It's very simple if xy=35 then y=35/× and we can use it in x^2-y^2=24

@bkbzgaming

2 ай бұрын

This is literally so easy, I just took the only 2 prime factors of 35 and substituted them and it works

@qhawe_tricks

23 күн бұрын

We don't divide by variables

@ronniedurham

2 күн бұрын

Awful example

takes all of 3 seconds to solve by simple inspection: xy=35, the only factors of 35 that aren't trivial are 5 and 7. Checking 7^2-5^2 = 49-25=24. x=7, y=5. Similarly works with -7 and -5, so the answer is 12 or -12. No imaginary numbers necessary as far as I can tell.

@jensraab2902

8 ай бұрын

Well, imaginary numbers *are* necessary if you need to find *all* solutions.

Solvable by inspection. 35 is nearly prime, it only has 5 and 7 as prime factors. So x,y = 35, 1 or 7, 5. x+y = 12. ps. forgot -7,-5 as solns.

@ollie4276

Жыл бұрын

Omg....... I feel so stupid. I went into a rabbit whole of using polar coordinates. I got it, but in the most ugly way ever

@AlanCanon2222

Жыл бұрын

@@ollie4276 I love a convoluted proof!

@michaelbell5984

Жыл бұрын

But isn't that assuming integer solutions?

@ronrobinson3872

Жыл бұрын

i did same way and shes still going n and on and on ..lol

@fahim8682

Жыл бұрын

Ho do you apply the 2i into the equation?

Substitution is an easier approach, get x in terms of y from eq 2, substitute in eq 1 and solve the quadratic equation

@GereHadush

6 ай бұрын

Agreed 👍. The simpler is the better

@user-kv9pi6vo4j

6 ай бұрын

Это было гораздо более очевидным и простым вариантом

@Xingzi786

4 ай бұрын

I did same

x+ y can be 4 different things: 12, -12, 2i and -2i

it's just that 1x35 and 5x7 are the only quick integer opties to test out. I know x2-y2 is a symetric shape and xy=c a 1/x shape. thus 7,5 and negatives are properly the real solutions.

When squaring both sides of an equation, it is possible to introduce solutions that do not satisfy the initial system equations. Although for this particular system of equations, this will not change anything, imho it would be better practice to check the final result with the initial system of equations

@ArnabSanyalakaDeathStroke

2 ай бұрын

Actually, if you keep solving for x and y, you will see that the solutions are x = 7, y = 5; x = -7, y = -5; x = 7i, y = -5i; x = -7i, y = 5i All 4 solutions satisfy xy = 35, but while the first two solutions satisfy the other equation, the last two do not. This is exactly because of the squaring process. @LKLogic please check.

Alternatively, multiply the first eq by x^2 => x^4 - x^2*y^2=24*x^2 => x^4 - 24x^2 - (xy)^2=0 now plug xy=35 into this => (x^2)^2 - 24x^2 - 35^2 = 0 Note that this could be factored as follows: (Try looking at the factors in 35^2= 5*5*7*7 to find two numbers from this the difference of which would be 24 => You will find 5*5 and 7*7) => (x^2 - 49) (x^2+25) = 0 => x^2 = 49 or x^2=-25 You can take it from here that x can be either +7 or -7 which makes x+y +12 or -12.

@RenatoLousan44

9 ай бұрын

This only finds two solution of four needed, your method is good but only for real numbers. The other two solutions are imaginary numbers.

@neeldas8955

9 ай бұрын

@@RenatoLousan44you can apply [-b+-(b^2-4ac)^1/2]/2a to find the imaginary values

@Cekcom

6 ай бұрын

@@RenatoLousan44 Not at all. The other two solutions follows from x^2=-25: x = +- i*5 => {xy=35} => y = -+ i*7 => x+y= +- i*2

Man, they made this simple math problem complex

It is good to say in which set to solve the equation. x, y are Integer , Real or complex;

Interesting problem, thanks for posting

Wow what a beautiful question, i got 7 and 5, but missed the complex solutions. Again beautiful question.

