Brandon the way you present and explain these concepts, you are truly gifted! Your own clarity of concepts and the effort put in to make these dense concepts clear to the viewer are very obvious. Kudos sir!

@BrandonFoltz

5 жыл бұрын

Thank you! :)

I've been using your videos to refresh my basic stats for my final dissertation defense in biostatistics. Thank you for these videos, they are fantastic!

i am binge-watching your videos for my statistics exam. wish me luck. and thank you for making such helpful and understandable statistics materials.

Thanks for simplifying stats.Keep enlightening us.

It's a really great video to understand. I believe lots of effort and knowledge is required to create such a type of tutorial. really thanks

Brandon you are explaining the concepts very clearly

11:18 how we substitute the value of population proportion p with sample proportion p-bar which is 0.567

@abdullahbabor4876

4 жыл бұрын

I am confused too!!

Thank you Brandon. You are the best

Hi Brandon, You can create your sampling distribution with only one sample because the rule of the approximation to normal is fine for this example. Am I right? or Can you create sampling distribution with only one sample in general? Thank you in advance.

thank you kindly, this was really helpful...

thank you so much B, it is goign a long way in my python work

awesome video! THank you!

Hi Brandon, so there are multiple ways of calculating Z-scores. If the sample is regular Z = x-xbar / standard deviation if it is a sampling distribution: Z = xbar - E(xbar) / (standard_deviation / sqrt(n)) if it is a sampling proportion: Z = pbar-E(pbar)/sqrt(p(1-p)/n) Can someone please explain when to use which one? what is the difference between sampling distribution and sampling proportion? Also how does one come with the formula for standard deviation as sqrt(p(1-p)/n)

14:38 the mean(at z=0) that was used, is that population proportion P ? I am a bit confused.. can some one help me with this?

Best channel i found... best videos and playlist

@BrandonFoltz

Жыл бұрын

Glad you enjoy it!

You are the best sir

Dear Brandon, many thanks for all your fantastic videos! One question: in minute 11.01, when calculating the standard error, the formula demands to put in a value for "p" (population proportion), but instead you fill in the value 0.567, which was previously calculated as a value for "p bar" (sample proportion). Why is that so? Do you consider that "p" and "p-bar" are the same?

@vulnerablerummy

4 жыл бұрын

i'm gonna assume they're the same for now since he only takes one sample proportion (one test to find E(p-bar)), whereas in previous videos on sample means, Mr. Brandon takes multiple samples (9 test to find E(x-bar)). add a grain of salt to that since this is only my hypothesis

@tallajayakumar5277

3 жыл бұрын

Hello, I've got the same doubt after rewatching the video I've got clarity. It's because population proportion is the expected value of the sample proportions E(p(bar)) = P. And E(p(bar)) is the average of the sample proportions that we take. So here E(p(bar)) = P = avg(all(p(bar))). there is only one p(bar). so P = p(bar)

Thank you boss!

Very nice.. Thanks sir

You literally saved my educational career, thank you.

loved it

timestamp 16:43: Why 0.55 is on the left side of 0, since it is a positive number, can’t it be between 0 and 0.6572 ?

Thanks

is sample proportion & population proportion are same?

11:18, In calculating the standard error of proportion we need population proportion then why you are putting value of sample proportion

Hi Brandon, thanks for this wonderful video but I'm a little confused in 10:19, i thought the formula for z-score is "z = (x-μ)/σ," are there different formulas in calculating z-score for standard error for mean and standard error for proportion ?

@mohdibrahim2173

8 ай бұрын

It's sampling distribution of sampling proportion standard error of mean is as standard deviation of sampling distribution. Maybe that is the reason of using standard error instead of standard deviation of population or sample

@mohdibrahim2173

8 ай бұрын

Standard error of mean and standard deviations of sampling distribution are same

How can we get a relationship when independent variable is qualitative in nature and dependent variable is in quantative

@BrandonFoltz

5 жыл бұрын

Hello! A few ways, but easiest may be to set up dummy variables for the IVs and then use regression.

Sorry, what are these tests you are running at 11:30 ? Before you said n/N and its relationship to 5%. Now you are saying stuff about np and n(1-p) and their relationship to 5%. Whats going on?

@wackojacko1997

Жыл бұрын

@BrandonFoltz -- I have the same question as the OP above. I assume that I'll find out why you are using 5 to determine if you can use the normal distribution in a prior video, but when I see it here in the video, I have no idea where it comes from. The 5% that Ethan mentions I think is just a test of significance and unrelated to the 5 mentioned at 11:30 (I think?).

Okay. So what if the proportion is not normally distributed

Thank you sir for such a beautiful knowledge 🙏

@Ilemaurice687

2 жыл бұрын

Do u do statistics plz

@laxmimishra6012

2 жыл бұрын

@@Ilemaurice687 Yes sir

@Ilemaurice687

2 жыл бұрын

@@laxmimishra6012 help me plz i will send u questions plzz cant find someone

@Ilemaurice687

2 жыл бұрын

These people dont even reply which have done videos on KZread they r not helping

@Ilemaurice687

2 жыл бұрын

@@laxmimishra6012 plz if u can help me i will sen u some questions will you be able to help me pleaseee

Best

"I think we forgot to mention that if the population proportion is known, we would have had to use it."