Thanks a lot. I have been struggling on Thevnin’s Theorem, and from watching your video I managed to pass all my exams. I have been watching all the tutorials on TT, and your tutorial is the most clear and helpful. :))

Needed a recap of this and you cleared all my confusions! Very nicely explained, two thumbs up!

This video was actually very good in my opinion despite the slack it's getting. It's not a tutorial on everything, just thevenin theorem. No need to go into depth for nodal analysis; all I needed was to see how thevenin works and that's what I got. Very glad, thank you!

really clear, thx a lot:) you made a marvelous start on my final revision! looking forward for more video!!

Its been 5 Years since the Snap.... The world has not been the same since Maerina has stopped uploading videos

@genshingt7792

4 жыл бұрын

L

@AliRizwanMasood

4 жыл бұрын

@@genshingt7792 It somehow got worse

@genshingt7792

4 жыл бұрын

@@AliRizwanMasood lmaoo😂

This was a hugh help! You explain it way better than my Uni.Teacher, thank you!

@ricardocabral3330

5 жыл бұрын

fuck, so relatable

thank you! you are ten times better than my lecturer!

"When the world needed her the most she vanished", we need ur vids

than u soo much . i had this question in my book but i couldn't slove it . then i found that u done it here . keep up the good working. god bless u

I’ve been looking all over the place for help on Thévenin equivalent circuits. This video finally helped me understand! To find V2 you just have to solve two equations with two unknowns.. it’s just algebra

@matnor1149

5 жыл бұрын

Unnecessary complication unfortunately. Better to solve this kind of problem using the source transformation technique.

Thanks a lot. Beautifully described!

In node analysis you should explain that we must include a ground on a reference node. So if you take reference node on node which is spotted on the branch between of b and the resistor 4ohms then Vb=0. The Vth = Va - Vb, where Va=V2 which you are right. But Vb = 0 because of the ground.

@anassaifi7613

5 жыл бұрын

Agree bro

@nabanitagoswami6652

4 жыл бұрын

Thank you

very helpful, clean, clear and punctuative. thank you very much.

Many thanks my lady , I've got this lesson in the first stage ,that was in 2004 and now I have refreshed my informations ,,,

Can please, explain how you got Vth as 6V? As nice as the video is, I couldn't arrive at the 6V using equation 1 at Node 1 or Equation 2 at Node 2

@TonyTv15

9 ай бұрын

Same question here.

Clearing up the algebra: From node2 multiply both sides of the equation by 24. 4V1-4V2-6V2=0 Solve for V1 4V1=10V2 thus V1=(5/2)V2 From node1 multiply both sides of the equation by 6. 12-V1+12-V1+V2=0 Simplify 24-2V1+V2=0 Substitute V1 from node1: V1=(5/2)V2 24-2(5/2)V2+V2=0 24-5V2+V2=0 Simplify -4V2=-24 OR V2=6 and V1=15

@horridharry33

6 жыл бұрын

At the line where you write: '12-V1+12-V1+V2=0 Simplify', Shouldn't it be '12-V1+12-V1-(minus here instead of +)V2 = 0 if you look at her equation for node1

@kylesaucier7650

4 жыл бұрын

Where do you pull the 24 from?

@catman8965

4 жыл бұрын

Kyle Saucier Trying to remember my thinking from 3 years ago, I think I multiplied both sides of the equation by 24 to reduce the number of fractions that would be created simplifing the typing and making the reading a little bit more clear.

@standog3696

2 жыл бұрын

@@kylesaucier7650 the 24 is from 12+12

Perfect tutorial , thank you Marina !

Great job! This was a good review for me.

Awesome explanation Marina. I find thevenin and norton's theorem particularly interesting it's why I tried as much as possible to solve a lot of questions on the topics on my channel.

You explain the lesson better than my doctor.

I am from india.Thank you very much now only I understanding the thevenin's concept by your video.Thank's a lot.....

May this video be blessed!

There are a lot of people who doubt that Vth is 6V. Do this instead: Transform the voltage source into a current source of 2 Amps. Combine the two current sources and get 4 Amps. Transform back to a voltage source, 4 Amps * 6 Ohms = 24 Volts. Use voltage division to find the drop across the 4 Ohm. That is 24 volts * (4 / (6+6+4)) Ohms = 6 volts.

@walterbaldemor2128

6 жыл бұрын

Or you can use the two 6ohm and 4ohm in series and get the voltage across 4 ohm. With 24v as the loop source. Say 24x4/16= 6volts. I hope it helps

@The_Daya

6 жыл бұрын

YoAirFresh nice explain and here using voltage division rule may I right Voltage division rule: Vth = total voltage × opposite resistance/sum of total resistance

@321reh

6 жыл бұрын

Thank You YoAirFresh...Perfect Explanation!!!