I didn't know you can plug in xy in equation as I'm used to isolate variable first, thanks for teaching a trick to find the solution

@DuyHoang-mr1ob

9 ай бұрын

Có hiểu kết quả không? Phép tính cộng còn không biết thì học hành gì

I'd subst. k=x+y, m=x-y, because that is the obvious thing to do. Then km = 24 and k^2 - m^2 = 4xy = 140. Multiply with k^2: k^4 - 140 k^2 - 24^2 = 0 = (k^2 - 144)(k^2 + 4) and we're done.

Congratulations on reaching 1 Million Subscribers 🎉🎉🎉

Great video and great question

Parabéns. Exelente solução.

It's fun. I want to study math again after university. 20years ago...

X^2 + Y^2= -70 is not valid, since the sum of the square of two number is always positive, It must be X^2 + Y^2 = 70.

@TheLoveKusano

Жыл бұрын

what's the result of i² + i²?

@otakurocklee

Жыл бұрын

We are including complex solutions.

I solved it in 2 seconds. First approach was to see 35 is prime so x and y could be 7 and 5. To make sure 7 sqaure - 5 square is also 24. So x + y is 12

@jensraab2902

8 ай бұрын

Congratulations! You found one solution in 2 seconds. But what about the others?

@lnmukund6152

4 ай бұрын

Correct my idea is same Mukund

@EnriqueAThieleSolivan

9 сағат бұрын

@@jensraab2902 Once you get one the other follow as negative numbers squared give positive numbers, the there are the imaginary ones whose difference is in notation, putting the i.

Set Y ²= a, the equation is converted to 1225/a-a=24→ 1225-a ²= 24a, a=49, so Y=7, X=5

@kpdywo848

Күн бұрын

No Y=5, X=7 your solution give : X²-Y²= -24., so Solution is Y=5, X=7 and also Y=-5, X=-7, Two solutions X+Y=12, X+Y=-12.

If you define x + y ≡ k, you can consider that x and y are solutions of the following equation: X^2 - (x+y) X + xy = X^2 - kX + 35 = 0. So you can get x - y = √(k^2 - 140) by solving this equation. You can obtain x^2 - y^2 = (x + y)(x - y) = k √(k^2 - 140) = 35, which means k = ±12, ±2i. This problem is basic level for Japanese high school students.

@RTX2050izyygaming

11 ай бұрын

Can u explain it step by step, i want to learn ur way

@sozkev9762

9 ай бұрын

how soln of X^2 - kX + 35 = 0 gives x-y = √(k^2 - 140) ??? Is this comment a scam?

@ihave2enemies

8 ай бұрын

​@@sozkev9762No, x-y is difference of roots which is equal to root(D)/a where D is discriminant and a is coffeciant of x²

I don't know why but I found the result mentaly in about 10 seconds. x=7, y=5 and x+y=12...

Simply replace 24 with 24/35 xy, then solve the first equation, youbcan easily get x equals 7 ,and y is 5.

very interesting. should take less than 2 sec to solve xy=35 x^2-y^2 =24 Given that 35 is an odd number and a small number (a limited number sets to get 35), it is either 35*1 = 35 or 7*5 = 35. 7^2 - 5^2 = 24. So, x+y = 12. Am I missing something ???

@rmtsapphire0

8 ай бұрын

Yes, the negative solution -12 and the two complex solutions; 2i and -2i

@IamtheHolyMan

6 ай бұрын

The question does not say that x and y are positive or negative integers.

All of this is only needed in school exams,but to solve it faster we can just look at the factors of 35 which are 1,5,7 and 35,now after getting this we can put the value and just test,since 35²-1² will be way more than 24(just by looking we can know),we have to put the other value and voila we got the answer as x=7 and y=5

I did this by little more than random guesswork in about two freaking seconds! The first two factors of 35 that came to mind were 7x5. 7 squared is 49, 5 squared is 25, 49 - 25 is 24.

