Transconductance amplifier: the works and applications

Пікірлер: 37

  • @justpaulo
    @justpaulo Жыл бұрын

    It's very interesting to know this "old" gems of electronics that I've never heard about before. Thanks.

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    👍😊🙏

  • @SuperHal2k
    @SuperHal2k Жыл бұрын

    Translinear circuits are always a exciting topic

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    Thanks

  • @ogrelg4131
    @ogrelg4131 Жыл бұрын

    большое спасибо за ваш труд. всегда очень интересно смотреть ваши лекции. Потому что кроме функционала хотелось бы увидеть математику обеспечивающую функционал, но при этом не утонуть вы буквах.

  • @hamidk4772
    @hamidk4772 Жыл бұрын

    Outstanding Job.

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    Thanks Hamid.

  • @benm4784
    @benm4784 Жыл бұрын

    OTA are also stable with capacitive loads! That's been useful on a few of my projects, and a convenient way to tune feedback loops in converters with few external passives

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    Stable in open loop like any amplifier.

  • @benm4784

    @benm4784

    Жыл бұрын

    @@sambenyaakov I thought most VFB opamps need a series output resistor to add phase margin when driving capacitive loads as an integrator? I think TI has a good app note on VFB vs OTA and their respective integrator topologies.

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    @@benm4784 To stabilize an OP Amp in closed loop with a large capacitive load, you add a series resistor and take the feedback at the output of the Op Amp not from the cap. A transconductance is a current source, that is, has a large series resistance at the output. So if you try to operate it in CLOSED LOOP you can not not sample the signal before the Cap.

  • @benm4784

    @benm4784

    Жыл бұрын

    @@sambenyaakov Ah! I believe I follow, and this gives me some concepts to play with! Thanks!

  • @paulpaulzadeh6172
    @paulpaulzadeh6172 Жыл бұрын

    Very Nice, could you please take composite amplifier too. one current feedback + voltage feedback . Current feedback is inside voltage feedback.

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    Not sure I follow. You mean to replace the transconductance amplifier?

  • @tamaseduard5145
    @tamaseduard5145 Жыл бұрын

    👍🙏

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    🙏😃👍

  • @elicohen2085
    @elicohen2085 Жыл бұрын

    The differential pair is indeed transconductance amplifier but the whole amplifier has a current to current gain

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    Indeed. Thanks for emphasizing this.

  • @h7qvi
    @h7qvi Жыл бұрын

    Every bit of analog professional audio gear has OTA audio compressors in them

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    AS far as I know real professional audio, and stuff I work on, has everything digital. The units I mentioned have about 1% distortion for 100 mVpp input, not very professional to me. And BTW are the OTA you talk about one of the units I have pointed out? If not which?

  • @h7qvi

    @h7qvi

    Жыл бұрын

    Mackie SRM450 v2 uses numerous NJM13600M OTAs as variable gain stages and for variable frequency filters

  • @h7qvi

    @h7qvi

    Жыл бұрын

    @@sambenyaakov Behringer PMP6000 uses V13700 as compressors on the input to the class-D power amp stage. Doubt 1% distortion would matter here because it's just going to speakers that add their own distortion anyway. Soft 2nd and 3rd harmonic distortion is much more tolerable than hard high frequency effects such as class B crossover distortion.

  • @goosgitaar
    @goosgitaar Жыл бұрын

    They're also used in guitar 🎸 Pedals

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    Thanks for input.

  • @weinihao3632
    @weinihao3632 Жыл бұрын

    Dear Professor, thank you for the great video! I think there is a slight mistake at 19:15. When I worked out the equation, I found that Io = Iin * (IB/ID) (e.g. no factor of 2).

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    Thanks for checking the calculation. I think though that there might be a confusion as what is Io, at the collectors or after the current mirrors. The ratio between these two is 2.

  • @32bits-of-a-bus59
    @32bits-of-a-bus59 Жыл бұрын

    Dear professor, thank you for an excellent video (as always). I am wondering: Being an open loop topology, it should be easier to make this kind of amplifier working up to a very high frequency, in comparison to trying to do so with a classical global feedback of an op-amp. That would make it a great application for a fast ADC preamplifier. Unfortunately, those parts that you've shown have GBP only of 2 MHz. This suggests there might be some caveat there. Maybe the transistors are not fast enough or some parasitic capacitances (or inductances -- as it is all current driven inside) are impeding high speed operation.

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    Youneed a dedicated design to HF Also. open loop ,means inaccuracy in gain and distortion

  • @xDR1TeK
    @xDR1TeK Жыл бұрын

    So it still could be used to condition a signal by changing the gain slightly rather than inducing a huge gain like a pre-amplification stage.

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    IN gain control you need a rather large amplitude range.

  • @mehmetdurna3115
    @mehmetdurna31155 ай бұрын

    Hello Professor. Could you please axplain why did we multiply (I_C1+2I_B) by the alpha factor to calculate the I_out? Also, what is the rationale to assume the base currents of the Q1 and Q2 equal? Is it an approximation or a fact?

  • @sambenyaakov

    @sambenyaakov

    5 ай бұрын

    Please specify to which slide or minute you are referring.

  • @mehmetdurna3115

    @mehmetdurna3115

    5 ай бұрын

    Thank you @@sambenyaakov , for your response. I was referring the calculations in Slide #7 (around 5'47"), I could not understnad why we multiply the I_C1+2I_B by ALPHA (line 2 in the slide.) And also in the same slide, what is the reason behind the assumption of identical base currents in the analysis. Is it due to small value, or matched transistor assumption etc? II appreciate your channel, videos and your explanation. I understood so much with your lessons.

  • @sambenyaakov

    @sambenyaakov

    5 ай бұрын

    @@mehmetdurna3115 Alpha is the ratio between collector and emitter current. Emitter current is 2*Ib+Ic1 The implementation is usually on a single chip and the transistors are pretty much matched if close one to the other. __________________________________________

  • @AnalogDude_
    @AnalogDude_ Жыл бұрын

    these linearization diodes, look like Voltage clamps. Never used them and it works just fine. it's still not very clear why you should use them, what benefit you get. Some new FET from Texas Instruments, released a couple of months ago has also a diode on the gate from the source, like the "circuit" on the right at 17:12. was the first time i saw i saw that, seams weird, like having the emitter power the base, seams illogical.

  • @sambenyaakov

    @sambenyaakov

    Жыл бұрын

    The benefit is linearization. Without the you get high distortion for larger signals. Please send the part number of the MOSFETs you mentioned?

  • @AnalogDude_

    @AnalogDude_

    Жыл бұрын

    @@sambenyaakov Well i have build voltage controlled filter with them. amplifying a 10 V.p.p. from one the attenuated -20x, no distortion found, instead of CA3080. not Texas Instruments, but Analog devices. MAT12, SSM2212. seams weird, one would think that the output, emitter would also power the base "partially", like a feedback.