Solve differential equation with laplace transform, example 2
inverse laplace transform, inverse laplace transform example, blakcpenredpen
Жүктеу.....
Пікірлер: 98
@EagleLogic6 жыл бұрын
Started the video, paused, went to my marker board and solved it! Then skipped to the end and I saw that I got it right. First time I have solved one of these on my own. Your help has been HUGE! Thank you!
@blackpenredpen
6 жыл бұрын
I am very glad to hear this!!!!
@gigispence60114 жыл бұрын
Spent the last week panicking about Laplace transforms - all of that anxiety vanished after watching this video! Thank you
@blackpenredpen
4 жыл бұрын
Glad to hear!!
@OussamaAbuUmar4 жыл бұрын
You just taught me more than my professor taught me in a whole semester❤
@xuhanzhen81265 жыл бұрын
学到了啊 待定系数还能这么拆 很棒的细节讲解
@ahmed_42945 ай бұрын
Seriously one of the best teachers I've ever encountered both on youtube and real life. I salute you! Thank you for explaining every detail of your solving and making sure we understand every step you take
@yeyito36765 жыл бұрын
thank you so much for explaining where the partial fraction decomposition comes from!
@bernaskojohnarthur36605 жыл бұрын
Your tutorials are the best just that I'd like to comment on this and a previous video about this same IVP that you should note the way you write your (Y and y). It conflicts as to know which is the laplace and the inverse laplace, Just to help amateur like me. Thank you for your best explanation.
@aanchalchaudhary164 жыл бұрын
your video makes concept crystal clear
@bizzysiru4 жыл бұрын
i am a student on uni. at south korea. thx your class. it a big help for me.
@Conditional_Finality7 ай бұрын
I dont really know why professors in my uni just does not go into this much depth into explaining a single example. The way he teaches me reminds me of my high school teacher who used to make complex problems easily digestible.
@Zonnymaka6 жыл бұрын
Just for the sake of trying the convolution formula i solved the partial fractions s/(4+s^2) + 2/(4+s^2) + 1/[s^2(4+s^4)]. Nice!
@andersjohnson90654 жыл бұрын
Watching this during my Calc 4 exam, thank you very much my dude
@skshabbir10125 жыл бұрын
Lots of love for you sir.. 😍😍😍 From Bangladesh.. Your method was super easy to get the problem..
@wync22035 жыл бұрын
woaahh i never knew laplace is this easy..thank you sir, tutorial appreciated!
@jemcel03976 жыл бұрын
I want to comment that you can use residue method to get A/s. To do so, we will consider P(s) = (s^3 + 2s^2 + 1)/(s^2 + 4). Then, we can differentiate P(s) but we have to divide it by n! where n is the number of times differentiation can occur. (In this case, n= 1) because s is only repeated once. P'(s) = [(3s^2 + 2s)(s^2 + 4) - 2s(s^3 + 2s^2 + 1)]/(s^2 + 4)^2 From the previous cover-up: s = 0 so we have P'(0). Then, you can plug 0 into your function. After applying differentiation. You'll be surprised you'll get the same answer for A.
@latrellebrown79165 жыл бұрын
I don't sub often, I am about to graduate this year and you earned it!
@MrSimmies10 ай бұрын
Absolutely perfect job. Thanks!
@ayandamtolo83125 жыл бұрын
Bro thanks so much for all youve taught me, in this case wouldn't it have been easier to solve using method of unconfirmed...
@rutgerlight74925 жыл бұрын
You're a good tutor! Im about to comment because i got confused in the A/s +B/s2 ... but you discussed it well ahhaha slow clap*
@falkinable6 жыл бұрын
Great work! Technically shouldn’t all of this be multiplied times the unit step function, which would be the same as saying “for t >= 0?”
@sanmuga2776 жыл бұрын
Dude You are the best !!!!!! I owe You 20 Marks!!!
@blackpenredpen
6 жыл бұрын
Thank you!!!!!!!
@tiibrahim57146 жыл бұрын
You've helped me a lot thanks
@marlenabigailrojogarcia55525 жыл бұрын
Me gustaría entenderte en el idioma pero observando tu procedimiento me a ayudado, gracias
@MrKristian2522 жыл бұрын
Thanks a ton, now I feel very motivated
@ChefSalad5 жыл бұрын
You can use cover-up to solve for C and D. Just make s=2i and substitute in. You get 2i+(-7)/(-4)=2i*C + D, therefore D = 7/4 and 2i=2i*C, thus C = 1. BAM!