@JerryRigged

8 ай бұрын

Lol same

@hellowill

7 ай бұрын

Ya not sure why easy questions are getting heaps of views. I guess school kids are studying using KZread.

Aren't you introducing extraneous solutions when you square both sides at 0:55?

The difference between squares is twice the summation of all natural numbers between the two terms, less the sum of the two terms ( the sum from x to y, time two , minus x+y) - it makes finding the answer much easier

@jesseshaffer3951

Жыл бұрын

5 , 6, 6, 7 = 24

Denote P = x^2, Q =- y^2 Then P and Q are the roots of t^2 - 24*t - 35^2 = 0

@59lotus52

Жыл бұрын

This is correct and the most beatiful solution! Answer is 12 or -12

This can be easily resolved in complex digits, x and y determined.

Number pairs whose product result can be 35, 5x7 and 1x35

I am a little surprised that one would be expected to just know 5476 is 74^2, although I suppose in a test problem one might guess that it would be a perfect square and it would not take long to find the square root, but, as several Commenters remark: one can see by eliminating y that there are four solutions expected since a quartic for x results. Since by inspection {x,y} ={7,5} and {-7,-5} are obviously solutions, it takes little more thought to realise that similarly {5i,-7i} and {-5i,7i} are the others and the results for x+y follow.

@User-jr7vf

7 ай бұрын

She knew tht 5476 is 74^2 because she solved the problem before recording for KZread, and she probably used a calculator to get to that result. Don't fool yourself, nobody is expected to know that from memory.

@nando9723

6 ай бұрын

Here’s how I did it. You can see that 5476 is a factor of 4 and so split it up into 4*1369. Then it’s a matter of finding the square root of 1369. This is clearly between 900 & 1600 and a square number only ends in 9 if the square root ends in 3 or 7, therefore if 1369 is a square number then the square root is either 33 or 37. Since it’s closer to 1600 than 900 that suggests it could be 37^2. It doesn’t take long to try calculating 37^2 by hand and it turns out that it is indeed 1369! Therefore 5476 = 4*1369 = (2)^2 * (37)^2 = (2*37)^2 = 74^2 :)

@tassiedevil2200

6 ай бұрын

@nando9723 Nice! Square root is easier than I first thought, although I still prefer the approach I offered.

Two more solutions. X = 5i, Y = -7i Or X = -5i, Y = 7i Where i = square root of -1.

@Barghaest

11 ай бұрын

Both covered by x+y=2i or -2i.

The squares of which numbers when the larger is taken from the smaller leaves 24.? what happens when these are added.......?. 12........,.,

한국어로 답변해서 미안하지만 답은 두개지만 한개로 5와7 입니다. 수식을 어찌저찌 계산하던 구구단 공식 35의 답은 5와7로 곱을했을경우입니다. 그래서 그결과의 x+y= 12 빠른 돌출된 결과 나옵니다.

Why the algo choose to place this video in my stream surprises me. As to why I actually tried and watched the solution baffles me even more. My days of spending my holidays solving calculus problems from Thomas & Finney were in the last century

The use of videos like this escapes me. If you already know maths, know the principles involved and know what to infer from the question, surely you could do this solution yourself. Numptys like me, who check out at the 30 seconds mark, would benefit from an explanation of the problem and the steps and tools required to solve it.

Just factor 35 into 7 and 5, 7sq=49 minus 5sq=25 equals 24. So 7+5=12.

This feels more like a middle school algebra question, if this is what passes for math Olympiad these days I fear over who will be designing bridges in our future.

@alchemist9905

8 ай бұрын

lol. I guarantee you the engineers actually making a bridge would have just gone for the simple but obvious +,- 7 and 5 as solutions for x , y

I simply went to equation 2, and got 7x5 =35. Then 7²=49 and 5²=25, giving me 24. Then 7+5=12 Take the simple way. It can save you a bunch of time.

