Think outside the quarter circle
Think outside the quarter circle. What's the length of the required segment?
#maths
#mathematics
#math
#mathpuzzles #geometry
Think outside the quarter circle. What's the length of the required segment?
#maths
#mathematics
#math
#mathpuzzles #geometry
Пікірлер: 15
Love your sense of humor.
Love this bro! Keep going❤
Thanks for sharing the fun power of math! Here is a video solving a similar problem using a free, browser-based modeling tool. kzread.info/dash/bejne/dIB40raKZcjKmbA.html
Pytagorean theorem: s²=24²+7² s = 25 cm d²=24²+(7+s)² d = 40 cm, r = 20 cm h² = s² - r² h² = 25² - 20² h = 15 cm ( Solved √ )
Nice problem, very nice solution
No need to think outside the quater circle? O the center of the quater circle, A on the circle on the left of the diagram, B on the vertical at distance x of O, and C on the quater circle as angle ACB is 90°. R is the radius of the circle. We consider OACB inscripted in the quater circle and use the Ptolemy theorem: AB.OC = AC.OB + BC.OA, then: 25.R = 24.x + 7.R That gives: R= (24/18).x = (4/3).x Now we use the Pythagorean theorem in triangle OAB: AB^2 = OA^2 + OB^2, so 25^2 = (16/9).x^2 + x^2, giving that x^2 = 625/(25/9) = 225. Finally x = 15 (and R = 20)
@znyght2071
5 ай бұрын
wow
Nice
The hypotenuse of 25 calculated for the triangle shown this is also the hypotenuse of the right triangle including the base of the 1/4 circle and the unknown line segment. A 5,4,3 triangle implies if hypotenuse =25 then other sides are 20 and 15 respectively ergo line segment =15. No need to go outside the quarter circle.
@ajsenju9383
15 сағат бұрын
so I assume your math teacher also taught you how to Psychicly guess triangls ratios
i dont understand extending the line which perfectly meets the other end of the circle (B) how does this property work and what conditions must it have?
@MindMathEnigmas
5 ай бұрын
Look at Thales's theorem: en.wikipedia.org/wiki/Thales%27s_theorem
@inthefogs
5 ай бұрын
@@MindMathEnigmas thank you very much
15
15 cm