@user-wu8yq1rb9t2 жыл бұрын
Thank you so much dear Teacher 💖
@1StraightPath2Islam5 жыл бұрын
Great job man, really good explanation. I think whats so hard to understand is how the denominator is split up into A, B etc. I've taken earlier courses that covered it, but not in the same extend that these exercises need.
@harleyspeedthrust4013
3 жыл бұрын
look up "partial fraction decomposition"
@wisphyr7 ай бұрын
this guy saved my life
@braskcovroldinin88162 жыл бұрын
This vid helped me more then books
@petersonkomane2689 Жыл бұрын
is there a playlist for this kind of problem's?
@5stepshred3006 жыл бұрын
Sorry man but I had to.... Pause the video to comment and give you a thumbs up! So glad I subscribed, great work!! Thank you!!
@ayshaalshamsi83304 жыл бұрын
Thank you so much!😭😭💕💕
@john-athancrow41696 жыл бұрын
Yes, I just said "isn't it?" just like Y O U ! ! !
@blackpenredpen
6 жыл бұрын
Yay!!!!!!!
@kibetbera91945 жыл бұрын
Thank you
@vahdetdelikaya16962 жыл бұрын
Love this!
@cjdiaz10995 жыл бұрын
this deserves more likes than those useless travel vlogs
@ronaldrosete40863 жыл бұрын
I can't find your Laplace playlist.
@lucvaniperen39645 жыл бұрын
Bedankt maat!
@juniorjay0014 жыл бұрын
wow. thank you
@user-bu8mg7uq3s2 жыл бұрын
thank you
@john-athancrow41696 жыл бұрын
If that s³+2s²+1 was s³+2s²+s, you would do: s³+2s²+s=s(s²+2s+1)=s(s+1)²
@ibrahimelosta74224 жыл бұрын
The best
@walter81544 жыл бұрын
your voice is asmr to my ears
@davitgurgenidze63074 жыл бұрын
very kind smile
@MajedHQ145 жыл бұрын
Is that a microphone
@john-athancrow41696 жыл бұрын
Aha! You want to look the 4 as 2², isn't it?
@HandlingSmilus Жыл бұрын
Math is beautiful
@edwin9966336 жыл бұрын
Weird thing. My teacher use this equation in our assignment
@xxslysinxx
6 жыл бұрын
Did you write your answer in black pen and red pen?
@sajjadkareem6085 жыл бұрын
Best way to solve DE is with Laplace Tf
@harleyspeedthrust4013
3 жыл бұрын
agreed, unless u dont have initial conditions then my favorite way is variation of parameters
@obeidaalamery10286 жыл бұрын
Very good
@manyielkoth2221
4 жыл бұрын
As long as you are getting him
@Flanlaina4 жыл бұрын
I distinguish my s and my 5 using cursive handwriting
@mcqueenweiyang38553 жыл бұрын
may i know why so i have to add CS + D and your peevious dont need?
@carultch
7 ай бұрын
For linear terms, you only need a constant for the numerator. For irreducible quadratic terms, you need to set up a linear term for the numerator. If you had an irreducible cubic, you'd use a quadratic term for its numerator. It wouldn't help you very much for either integration or Laplace transforms, but that's what you'd do in concept. In general, the polynomial on the top, is one degree less than the polynomial on the bottom. Sometimes, the linear factor turns out to just be a constant, other times, the linear factor turns out to only be the term with the variable
@ServitorSkull2 жыл бұрын
that pen swish doh 15:10. Swag
@damiandassen77636 жыл бұрын
5:00 20 seconds does not equal 50 seconds unless we are moving fast away from each other and relativistic effects take over.
@katherinebaloch74196 жыл бұрын
What is the laplace of sint
@carultch
8 ай бұрын
1/(s^2 + 1) Cosine has the s up top, sine has the constant.
@rashidibrahim9793 жыл бұрын
I found "A" to be 1/2 no zero
@syavv75145 жыл бұрын
I love youuuuu
@tarekkhalifa86343 жыл бұрын
ليه حطيت T=1/s^2 ???
@tarekkhalifa8634
3 жыл бұрын
why ?
@MrNdog10007 жыл бұрын
Pointing out the seemingly obvious, but you forgot to multiply by 2 inside the cosine inverse LaPlace and the 1/2 outside, so it should be 1/2* cos(2t)
@blackpenredpen
7 жыл бұрын
Steven Tucker u only have to do that for sine. Cos is ok
@shirashira88712 жыл бұрын
how we can get D=7/4 like how 2 become 8/4 - 1/4 = 7/4 just how that 2 become 8/4 sorry if my question is so complicated .