@bowlchamps37

11 ай бұрын

Yeah, save a bunch of time, but x+y=12 only gets you 2 out of 10 points for the question.

Why do you keep putting parentheses on numbers when marking 24 squares😫😫😫

Great ,thanks very much

x²-y²=24 et xy=35 --> x=35/y --> (35/y)²-y²=24 Multiplions par y² et regroupons on a : 1225-y^4-24y²=0, posons y²=Y, l'équation devient: -Y²-24Y+1225=0 --> deux solutions Y'=-49, Y''=25. Alors seul Y''=25 fonctionne puisque Y=y², -->i y=5. Puis : x²-25=24 --> x²=49 --> x=7. Alors x+y=12, et cela fonctionne avec x=-7, y=-5, x+y=-12... Inutile de travailler dans C.

What’s wrong with 7 and 5 as immediate answers?

I can only say it is a shame for International Olympic Committee to have a question like that.

Try to solve it via integrals and dif. functions. Solving is to be harder

Try this: X^2 - Y^2 = (X+Y)(X-Y) = 24. Let Z = X+Y, then X-Y = 24/Z, (X-Y)^2 = X^2 + Y^2 - 2XY = 24^2/Z^2 = 576/U, where U = Z^2. Also U = Z^2 = (X+Y)^2 = X^2 + Y^2 + 2XY, subtracting the previous equation from this gives 4XY = U - 576/U, U^2 - 140U + 576 = 0. Observing that 576 = 144*4 we can factorise to get (U - 144)(U + 4) = 0, i.e. U = Z^2 = 144 or -4. Only 144 gives the real answer Z = X+Y = 12.

All this math and it’s too complicated. Sometimes you just have to “see through the trash”. Not too many integers where the product of them is 35. In fact the choices are 1 and 35 or 5 and 7. Simply try that first and you’ll find that if x=7 and y=5, the x^2-y^2, 49-25=24. X+y=12

Why you don’t substitute y=35/x in the other equation given not equal 0

teşekkürler elinize sağlık

In the later solution , It seems (x+y)² = (x²+y²) I can't understand why?

Easiest math olympiad question ever

@Vertical-Limit_BURST

8 ай бұрын

You said it. Even I was able to solve this in 5 minutes lol

Yeah, an equation of two polynomials from the second degree has 4 solutions in |C (for a perfect demonstration, you should have added a line x and y are both =|= 0, so you can resolve for the rest, but given the problem, it's obvious.)

the only number that i can think of xy =35 is 7x5. 7x7=49, 49-24= 25. 5x5=25 x=7 y=5 x+y=7+5= 12

you are good at math。very nice person。

Simple 35 has only one combination - 7 & 5 Therefore x=7 and y=5

X+Y=2M, X-Y=2N,X=M+N, Y=M-N, MN=6, M^2-N^2=35, M^2(-N^2)=-36, M^2=36, -N^2=-1, M=-+6, X+Y=-+12

I wonder if there such property which allows you take power to both side of an equal equation. For instance, if a = b, can you say that a^2=b^2? is true that you can do this, a=b, then a.a = b.b? I don't think so. 🤔

@service7755

10 ай бұрын

Dude. Your example is wrong. Think. Whay are you multiplying different number on each side?

Hint: 49 - 25 = 24. The instructor has a lovely feminine voice. I could listen to her reading a telephone book.

This was so satisfying...

Congratulations

@LKLogic

Ай бұрын

🫶🏻

Just eyeball it and see 7 * 5 = 35 and is the answer for both equations.

great 👏🤘

iam more simple, there is only one solution for: xy=35, easy as 7x5=35, it just match for x²-y²= 24, so x+y must be 12

Thanks you

The question doesn't say X and Y are integers.. Therefore it's wrong to get X=7 and Y=5 immediately.

