I appreciate the enthusiasm in your voice, its appreciated, and of course the video is excellent. Thank you for taking the time out to make it sir.

@jbstatistics

8 жыл бұрын

+andrew morchik You are very welcome. Thanks for the compliment!

@gulbengozu9232

2 жыл бұрын

i agree with every single word

Thanks! I'm glad you like this video. I've got lots more stats videos, and I'll definitely be adding content for some time.

Thanks for the feedback and compliment James. I am just doing my videos the way I think is best. What I think is best changes a little through time. I had a different vision in mind when I first started making these than I do now, so I've changed how I do things a little. I'm glad you like this video. I do too.

Dude, your videos are some of the most well-presented math videos I've seen (and trust me, I'm in 4th year eng, I've seen A LOT) You're a real gem

Feel really proud in what you're doing. Every view that you ascertain through one of your videos, motivates an individual to carry on and learn more. You've really made learning fun and easy. keep up the wonderful effort.

My teacher spend 1 hour of the class trying to do what you did in less than 10 minutes, truly excellent work. You deserve more views that this!

you have no idea how much you've helped me omg. i've been almost failing stats because i couldn't understand it until i found this channel #bless

You can find that using software or a standard normal table. I have videos outlining how to find percentiles using the standard normal table. (There are 2 main types of table, and I have a video for each one.)

You're welcome, and thanks for the compliment! I'm always happy to be of help to my friends in the UK.

One word about your presentation: SUPERB!!! Thanks a lot, you are the best tutor to explain this!

Thank you for having me enjoying my statistics course because of this beautiful and useful lectures! You deserve the best

I like the speed of this video! Towards the end it sounds like you're in a game show about explaining statistics before being swept down into water by a moving wall, but it's still calm enough to understand without feeling stressed. I guess it's more akin to a commentator's change of voice when a goal is approaching.

You're welcome, and thanks for the feedback. Due to popular demand, I've slowed down a touch on my recent videos. But I still try to make them a little quicker and much more concise than what I see out there.

Bless you sir, your enthusiasm for stats is so infectious, I think i finished my entire semester's worth of content in a single weekend. All thanks to your videos.

@jbstatistics

6 жыл бұрын

You are very welcome, and I'm glad to be of help.

thank you so much for a fast version of this. cant stand seeing every calculation done in a video

I do school online, and even the lecture videos and textbooks could not teach me the way you just did. I appreciate you making this. You just helped me pass my class.

You are a global brand. I like your enthusiasm in improving your presentation. Just noticed the sudden change in emphasis. The material is top notch as usual. Many thanks.

@jbstatistics

6 жыл бұрын

You are very welcome. I'm glad you liked the video!

15 seconds in, and I already love your enthusiasm.

Love that you're using a higher tempo than usually man. Never really understood the point of talking slowly when KZread has the ability to paus and rewind. Thanks man.

9 years later and still helping me feel better about my final tmrw, thank you

Good to hear! I'm glad to be of help!

You're welcome! Yes, I have videos along those lines. You could start by searching for my video entitled "The sampling distribution of the sample mean." That will explain the sqrt(n) and when we'd use it. I taught at UGA for a year a decade or so ago. I miss Georgia.

Best. Statistics. Channel. EVER. THANK YOU!!

You are awesome! I literally learned my whole Quantitative Methods material through your videos! I wish the money I paid for this course went to you! Thank you and keep up the awesome work!

@jbstatistics

9 жыл бұрын

Thanks for the compliment! I'm very glad I could be of help!

@EJigut

8 жыл бұрын

+jbstatistics Your statistics videos are beast mode. Clear, concise, and for once the audio is not monotone or a computer.

Really nice video, nice voice, clear presentation, great teaching. Sped up my revision, thank you so much.

this is definitely the *fast version* haha i cannot thank you enough for all of these videos! salut du Québec!

Thanks! I'm glad you liked it!

You're welcome! Thanks for the compliment!

Sir ..could u explain how the z value is 1.28??

Great video that properly explains the topic. Thanks for the upload!

So much enthusiasm I love it.

AWESOME videos, sir. Please do more of these. I am starting a Masters degree in Economics in France. And I was so worried about my statistics but your videos are amazzzzing. I learned in a day what I COULD NOT learn in 4 years of graduate studies.

@jbstatistics

5 жыл бұрын

I'm glad to be of help! I'll get back to video production very soon!

I'm glad to be of help!

You make me enjoy statistics, great videos.

You are such a brilliant dude. Thanks for your all videos 🔥🔥🔥🔥

Thank you so much for this video. Couldn't have been more helpful

@jbstatistics

5 жыл бұрын

I'm glad to be of help!

Thanks! Just helping out where I can.

For area finding we have to use A3 table? Plz reply ASAP... SIR ACCORDING TO A3 TABLE in. American height ques. Area is coming wrong

sir, I can`t believe that u are giving this at free.thank you so much sir

Good stuff, if only my lecturers were as enthusiastic as you are.