@muballatofficial3754

5 жыл бұрын

Could the whole process be done with the superposition method?

@modibosco9287

2 жыл бұрын

i got 2v so i dont know she arrived at 6v but her explanation was excellent

thanks a lot marina .....u did a great job

Thanks!!! Everything makes sense now!!!

i have an exam tomorrow , this is a life saver

Thank you very much, I have finally understand.

thank you , appreciate your work :)

Thank you...u helped me a lot now am ready for my finals

tnxxx fr uploading this video...Infect your determination of V2 is superb... its a supernode bt u did it very easily which made this concept easy to me...

1:35 and i oop-

@sachinandanprasad7618

3 жыл бұрын

ooppp

Súper! muchas gracias desde Freirina, Huasco, Chile

really helpful ! thanks a lot!

your explain is very good . please continue make videos and start in circuit with ac sources :'D

Thanks for your video. Your example is similar to my homework question. Now, I can solve it with clear mind. Hope you can upload more video

Thank you so much... :) You just made it so easy for me...

Thank you very much, the video was very helpful. :)

Just wanted to thank you! :)

thanks so much.. this is very useful...

@dabulls1g

6 жыл бұрын

how on earth is a video that skips some of the most fundamental concepts behind thevenin's theorem useful to you AT ALL?

Thanks for your video.This problem is really solved and i easily understand .

i just fall in love with your voice...

Marina :D thnx for this video :D u got a lovely voice here

Much more helpful than my actual teacher. THANK YOU

Thanks so much for your such fab explanation...... Hope it will help today in my exam👍👍👍👍

Great vid! Thank you

VERY SIMPLE AND GOOD WORK !!

i love her speaking accent!

@nsa3679

5 жыл бұрын

She’s Russian.

@jamesretreat

5 жыл бұрын

shes greek

@Maen963

5 жыл бұрын

She is french

@perrytheplatypus8380

5 жыл бұрын

she is everything 🤣

why is this better than lectures in class?? :(

*Thank you very much. Very useful explanation*

A very useful video...thank you!

You are a great teacher

this video helped me alot to understand this thereom in my final exam today .. thanks alot 😊

I thought you made currents negative when coming into a node, and positive leaving. Or is that only with KVL/KCL?

Amazing stepwise approach

Thanks!! I finally get it

Thanks it is very helpful :)

Your voice is more anticipating I am in love😍😍😘

You can also use superposition theorem to solve for the voltage drop across 4 Ohm resistor. It takes a bit longer but it works if you haven't learned Nodal Analysis

@voyasart

5 жыл бұрын

superposition is embedded within the theorem.

@abhinavaray299

2 жыл бұрын

Yes . actually by doing that we are getting 3 volt for both cases(two sources alone) and they add up to 6 volt

how do you get 6v for v2? how did you calculate that?

explained great thank u so much

Thanks a lot .. you just make a mundane understand better

Thank you for your explanation Now I can a Do the 10 marks question in tomorrow exam

@shifty7

6 жыл бұрын

oh my English

Thank you Mam!really helpful

i love your voice, also thanks for the video!! :D

thanks . this is so perfect

Really much more helpful .........Thank you

Great! Thank you

Here is how she got 6 V. From node2: arrange the equation to get V1=5/2 v2 From node1: arrange the equation to get 4 - 2/6 V1 + 2/6 V2 =0 Substitute for V1 in the above equation: 4 - 2/6 * 5/2 V2 + 1/6 V2 => 4 = 5/6 V2 - V2/6 ==> 4= 4/6 V2 ==> multiply both side by 6/4 . The result is V2 = 6 V.

@Anbuninja840

2 жыл бұрын

still wrong she didnt include the 4ohm resistor in series with the 6 resistor

@VALIANT_Electronics

2 жыл бұрын

@@Anbuninja840 who told you 4 ohm resistor is in series with the 6 ohm resistor?, first you do series then parallel, 4 ohm is in parallel with 12 ohm.

@Anbuninja840

2 жыл бұрын

@@VALIANT_Electronics since the a and b is opened , the 4 ohm became series with the 12 ( 6 and 6 )ohm resistor

@VALIANT_Electronics

2 жыл бұрын

@@Anbuninja840 nope, opening in a and b has nothing to do with that, if they share 2 nodes that's parallel.

@kennethbanda7622

Жыл бұрын

Where did you get 2/6V2 on Node 1: 4-2/6V1 +2/6V2 ??

excellent!! thanks a lot

thank you helper

Thanks for the video, it was very helpful. Please clarify my doubt: while calculating Rth, we removed both power sources... we considered voltage source as short circuited, but why did we take current source as open circuit? i mean, why didnt we consider a shorted connection between 2 6ohms resistors while calculating equivalent resistance?

