(n) unpaired electrons (u) Magnetic Moment in under root coloured/colourless Magnetism V 4+ 1 3 Coloured Para V 3+ 2 8 coloured Para V 2+ 3 15 coloured para Cr 3+ 3 15 coloured para Mn 3+ 4 24 c p Co 3+ 4 24 c p Ni +2 2 8 c p Cu +2 1 3 c p Zn +2 0 0 COLOURLESS DAIMAGNETIC Fe +3 5 35 c p THANK YOU SOO MUCH SIR

As you mentioned, it does away with writing electronic configuration for finding un-paired electrons. Thank you, Sir, for enlightening us on this topic.

@KSanthu-ry8mo

Жыл бұрын

Tqq sr

@TaekwondofederationIndia7697

9 ай бұрын

​@@KSanthu-ry8mowa22l

v4+ = 3^1/2 v3+ = 8^1/2 v+2 = (15)^1/2 Cr+3 = (15)^1/2 Mn+3 = (24)^1/2 Co+3 = (24)^1/2 Ni+2 = 8^1/2 Cu+2 = 3^1/2 Zn+2 = 0 Fe+3 = (35)^1/2

@AB-fw8kl

2 жыл бұрын

Nice

@techinicalissues5427

2 жыл бұрын

Awsome great

@chavanaadinath2960

2 жыл бұрын

Nice 👌👌

💥💥💥BHAOT BADIYA TRICK....SIR..JI.. THANK YOU..🙏🏻🙏🏻🙏🏻

Thank u sooooooooo much sir...ur trick is just awsm....😍😍😍😍😍

Just awesome 🤩👍🏿👍🏿

Thank u sir bohot achi trick thi u made it 😊 easy

Thanks sir itni easy trick or liye👍👍👍

Thank you so much sir ji 😊😊

Thanks sir esi trick batane ke liye

Thanku sir ...thix was amazing trick

Thank you sir, very nice trick, useful to solve questions in less time in exams👍😊

@gwyt3451

2 жыл бұрын

Noo i also learnt it without trick

Thanks sir first time samgha Mai d block🎉

great trick sir.......easy h bht.....thnx alot....:)

Thanks sir please continue

Yeah it's such a easy trick

Thnkuuuuuuuuuuu sir you are great sir 👀😱

Great sir....🔥🔥

Thank u so much sir 🙏🙏🙏

Sir your trick is amazing😮❤

Thank you sir ❤️😊

Sir v^4+ vala smjh ni aaya... Plaese explain... Because group no. Of vandium is 3 but charge on this is given 4+ then if we substract 4 from 3 mean 3-4= -1 how is this possible to have -1 unpaired electrons for any element.. please explain 🙏🏻

Thanks you so much sir

V4+ = √3 (Paramagnetic), colored V3+ = √8 (Paramagnetic), colored V2+ = √15 (Paramagnetic), colored Cr3+ = √15 (Paramagnetic), colored Mn3+ = √24 (Paramagnetic), colored Co3+ = √24 (Paramagnetic), colored Ni2+ = √8 (paramagnetic), colored Cu2+ = √3 (paramagnetic), colored Zn2+ = o (Diamagnetic), Colorless Fe3+ = √35 (paramagnetic), colored THANKS SIR ❤ FOR THIS INTERSTING LECTRUR......... 🙏🙏🙏

Super trick thanks sir..

Waah sir bahut badhiya trick hai

I love you ❤️ sir Video banane ke liye thanks sir 🙏🙏🙏

Sir ye trick hum s-block ke elements pr bhi use kr skte h kya??

Thankyou sir for video🙏🙏

Thank you so very much sir is a very eji and last moments ecjams

Nice trick tnku sir🙏

Thaks a lot sir to provide us a lot of easy tricks It's very helpful for me Thanku Thanku Keep it up..

Tq very much🙏🙏🙏

Thank you for the video sir.. I really didn't know about this trick before watching your video... Even I was confused about this.. how to calculate unpaired elctrons. But now I am fully sured that I can do this.. thank you again...🎈

Is it only applicable to 3d series

Thank you sir😊

Sir to know the colour ? Do we have to learn it or is there any trick ?

Thank u sir 🙏

So beautifull video guru jii..................🙏🙏

Bhai sahab mja hi agya 🫡 salute

Thanks a lot sir

Thanku😮

Thank you so much sir this will really help us in JEE !!

Thanku sir ji

This is a very nice trick

The answers are of 1,2,3,4,5,3,4,1,0,5 of unpaired electrons

V4+= (3) sir your teaching is nice

Colour koi v dal sakte hai sir

Aise hi dimaag khrab kr rha tha or itna simpel tha ye just hats of sir for enlightening this topic to the students your trick will be very helpful for the students like us thankyouu from the behalf of all of us 🫡

Superb tricks 🙂🙂🙂

So nice trick sir ❤❤

Excellent trick sir

Thanks a lot

Thank u sir

1st like view Informative video sir thanks

@fundamentholcom

4 жыл бұрын

thanks a lot :)

Sir aapka bataya ek ek chij samjh aaya sir thank you sir maine solve kr liya hai sir.... Answer de sir

Thanks for sharing

Thanks sir

Thanku sir

Trick is very very excellent

Best trick h sir ji

Can this be applied to coordination chemistry!? Anyone please answer!

@thalavalikaran262

3 жыл бұрын

Sure yes

Superr sir👌👌👌👌👌👌

Thanks again😁😁

Dominating voice

Sir electronic configuration pr video banaiy

Wow ! 🙏👍👍👍

Awesomeone trickkkkkkkk

Super ....

Good lecture

Thank you so much sir it's very helpful for me 🙏🙏

👍👍👍💞💞💞💞Good❤❤❤

Very very nice sir

sir.u are a brilliant...for tricks

Sir, by this trick how we can distinguish between high spin and low spin complexes

@akshaymallya4704

3 жыл бұрын

See ligand if halogen low spin if not then high spin

@NATSU-hi1zb

2 жыл бұрын

If electrons paired - dimagnetic

Wow nice trick

Best formula

Trick to bhut achhi lagi... Lakin, Sirf d block ,1st row ke liye hi hai..!!🙄🤔??

@rahulshendre7089

Жыл бұрын

ha bhai

Excellent

sir we want more tricks for physical chemistry

Tnk u sir

Super sir

Nice tricks sir

Mast

Mast trick h sir thanks

@fundamentholcom

4 жыл бұрын

thanks Gouri.

Excellent trick.....

@jankiprasad4457

3 жыл бұрын

Sachin Tendulkar world cup mein phir koi naya cup jeetegaa Ye hai excellent trik

Hello sir please give me answer

Awesome

ELEMENTS. NO. V4 ~root 2 V3. ~root 8 V2. ~root 15 ......So on

@Pratikshya_Das

3 жыл бұрын

Brother V4 ka answer √3 👍😎

@abas8043

2 жыл бұрын

ager no more than 5 hoga tu 10 se - karo no ko

Love it😘

Nice sir

Thanks sir...

@mr_raghavbairagi02

3 жыл бұрын

Samjh me bhi nhi aaya thoda slow..

if charge on element is zero .. this trick is not applicable

Next part?

Thanks

So easy tqq sir Ji ❤

@fundamentholcom

4 жыл бұрын

thanks Kapil.

Super duper trik

I am in class X and watching in lockdown. Thank you sir for this trick

Zn Ka kitna hai..???

@Sanvideshmukh6118

4 жыл бұрын

Zn is not a transition element