@saigonsong1954

Жыл бұрын

Ok

@Generalist18

Жыл бұрын

That what I also thought

@user-up4sj5yv6d

Жыл бұрын

(x,y)=(7,5)或(-7,-5)故x+y=12或-12

@suryaentertainment5028

Жыл бұрын

​@@user-up4sj5yv6d 🎉

@mathbigsmart

Жыл бұрын

Ur right

vvery very impressive

x=7 y=5 x + y=12 or x=-7 y=-5 x + y= -12 I solved the equation in my mind

35 is only divisible by 1, 5, 7 no need to overthink this; just use your times tables. Oh and obviously itself.

this one was too simple.

@oluwatosinakinpeloye5111

Ай бұрын

True but tricky at first

X^2+y^2 is always positive dear

Quadratic simultaneous equation

7 и 5 , методом подбора решается за 2 секунды

@scuendo

7 ай бұрын

если не считать комплексные числа, то ты минимум пропустил -5,-7 и ответ на вопрос «-12».

Well we all know it's x=7 and y=5, but we needed that demo

Much easier if you simply solve the system of 2 first equations

Are You sure its South african olympiad ? Because ive seen the same exercice with a title : Indian olympiad and Bihar Olympiad.

Jeez this is substitute problem You substitute to maid only one unknown - either x or y.

Seriously, you could’ve just used substitution right from the start. It would’ve been easier.

A typical soviet schoolboy solve this in 2 minutes

1×35 or 5×7 that' all. square of 7 - square of 5 = 24. Therefore 7+5= 12.

As an engineer I find all the math amusing. There are only two integers that are factors of 35. Why do so much algebra when the answer is right there? 😮 Oh wait, this is an olympiad and the easy way would be wrong...

@jensraab2902

8 ай бұрын

It's a Math Olympiad, not an Engineering Olympiad! 😛 That's why they most likely want to have *all* solutions.

The square root of a number is just a positive number not plus or minus a number....

@jensraab2902

8 ай бұрын

Yes, the square root symbol is used for the principal root (the positive one when referring to real numbers); she didn't use the notation correctly. But her solutions are correct nonetheless because we're dealing with quadratic equations which in this case yield one positive and one negative solution.

I think my brain getting rusty already

За пол-минуты в уме решил.

35 = 7 X 5 So x times y = 7 times 5 x^2 - y ^2 = (x +y)(x-y) = (7+5)(7-5) = 12 times 2 = 24 so x + y = 7 + 5

Sees title Me: Brain.exe has stopped working

uhmm you can do more easy way, 35 is 35*1 or 7*5, you test in the cuadratic equation and is fast probe 7 7 and 5 works

Все такие умные 😁, а кто нибудь нашёл корни этих квадратных уравнений, потом подставил их в искомую сумму 😂 листа бумаги хватило😂

This one is so easy. I don’t want to spend time on solving it

Just by looking at them you can say it is 7 and 5.

La gorma mas facil y rapido de resolverlo es despejando el valor fe X o Y....de la ecuscion XY = 35, X= 35/Y....luego reemplazar en X2 - Y2. Llegamis sl trinomio cuadrado perfecto que de resuelve por factorizacion y da como resultado X = 7, Y =5

Why are you just not removing Y as a variable by saying that Y = 35/X?

There are infinite amounts of ways to solve this and you picked the nost complicated and confusing one.

An unnecessary complication. I'ts enough to do a simple variable substitution in order to get a bi-quadratic equation (solved transfoming it in a quadratic equation).

12

South Africa Olympiad is easier than Maths exam of 10th standard in India 😂😂😂😂

7 and 5, -7 and -5. If you can't do it in your mind in less than one minute you'll better go back to junior high school fast.

@oenrn

11 ай бұрын

Once you graduate from junior high school you will learn that complex numbers exist.

I LOVE MATH ❤❤❤❤😊

X=7 Y=5 X+Y=12