How can anybody be soooooo excited about statistics? This is awesome hahaha

Thanks from Queen Mary Univerisity Of London. You are an awesome Teacher , Thx for your time and effort.

TStudent distribution video has been removed/made private on this playlist? I suggest people to access it through the website.

You are such a great tutorial i have ever seen... Good job dude... By the way I'm from india.... A lot of love by me... Keep it up🙏💯

Yeaah, you could even talk faster and we would understand. You teach so good that that is even possible. I've watched many of your videos and sometimes several times, and i have not only learnt probability, but my english listening skills improved dramatically, to the point that i can understand anyone. My main language is spanish.

For 0.521 should we look at negative z-score or positive?

Great job sir! I love your work !

Thank you so much! However, still have not got WHY standard normal distribution has a mean of 0 and a standard deviation of 1. Could you explain that theoretically with examples, please?

You are very welcome MizzDivaThang!

This was very helpful. Thanks! I really enjoyed the enthusiastic voice. I am currently in an engineering statistics course at Georgia Tech and we have an exam coming up this week and I was looking through my notes and seeing that when we standardized, we used two different formulas. Sometimes we used what you just showed, and sometimes we used sigma / sqrt(n). Or sometimes, we use a sample variance and do stuff with it. Do you have any videos on something like that? I've been thoroughly lost:\

thank you for these awesome lectures!!

couldn't be explained any better...!!

@jbstatistics

10 жыл бұрын

Thanks!

YOU ARE AMAZING! the best explanation ever! And why you stop uploading videos :((( miss you and please come back sir! btwi love jimmy Snoothouse so much

@jbstatistics

7 жыл бұрын

Thanks so much! I'm going to get back to video production this year. I promise! Thanks for the Jimmy & Mr. S. love, I think they are underappreciated :)

You are welcome!

sir plz help me to solve this... ** Given a normal distribution with a mean of 60 and sd of 14, n=100 what percentage of cases will lie between the score of50 and 65??

Thanks so much! I'm a little boisterous by nature, and that can sometimes come off as a little over the top in videos. I try to rein myself in a little bit in my recent videos.

@adityashikhar6143

3 жыл бұрын

Sir you are great. A timeless beauty

Thanks!

i just got a question, the example #3 i very confuse the z=1.28. how can i got that value?? looking forward your answer,and your video is very good!!!

@jbstatistics

10 жыл бұрын

Thanks! You can find the value 1.28 from software or a standard normal table. There are different varieties of standard normal table, and I have videos outlining how to use them.

@93gretamat

10 жыл бұрын

jbstatistics soooo,I USE IT.. and its doesnt make any sense .. maybe i dont know.. but it can be more than 1… or can be

@jbstatistics

10 жыл бұрын

An area under the curve (which is a probability) must lie between 0 and 1. But a standard normal random variable can take on any finite value. For example, as given in this video, z = 1.28 has an area to the left of 0.90. The z value most definitely does not have to be between 0 and 1. If you don't know how to find values under the standard normal curve, I strongly recommend you stop doing anything else until you learn how to do that. (I have videos outlining how to use the table.) Trying to learn topics that involve the normal distribution, when one doesn't know how to find standard normal areas and percentiles, is not an efficient use of one's time.

@johndough7479

5 жыл бұрын

I still can't decipher how you got Z = 1.28 from .9? Good videos! ;)

@TheMohVEVO

5 жыл бұрын

@@johndough7479 Basically you just do the same procedure but in reverse. so look at your table and look at all the probability values, once you find the value that is 0.9 or closest to 0.9 you will find that it equals a Z value of 1.28.

can someone tell me why isit needed to STANDARDize a normla distribution? Im desperate.

I went to Khan Academy and after watching 2 videos i still hadn't found how to standardize the normal distribution.. thank you.

@jbstatistics

7 жыл бұрын

You are very welcome!

this is very useful, but im struggling to apply it to my practise questions, mean 21.8 deviation 1 create a graph to show between 19-24

incredible video, exactly what i needed!

@jbstatistics

8 жыл бұрын

+IIAndersII I'm glad I could help!

How could (x-mu)/sigma has a standard deviation of 1?

@jbstatistics

6 жыл бұрын

Suppose we let Z = X/2. The standard deviation of Z will be half the standard deviation of X. In general, if we multiply a random variable by a positive constant, the standard deviation gets multiplied by that constant. This is not too hard to show, starting from the definition of the variance. Adding or subtracting a constant doesn't change the variance. So if X has a standard deviation of sigma, then the standard deviation of (X-mu)/sigma is sigma/sigma =1.

YOU ABSOLUTE LEGEND!!!!!!!!!!!!, YOU DIDNT BORE ME ONE BIT, SUBSCRIBED!!