@carultch
7 ай бұрын
Given: (s^3 + 2*s^2 + 1)/(s^2*(s^2 + 4)) I like to set up the terms for Heaviside coverup first, which in this case is A: A/s^2 + B/s + (C*s + D)/(s^2 + 4) At s=0, cover up s^2, and find A: A = (0+0+1)/(0^2 + 4) = 1/4 Reconstruct: (s^3 + 2*s^2 + 1)/(s^2*(s^2 + 4)) = 1/4/s^2 + B/s + (C*s + D)/(s^2 + 4) Multiply by s, to partially clear the fraction: (s^3 + 2*s^2 + 1)/(s*(s^2 + 4)) = 1/4/s + B + (C*s^2 + D*s)/(s^2 + 4) Take the limit as s goes to infinity, to set up our first equation: 1 = 0 + B + C B = 1 - C Pick two values of s we haven't used yet, to create two more equations. I'll choose s=1 & s = -1 s=1: (1^3 + 2*1^2 + 1)/(1^2*(1^2 + 4)) = 1/4 + B + (C + D)/(1 + 4) 4/5 = 1/4 + B + (C + D)/5 20*B + 4*C + 4*D = 11 s = -1: ((-1)^3 + 2*(-1)^2 + 1)/((-1)^2*((-1)^2 + 4)) = 1/4/(-1)^2 + B/(-1) + (C*(-1) + D)/((-1)^2 + 4) 2/5 = 1/4 + -B + (-C + D)/5 8 = 5 + -20*B + 4*(-C + D) -20*B - 4*C + 4*D = 3 Add equations to cancel B & C terms and solve for D: 8*D = 14 D = 7/4 Use original equations to solve for B&C: 20*B + 4*C + 4*7/4 = 11 5*(1 - C) + C = 1 -4*C + 5 = 1 C = 1 B = 1-1 = 0 Result: 1/4/s^2 + (s + 7/4)/(s^2 + 4)
@phindulobidi77095 жыл бұрын
His using 2 markers one hand
@sunainas79064 жыл бұрын
This is so tough
@hakeemnaa2 жыл бұрын
not difficult, but very easy to make a mistake
@hanaa.r_7 ай бұрын
I don't understand at 6:45
@hanaa.r_
7 ай бұрын
How when 1/4 we put in A
@AndreSimoni946 жыл бұрын
hm, so you don`t use the +1...
@5stepshred300
6 жыл бұрын
Good observation, did you forget to use the +1?
@blackwatch7572
4 жыл бұрын
hahahahaha temos um ancap por aqui.
@rob8765 жыл бұрын
Worst way to solve a linear ODE. How about a non-linear ODE example?
@blackpenredpen
5 жыл бұрын
Hi Rob!
@jammcrusader1981
4 жыл бұрын
lol dude - its about learning the method
@harleyspeedthrust4013
3 жыл бұрын
dude its just an example to get the hang of laplace transforms chill out dickwad
@joshuamitchell3595 жыл бұрын
The way you do partial fractions doesn't make a bit of sense...
@blackpenredpen
5 жыл бұрын
Which part confused you?
@joshuamitchell359
5 жыл бұрын
@@blackpenredpen Actually, I totally confused myself while I was doing the problem along with you. I missed an "s." It made perfect sense! Sorry about the inconvenience!
@blackpenredpen
5 жыл бұрын
Joshua Mitchell I see. 😎
@tjtaneja12855 жыл бұрын
Literally the partial fractions is so unnecessary and it takes up over half the video, without taking the common denominator and keeping it as three seprate fractions we coud have taken the inverse laplace much easier with a VERY easy convolution to solve at the end
@harleyspeedthrust4013
3 жыл бұрын
yes but in general you want to avoid convolutions. the point of the laplace transform is to solve the problem without actually doing calculus, so if you can find partial fractions then you should do that instead
Пікірлер: 98
Started the video, paused, went to my marker board and solved it! Then skipped to the end and I saw that I got it right. First time I have solved one of these on my own. Your help has been HUGE! Thank you!
@blackpenredpen
6 жыл бұрын
I am very glad to hear this!!!!
Spent the last week panicking about Laplace transforms - all of that anxiety vanished after watching this video! Thank you
@blackpenredpen
4 жыл бұрын
Glad to hear!!
You just taught me more than my professor taught me in a whole semester❤
学到了啊 待定系数还能这么拆 很棒的细节讲解
Seriously one of the best teachers I've ever encountered both on youtube and real life. I salute you! Thank you for explaining every detail of your solving and making sure we understand every step you take
thank you so much for explaining where the partial fraction decomposition comes from!
