Me, an intellectual: „Ah yes pi=0“

@thibaudjacolin-buffard9397

3 жыл бұрын

I don't get it

@cameronschyuder9034

3 жыл бұрын

@@thibaudjacolin-buffard9397 every number to the zeroth power is equal to one. Of course pi doesn’t equal one, but the joke is that the person is making themselves by saying they’re an “intellectual” and following that up with a clearly wrong statement in order to simplify solving the problem for themselves

@thibaudjacolin-buffard9397

3 жыл бұрын

@@cameronschyuder9034 ho ok thanks I'm french and I try to learn english with this channel but understand jokes in an other language is pretty hard

@lucifugerofocale5847

3 жыл бұрын

@@cameronschyuder9034 pi=3 this comment was made by the engineer gang

@nickwilson3499

3 жыл бұрын

@@lucifugerofocale5847 pi = 3.15 This comment was made by the average guy

0:59 Look at the change of his face😂

@alejrandom6592

3 жыл бұрын

Lol

@justalazyguy.0_0

3 жыл бұрын

You ruined the comment with the edit

I love the way you turn maths into a fun sport

@jamirimaj6880

3 жыл бұрын

Blindfold Math Olympiad, now that's gonna be money $$$

@fakeAtlas6080

3 жыл бұрын

to be fair, if you don't speedrun linear algebra you aren't living

@marcoparco_9564

2 жыл бұрын

I hated math until I met my 9th grade math and physics teachers, his punchline was "math is a party" and ever since I've been addicted

His face's saying "Is it so bad? Do I have to do it again?.. *thinking* ..Nah"

I have no clue why he was holding a pokeball the entire time, but I loved it

@onokr705

3 жыл бұрын

thats his mic, i think

@spizarro5577

3 жыл бұрын

His Squirtle was telling him what to do

@Yadobler

3 жыл бұрын

he's hiding his microphone in it, else it would be an awkward black ball he'd be holding

@venkatesh662

3 жыл бұрын

@@onokr705 yes that's a 🎙️

@acn121

3 жыл бұрын

@@venkatesh662 why are you using emojis instead of words

result u see....hard work behind it you don't see...hats off to u sir

The way he looked at the board in the end is like "i'm proud of myself"

Wow, I didn't expected that the solution was so simple. Proof of my need to learn more xD

@scares009

3 жыл бұрын

We all learn something new every day

@amir3515

3 жыл бұрын

@@scares009 every millisecond technically

You're just awesome. You make videos with short length so that we can enjoy cool math tricks without wasting our time. Hats off to you.

Love this idea, and complex analysis can never be over done

He didn't even took a retake, what a legend.

One of my friend told me to see your 100 integral video ,and now I am bing watch your channel you make me feel math can fun and impressive.🤗🤗👌

This put a smile on my face. Thanks!

Beautiful! This videos have helped me see numbers in a very different way and find solutions to seemingly impossible broblems. Sincerely thenk you for the amazing conten and for making math fun.

i love you blackpenredpen!!

"This is good" Absolutely!

Love your smile! Thank you from California

I love your confidence. And your beard. It's breathtaking.

When you uses a weird unrigorous method but still arrive at the correct result

@ScandGeek

3 жыл бұрын

How is it unrigorous?

@alejrandom6592

3 жыл бұрын

@@ScandGeek It's just an analogy to the fact that the result is well written but the previous steps are out of place. I'm not saying the math is unrigorous

@tttm4rt1n49

3 жыл бұрын

@@ScandGeek you just make both sides to the power of 1/pi and you got x=1^(1/pi)=1

BFBPRP Blind folded black pen red pen

@ilickcatnip

3 жыл бұрын

I mean, Wow

You're the man, Chow 😄👌

@bprpfast

3 жыл бұрын

Thanks!

I did the exact same thing but I forgot the integer n. Your videos are so good honestly.

Love how this man is flexing!

Alright i gave up. I cannot switch my pen blindfolded that smoothly.

Perfect!😙

You are magician !!!!!

Me as an intellectual : 1.. 1^anything is 1 so x=1... XD

He looked at all he had done and saw that it was good.

Find value of (-1)^π blindfolded.

I agree: "This is good".

He even switches colours like it's nothing

@shashankgn6168

3 жыл бұрын

Cuz he's bprp

What I just realised is that this means that there are infinitely many points on the complex unit circle that never align with each other that satisfy this equation, but still not every point on the complex unit circle of course.

BPRP I'm hereby requesting you plot any quadratic graph blindfolded. Let the curve touches the two x intercepts.

I can hold the pokeball... That all I can contribute to this question.

That was nice

I was trying to watch this blindfolded but I failed miserably

That pokemonn ball has a seperate ban base

The difference between any two consecutive interior angles of a polygon is 5°. If the smallest angle is 120°, find the number of the sides of the polygon.

"Thes is gudo" - this guy

Ah yes gojo sensei from pokemon is teaching us mathematics

bprp blindfolded

How about solving an integral blind folded?

1 is automatically a solution 1^x=1

Since, e^2πni = 1 Then, 1^{1/(2πni)} = e ---(i) Now e^(?) = 2 Well clearly, e^(ln2) = 2 rising both sides of (i) to the power ln2 :- => 1^{(ln2)/(2πni)} = e^(ln2) =2 Therefore we get, 1^{ln2/2πni} = 2 or, 1^{(i×ln2)/(2πni × i)} =2 Therefore, 1^{((-i)ln2)/2πn} = 2 [n belongs to Z] so if we were to find 1^x = 2 Then the value of x would have been, {(-i.ln2)/2πn} 😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😳😮😮

What do you advise me to learn mathematics

Hey, how about value of (-1)^π blindfolded.