This video helped me pass my midterm

you the man jb

love all your content been helpful but i have a concern on the z value for the 90th percentile. i think it's supposed to be 1.29 rather than 1.28.

@acepriority4042

Жыл бұрын

will be grateful for a positive feedback. thank you!

@jbstatistics

Жыл бұрын

@@acepriority4042 In R: > qnorm(.9) [1] 1.281552

before reading fast version I was wondering why he was talking sooo fast thought he drank some coffee or was super excited about this

Great stuff dude. Thank you

Brilliant stuff!

wonderful specially with this tune

This is even harder than I thought

YOU ARE GORGEOUS !!

i went through all of your playlist last night and i think i am gonna ace today's exam. PS- You sound like white canadian version of morgan freeman ! (Y)

If all my teachers/lecturers spoke like sports commentators I'd never have trouble concentrating :) ty

Thanks so much ! This was brilliant ♥♥

Hi, I just got a question, when you standardised the distribution to find the probability of the height between 170. cm and 180.0 cm = P(-0.887 Can you please clarify on this matter and thank you for these great videos.

@jbstatistics

10 жыл бұрын

Thanks for the compliment about my videos, and you are welcome. Your value of 0.1148 is P(Z < 0.88) - P(Z < 0.52). We're looking for (approximately) P(Z

@MrDokshowof

10 жыл бұрын

Thank you for the reply, I really appreciate it.

@sidhurokrz

8 жыл бұрын

+jbstatistics So that is P(Z0.88)=0.1894 (normal right tailed table) ie. 0.6985-0.1894=0.509. Is this right? May be more accurate value would come up to 0.511 I guess, isn't it?

@jbstatistics

8 жыл бұрын

+sidhurokrz The values I give in the video are based on software (without rounding). If you use a table (with z values to 2 decimal places, and the probabilities rounded to 4 dp), then there will often be a small difference due to rounding error. Here, we cold use a table to find P(-0.89 < Z < 0.52) = P(Z < 0.52) - P(Z < -0.89) = 0.6985 - 0.1867 = 0.5118.

@sidhurokrz

8 жыл бұрын

+jbstatistics okay got it. well I'm lucky to have found your channel, You have answers to all my silent questions which I had during my stats class. I appreciate the efforts you have put in.Thanks for such conceptual explanation.

Great video! I was just wondering how you found the 90th percentile to be 1.28?

@adityashikhar6143

3 жыл бұрын

Well after 7 years, by use of tables of standard normal variable

This is super helpful! Thanks so much

@jbstatistics

5 жыл бұрын

You are very welcome!

How do you make stat look sooo easy! And now i understand it! :D

I wish you were my prof ur voice is the best

great ascent

JB statistics, whoever you are, wherever you are thank you.

@jbstatistics

7 жыл бұрын

I'm me, and I'm right here. You are very welcome!

Thank you so much!

Why does the quantity x - u = zero at the 0:50 point in the video?

@jbstatistics

3 жыл бұрын

It doesn't equal 0, it has a mean of 0. The mean of X is mu. The mean of X - mu is 0. More formally, E(X - mu) = E(X) - E(mu) = mu - mu = 0 (since the expected value of X is mu, and the expected value of a constant is just that constant).

@billygraham5589

3 жыл бұрын

@@jbstatistics Thanks

when ive got my skyrim disc sitting next to me calling my name..... lol, but seriously good job, i think your voice kept me interested somehow lol :p

Finally I understand standardizing. Whew!

awesome thanks, didnt even seem boring lol!

Thanks, I'll take a look right now. You should've taught at Tech! That would've been one better professor here haha

Future career in sports commentator

For the second example, isn't the P-Value of .521 = .6950? The P-Value of -.521 is .301.

You started sounding like Scott Manley for a bit at the end of the video. Love the enthusiasm. :D

Sold!

Thank you so much I wish i had you here with me to help my understand more. Sometimes i make things more difficult when there not. Then i was going to ask you to go slower a little for the slow math people but I saw the link about Thanks. This one person puts videos up and doesnt even talk uhm booooo.

Quality video

thank you so so much.

You're welcome! How could standardizing a random variable ever be boring?

Thank you this is very good video. Also you shouldn't care what people think about your voice or how you decided to teach what you know. There people are coming to you for FREE math help. You have to pay for this kinda stuff elsewhere. You should just do your videos anyway you want and if people have a problem with it, they can suck it. I've seen your other videos and I prefer this video, thanks again.

How the variance is 7.1? Wasn't it N(0,1) so 1?

@jbstatistics

2 жыл бұрын

Height isn't N(0,1); it's normal but has a mean of 176.3 and a standard deviation of 7.1. Once we standardize (subtract the mean and divide by the SD, we get a variable that's N(0,1)).

you are genius!!

@jbstatistics

5 ай бұрын

Nope, but thanks!