5:01 can you interchange the signs of + and - in terminals a and b?

Love your videos and love your voice, haha!

@sagarrajkumargupta5168

3 жыл бұрын

itni achi bhi nahi hai

at 3:17 shouldn't the 4 ohm resistor be in series with the rest of the resistors ? I could be wrong I just need clarification on why you think theyre in parallel thanks

@isaiahphillip4112

4 жыл бұрын

Don't forget that there's a node on either end or the 4 ohm resistor. Therefore it's not in series.

You made it so much easy🙏🙏

Thanks a lot Madam !!!! you are teaching..........

Thank u and god bless you

For Rth shouldn't you first calculate 6 and 4 in parallel and then add the other 6?

Vth... 6ohms, what about the current source of 2A that create also a voltage over the (6 and 4ohms resistors. Maybe I wrong... I belief that you also need kvl to know the voc (over the 4 ohms resistor).

thank you madam, good teaching

I loved this! The explanation is so good. :D

Anybody confuses about what +Marina Belkina did. Here is the full list of the procedure: 1. Nodal Analysis on two node: V1 and V2, you could name them as VA or VB, does not matter. 2. As part of the nodal she did KCL (current In=Current Out) in each node. 3. Did simultaneous equation solving to figure out the voltage in V2. [Note: she made an ground node analysis in node 2 to get (-V2/4ohm) because Vground-V2=-V2 as Vground=0V] 4. She claimed no current will follow the end of 4 ohm resistor so V2 will be the same as the Voltage through Open circuit = VTH.

VTH is essentially the point at which the voltage going to the resistor is consistent in terms of value. So in this case, VTH is the point where the resistance is 4 ohms. Ideally V2, should have been labelled VTH.

thank you very much Marina, greetings from Greece!

thank you for ur useful tutorial

Why wasn't v1 subtracted from v2?Instead of the other way around? I thought that all voltages are either were either supposed to be coming into or else leaving the node right?

excellent ! well explained

Thanku thanku thanku very much nice teaching very well, excellent

Why is Vth=V2 ? it should be V2 - V3 , where V3 is voltage at junction point just to the left of open terminal b

@jokerrecon8420

6 жыл бұрын

It is assumed that they're connected to the ground, hence V3 = 0. This is just to make the problem simpler.

@amritacharya5771

2 жыл бұрын

Agreed!

I 've question about Vth that when we use )V.D.R and C.D.R to solve Eth?

u r a very gud teacher

Hi I think what you did with current analysis to the node by KCL is quite wrong, because current don't just add up because they want to. From Voltage source of 12 V battery current flow clockwise but 2A currect souce(supplied) is going anticlockwise relative to the voltage source so should not there be a negative sign. I don't know how you worked but your Thevenin Voltage seems reasonable to me. Thanks.

@JustWatchingVideo56

5 жыл бұрын

Whom Isac Her KCL is correct if don’t want to mess up though just do V1 drops over every branch and you add them up to zero. Basically following the idea that at any given node all current is either going into the node or going out of it and it adds up to zero. That’s how I do it. So my equations for this would be: (V1-12)/6 - 2 + (V1-V2)/6 = 0 (V2-V1)/6 + V2/4 = 0 Personally I don't try to determine if the current is going in or out of a node based on intuition because it can be confusing. I just like to be consistent with this method and not have to worry about it. After all it's nodal analysis, you look at it from the node not the circles.

Wow your voice is like that of an angel, oh and good job :)

@thealex232323

5 жыл бұрын

A russian angel

THANK YOU

wil u plz explain,how do we find the vth in the same circuir with mesh, your explaination about thevnin with noodle is so good.i hope you solve my problem.

@sagarrajkumargupta5168

3 жыл бұрын

hi

For this to work, she had to automatically assume that Vb is GND, correct?

@videoeffectstutor

5 жыл бұрын

Yeah I think so

VERY HELPFUL.....THANKS

so clear.......amazing

Why did you consider the terminals from a to b open circuited in nodal analysis and didn't consider it open circuited in calculating Rth ?

how did you calculate V2 as 6 volts?

@marinabelkina8397

9 жыл бұрын

2013Aleksey2013 Aleksey, Thank you)

@masroorahmed1638

8 жыл бұрын

+Marina Belkina how to calculate v2 as 6 volt.

@tevinmorgan191

7 жыл бұрын

peter almeida , simplify the two equations by removing the fractions then solve simultaneously

@king_kunta095

5 жыл бұрын

your high school algebra teacher must give you change