@arjunsheth3303

3 жыл бұрын

Negative no.s can't be defined if their power is not perfectly defined Like if u had -1 to an odd root then u would get a value for sure like -1^(1/3) But if it had been (-1)^(1/2) then it wouldnt be defined as real If u can't decide if the no. is real or not then u can't define the no. Itself Something like that¯\_(ツ)_/¯ Maybe i should check it out first.... Edit: Yep should've checked lol Its easily doable using Euler's form of complex no.s

@mathevengers1131

3 жыл бұрын

You can find value of (-1)^π in complex world.

@arjunsheth3303

3 жыл бұрын

Yepp should've checked it out first 😅 I got it confused with a concept of limits lol Thanks for clearing it up!

@mathevengers1131

3 жыл бұрын

Welcome.

If we are taking exponents then x can be any a raised to 0 then x raised to π will always be 1

What is the range of xe^-x on (0,infinity)???????????

The Force guided u when u wrote with covered eyes.

People: pi Me: *PIE*

Sir slove this The difference between any two consecutive interior angles of a polygon is 5°. If the smallest angle is 120°, find the number of the sides of the polygon.

Can you say some tricks on indefinite integration

1:01 *Awkward laugh* This is good tho :) *Silence, turns to camera* :D *Finishes* Well, whatever!

Sir, what is the value of o√0 .

Can I ask why you hold that pokeball in your hand.

This may be just me not thinking right enough, but wouldn't exp(2ni) equal 1 in an (a+bi) form, which means it's a single solution in practice?

I cant even do this with open eyes

We need bloopers

This only works for n=1 in my calculator. For n=2, for example, i get (e^(2*2*i))^(pi) about equal to 0.63-0.78i, when it should be 1.

If gojo satoru was a math professor

Easy: x = 1 cause 1 raised to any power = 1. More algebraic approach: x^pi = 1 (x^pi)^(1/pi) = 1^(1/pi) [raise both sides by (1/pi) x^(pi * 1/pi) = 1 [Simplify. exponents can multiply and 1^n = 1] x^1 = 1 [simplify] x = 1 [simplify. n^1 = n] QED.

Eyes : this looks like easy Hand : yeah we can solve this question Brain: WTF are u crazy?!

Yo I need that magical blindfold.. I have my maths exams next week so please send me asap sir!!!🙏

I think I can actually do this one! It’s cos(2) + isin(2), right? There’s gotta be a family but that’s the main one.

@christermi

3 жыл бұрын

Yes, the family cos(2h)+isin(2h) , h integer , is the answer to the equation.

I don't know about complex numbers, does the result you found mean that there are infinite roots or something?

@cyberclash2814

3 жыл бұрын

I think yes but I don't know either

Substituting value , x=-(b) ±√b²-4ac/2a , in equation :ax²+bx + c=0. Could you please solve.

The real answer: x = 1. The other 2 or 3 answers are virtual

This is why we pay for the internet

Do Pi root both sides.

His pen colour switch is way harder to solve

When will you throw that Pokemon ball?

Me as a JEE aspirant find it so easy.In India these stuff are being taught in 11th standard..I liked the way you make mathematics fun👍

@sumeadhms3482

3 жыл бұрын

Hell no😂As a jee aspirant i say that, its only taught in 12th . we only get taught with basic calculus in 11th. Just becz u know it ,u can't genralise for whole india

@anupamjha3226

3 жыл бұрын

@@sumeadhms3482 In india means in iit jee criteria not all science students

@anupamjha3226

3 жыл бұрын

@@sumeadhms3482 it is something like nth root of unity

@sumeadhms3482

3 жыл бұрын

@@anupamjha3226 ok this topic comes under complex numbers and as i am halfway through 11th i dint learn that chap yet

@nikhilnagaria2672

2 жыл бұрын

if you find it easy, then tell me when is the given answer true? Any calculator will tell you (e^4i)^π is not 1.

can i just take natural log both side and get : pi ln(x) = 0 then divide by pi : ln(x) = 0 and finally expo : x = e^0 = 1

i bet he did it more than a dozen times

I solved this before I click on this video, take natural log to both sides then divide by Pi, then raise both equations to ''e''. ln(1) is 0. Therefore, e to the power zero = 1

Hello everyone. I have a lot of good math exercises for you all.

Yeah, i understood everything... uhum, off course.

I dont get it, but i like it

this is good tho

Jee students can relate it with complex no.s

Me as an intellectual: X^pi = 1 X^pi =1^pi X=1

Anyone else still wondering why he's got a pokeball

Do Int of cube root of tanx dx

What is limit of x^-x in +∞ and -∞.

or you just make both sides to the power of 1/pi and you got x=1^(1/pi)=1

Did he write an infinitesimal?

Value of pie I dare you

Surely something's gone wrong. (e^6i)^pi does not equal 1,for example. This only looks to work for n=1 when I put it into my calculator.

Good

isnt just the solution 1? because 1 to the power of everything is 1

e^2pii=1 e^pii=-1 x=e^2pii or e^pii + 2 or 1

me: x=1

Why does the dude always hold a poke ball tho

0:14 Who needs real numbers? WE ARE ALL ADULTS NOW.

Differentiate x^x

Hey could u able to solve y=sin(x-1)

When he is using 2pi instead of tau:

0:56 his efforts could be traced

x is 1, as 1 to the power of anything is 1.

Is f(x) =x^(1/pi) injective??