Your tutorials are the best just that I'd like to comment on this and a previous video about this same IVP that you should note the way you write your (Y and y). It conflicts as to know which is the laplace and the inverse laplace, Just to help amateur like me. Thank you for your best explanation.
your video makes concept crystal clear
i am a student on uni. at south korea. thx your class. it a big help for me.
I dont really know why professors in my uni just does not go into this much depth into explaining a single example. The way he teaches me reminds me of my high school teacher who used to make complex problems easily digestible.
Just for the sake of trying the convolution formula i solved the partial fractions s/(4+s^2) + 2/(4+s^2) + 1/[s^2(4+s^4)]. Nice!
Watching this during my Calc 4 exam, thank you very much my dude
Lots of love for you sir.. 😍😍😍 From Bangladesh.. Your method was super easy to get the problem..
woaahh i never knew laplace is this easy..thank you sir, tutorial appreciated!
I want to comment that you can use residue method to get A/s. To do so, we will consider P(s) = (s^3 + 2s^2 + 1)/(s^2 + 4). Then, we can differentiate P(s) but we have to divide it by n! where n is the number of times differentiation can occur. (In this case, n= 1) because s is only repeated once. P'(s) = [(3s^2 + 2s)(s^2 + 4) - 2s(s^3 + 2s^2 + 1)]/(s^2 + 4)^2 From the previous cover-up: s = 0 so we have P'(0). Then, you can plug 0 into your function. After applying differentiation. You'll be surprised you'll get the same answer for A.
I don't sub often, I am about to graduate this year and you earned it!
Absolutely perfect job. Thanks!
Bro thanks so much for all youve taught me, in this case wouldn't it have been easier to solve using method of unconfirmed...
You're a good tutor! Im about to comment because i got confused in the A/s +B/s2 ... but you discussed it well ahhaha slow clap*
Great work! Technically shouldn’t all of this be multiplied times the unit step function, which would be the same as saying “for t >= 0?”
Dude You are the best !!!!!! I owe You 20 Marks!!!
@blackpenredpen
6 жыл бұрын
Thank you!!!!!!!
You've helped me a lot thanks
Me gustaría entenderte en el idioma pero observando tu procedimiento me a ayudado, gracias
Thanks a ton, now I feel very motivated
You can use cover-up to solve for C and D. Just make s=2i and substitute in. You get 2i+(-7)/(-4)=2i*C + D, therefore D = 7/4 and 2i=2i*C, thus C = 1. BAM!
Thank you so much dear Teacher 💖
Great job man, really good explanation. I think whats so hard to understand is how the denominator is split up into A, B etc. I've taken earlier courses that covered it, but not in the same extend that these exercises need.
@harleyspeedthrust4013
3 жыл бұрын
look up "partial fraction decomposition"
this guy saved my life
This vid helped me more then books
is there a playlist for this kind of problem's?
Sorry man but I had to.... Pause the video to comment and give you a thumbs up! So glad I subscribed, great work!! Thank you!!
Thank you so much!😭😭💕💕
Yes, I just said "isn't it?" just like Y O U ! ! !
@blackpenredpen
6 жыл бұрын
Yay!!!!!!!
Thank you
Love this!
this deserves more likes than those useless travel vlogs
I can't find your Laplace playlist.
Bedankt maat!
wow. thank you
thank you
If that s³+2s²+1 was s³+2s²+s, you would do: s³+2s²+s=s(s²+2s+1)=s(s+1)²
The best
your voice is asmr to my ears
very kind smile
Is that a microphone
Aha! You want to look the 4 as 2², isn't it?
Math is beautiful
Weird thing. My teacher use this equation in our assignment
@xxslysinxx
6 жыл бұрын
Did you write your answer in black pen and red pen?
Best way to solve DE is with Laplace Tf
@harleyspeedthrust4013
3 жыл бұрын
agreed, unless u dont have initial conditions then my favorite way is variation of parameters
Very good
@manyielkoth2221
4 жыл бұрын
As long as you are getting him
I distinguish my s and my 5 using cursive handwriting
may i know why so i have to add CS + D and your peevious dont need?
@carultch
7 ай бұрын
For linear terms, you only need a constant for the numerator. For irreducible quadratic terms, you need to set up a linear term for the numerator. If you had an irreducible cubic, you'd use a quadratic term for its numerator. It wouldn't help you very much for either integration or Laplace transforms, but that's what you'd do in concept. In general, the polynomial on the top, is one degree less than the polynomial on the bottom. Sometimes, the linear factor turns out to just be a constant, other times, the linear factor turns out to only be the term with the variable
that pen swish doh 15:10. Swag
5:00 20 seconds does not equal 50 seconds unless we are moving fast away from each other and relativistic effects take over.
