

@AshokYadav-zq2kd

5 жыл бұрын

I couldn't get you

@AshokYadav-zq2kd

5 жыл бұрын

Please sir .I am very eager to know this trick.that will be helpful for my competitive exam

@ffggddss

5 жыл бұрын

@@AshokYadav-zq2kd In Hindi? I think you must have meant to ask Suresh that. In any case, I know about as much Hindi as I know Martian. And Suresh's method is more generally suitable than mine, which is more attuned to me personally. Fred

@AshokYadav-zq2kd

5 жыл бұрын

@@ffggddss no sir absolutely not I asked you only.i have seen Suresh sir video but I want to know different tricks .so i asked you

Thank you sir for explaining in such a simple way, now I can compute the day of any date, thanks a lot sir.

Fantastic explanation sir

Sir I am learning in class 10 I will give the NTSE exam ( can I aske to question Sir please)

@sukumarb7836

3 жыл бұрын

So did you crack NTSE?

thank you so much sir...you give best tricks all the time... dislikers are losers..

@sureshaggarwal

6 жыл бұрын

Thanks for the motivation. ...Kindly do help in sharing

@mahaboobbasha9298

6 жыл бұрын

Poonam doll Hi

@themasterji8252

5 жыл бұрын

It is good but not best. Have you seen scot flansburg how fast he was... And now i am like him

@themasterji8252

5 жыл бұрын

And I am preparing my self to break the Guinness book of world record of Scot flansburg.

@jaihind5000

5 жыл бұрын

Sir I have learn this in my third standard in 1977 but where is fifteen seconds

Thank you soooooooooo much!

Today morning I learnt this and now you taught.. Ur was better.. The morning session went tangentially

The trick finally revealed

What if the year is less than 1600. I couldn't get that. Please tell

@AmulrajSundaramoorthyTAS

2 жыл бұрын

Check the complete steps in the video I uploaded in my channel.

@LetsClashYT

2 жыл бұрын

@@AmulrajSundaramoorthyTAS ok

thanks sir u have a very positive persona

Thank you so much, sir! This was really helpful.