Synthetic Division with a Quadratic Divisor

This video shows an example of how to use synthetic division when the denominator or divisor is a quadratic function. It might me easier to use long division for this process, but if you are required to use synthetic division, hopefully this video will help you.
If you want to view all of my videos in a nicely organized way, please visit mathandstatshelp.com/ . It is free for anyone to use. Please share with others you know who are struggling with math topics or statistics.

Пікірлер: 18

  • @rocks813
    @rocks8132 жыл бұрын

    Wow, this is new to me! Lucky KZread recommended this video, thank you for the new knowledge

  • @mrcrash4107
    @mrcrash41072 жыл бұрын

    Very informative, thanks for all the work

  • @xtremegamemaker
    @xtremegamemaker Жыл бұрын

    Thank you. I was looking for this... Just one question, please tell me what changes I'd have to make for a non monic quadratic. Also will it help if i factorise the quadratic first and then repeatedly divide.

  • @christmastunip4913
    @christmastunip49132 жыл бұрын

    Math and Stats Help, can you make a video about the addition & subtraction of Integers? Thank you!!!

  • @user-uz6we7hv7b
    @user-uz6we7hv7b5 ай бұрын

    how to divide when the power of X in divisor is greater than the dividend?

  • @holyshit922
    @holyshit9226 ай бұрын

    It is useful for Bairstow's method Write it in a loop

  • @kreshnaapriiyaa4857
    @kreshnaapriiyaa48572 жыл бұрын

    Very nice explanation 😁😁😀

  • @MathandStatsHelp

    @MathandStatsHelp

    2 жыл бұрын

    Thank you

  • @MrMask-zt9uo
    @MrMask-zt9uo Жыл бұрын

    Why is there x in the remainder 2x? I got the rest but that one..

  • @robonthecob5092

    @robonthecob5092

    Жыл бұрын

    The table from left to right goes down in degree, so the second to last one will be of degree 1

  • @MathandStatsHelp

    @MathandStatsHelp

    Жыл бұрын

    If you were to do long division, you would probably be able to see the remainder better. Basically what happens is that you have a remainder in both the linear and constant terms.

  • @eduwithsh9991
    @eduwithsh9991 Жыл бұрын

    what if the divisor is x^2 - 2x -1

  • @MathandStatsHelp

    @MathandStatsHelp

    Жыл бұрын

    You would put the opposite sign on the outside for the linear and constant term. 2 and 1 would be used.

  • @mrlarrydapuppet4337
    @mrlarrydapuppet4337 Жыл бұрын

    This doesn't work it's not a monic quadratic right? How would you do this if the x^2 coefficient was something other than one?

  • @johngambino5105

    @johngambino5105

    Жыл бұрын

    She explained that you would need to divide all coefficients by the leading coefficients

  • @mrlarrydapuppet4337

    @mrlarrydapuppet4337

    Жыл бұрын

    @@johngambino5105 Damn I must have been really tired when I made this comment XD, thanks for replying anyway

  • @uttkarsh2092

    @uttkarsh2092

    11 ай бұрын

    not sure but i would guess if the equation is like ax^2 + bx +c then u can write it was a(x^2+b/a*x+c/a) and do it then