What is the laplace of sint
@carultch
8 ай бұрын
1/(s^2 + 1) Cosine has the s up top, sine has the constant.
I found "A" to be 1/2 no zero
I love youuuuu
ليه حطيت T=1/s^2 ???
@tarekkhalifa8634
3 жыл бұрын
why ?
Pointing out the seemingly obvious, but you forgot to multiply by 2 inside the cosine inverse LaPlace and the 1/2 outside, so it should be 1/2* cos(2t)
@blackpenredpen
7 жыл бұрын
Steven Tucker u only have to do that for sine. Cos is ok
how we can get D=7/4 like how 2 become 8/4 - 1/4 = 7/4 just how that 2 become 8/4 sorry if my question is so complicated .
@carultch
7 ай бұрын
Given: (s^3 + 2*s^2 + 1)/(s^2*(s^2 + 4)) I like to set up the terms for Heaviside coverup first, which in this case is A: A/s^2 + B/s + (C*s + D)/(s^2 + 4) At s=0, cover up s^2, and find A: A = (0+0+1)/(0^2 + 4) = 1/4 Reconstruct: (s^3 + 2*s^2 + 1)/(s^2*(s^2 + 4)) = 1/4/s^2 + B/s + (C*s + D)/(s^2 + 4) Multiply by s, to partially clear the fraction: (s^3 + 2*s^2 + 1)/(s*(s^2 + 4)) = 1/4/s + B + (C*s^2 + D*s)/(s^2 + 4) Take the limit as s goes to infinity, to set up our first equation: 1 = 0 + B + C B = 1 - C Pick two values of s we haven't used yet, to create two more equations. I'll choose s=1 & s = -1 s=1: (1^3 + 2*1^2 + 1)/(1^2*(1^2 + 4)) = 1/4 + B + (C + D)/(1 + 4) 4/5 = 1/4 + B + (C + D)/5 20*B + 4*C + 4*D = 11 s = -1: ((-1)^3 + 2*(-1)^2 + 1)/((-1)^2*((-1)^2 + 4)) = 1/4/(-1)^2 + B/(-1) + (C*(-1) + D)/((-1)^2 + 4) 2/5 = 1/4 + -B + (-C + D)/5 8 = 5 + -20*B + 4*(-C + D) -20*B - 4*C + 4*D = 3 Add equations to cancel B & C terms and solve for D: 8*D = 14 D = 7/4 Use original equations to solve for B&C: 20*B + 4*C + 4*7/4 = 11 5*(1 - C) + C = 1 -4*C + 5 = 1 C = 1 B = 1-1 = 0 Result: 1/4/s^2 + (s + 7/4)/(s^2 + 4)
His using 2 markers one hand
This is so tough
not difficult, but very easy to make a mistake
I don't understand at 6:45
@hanaa.r_
7 ай бұрын
How when 1/4 we put in A
hm, so you don`t use the +1...
@5stepshred300
6 жыл бұрын
Good observation, did you forget to use the +1?
@blackwatch7572
4 жыл бұрын
hahahahaha temos um ancap por aqui.
Worst way to solve a linear ODE. How about a non-linear ODE example?
@blackpenredpen
5 жыл бұрын
Hi Rob!
@jammcrusader1981
4 жыл бұрын
lol dude - its about learning the method
@harleyspeedthrust4013
3 жыл бұрын
dude its just an example to get the hang of laplace transforms chill out dickwad
The way you do partial fractions doesn't make a bit of sense...
@blackpenredpen
5 жыл бұрын
Which part confused you?
@joshuamitchell359
5 жыл бұрын
@@blackpenredpen Actually, I totally confused myself while I was doing the problem along with you. I missed an "s." It made perfect sense! Sorry about the inconvenience!
@blackpenredpen
5 жыл бұрын
Joshua Mitchell I see. 😎
Literally the partial fractions is so unnecessary and it takes up over half the video, without taking the common denominator and keeping it as three seprate fractions we coud have taken the inverse laplace much easier with a VERY easy convolution to solve at the end
@harleyspeedthrust4013
3 жыл бұрын
yes but in general you want to avoid convolutions. the point of the laplace transform is to solve the problem without actually doing calculus, so if you can find partial fractions then you should do that instead
But… no.
His English is so bad
@harleyspeedthrust4013
3 жыл бұрын
better than yours
Thank you